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Calculus
Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
asked by George on September 9, 2008 
Calculus
Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
asked by George on September 9, 2008 
i lied. very quick calc problem.
f(x) = abs(sin(x)), pi less than or equal to x less than or equal to pi g(x) = x^2 let H(x) = g(f(x)) i got that H(x) would equal sin^2(x). THIS IS WHERE I AM STUCK! find the domain of H. do i still need to account for "pi less
asked by jane on February 20, 2009 
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Test for symmetry with repsect to Q=pi/2, the polar axis, and the pole. r=16cos 3Q r=16cos(3pi/3 + 3h) = 16(cos3pi/2 3h sin 3pi/2 sin h) cos 3pi/2 = 0 sin 3pi/2 = 1 Not symmetrical My teacher said that this was wrong!Why?
asked by Abbey(Please help) on May 5, 2010 
Math
Test for symmetry with repsect to Q=pi/2, the polar axis, and the pole. r=16cos 3Q r=16cos(3pi/3 + 3h) = 16(cos3pi/2 3h sin 3pi/2 sin h) cos 3pi/2 = 0 sin 3pi/2 = 1 Not symmetrical My teacher said that this was wrong!Why?
asked by Abbey on May 5, 2010

Math:)
Explain why sin^1[sin(3pi/4)] does not = 3pi/4 when y=sin(x) and y=sin^1(x) are inverses. Any help on this question is greatly appreciated. Thank you!
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Volume of the area bounded by y=sin(x), xaxis, x is greater than or equal to 0 but less than or equal to pi, revolved about x=3pi/2.
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Thank you STEVE!!!!! Suppose that Cos (theta) = 1/square root 2 if 0
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I need to find the exact solutions on the interval [0,2pi) for: 2sin^2(x/2)  3sin(x/2) + 1 = 0 I would start: (2sin(x/2)1)(sin(x/2)1) = 0 sin(x/2)=1/2 and sin(x/2)=1 what's next? Ok, what angle has a sin equal to say 1/2 sin
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