math/algebra
 👍 0
 👎 0
 👁 126
Respond to this Question
Similar Questions

algebra
I need to divide this but I am a little confused. I hope this makes sense I tried to make sure I have the parenthesis in all the right spots [(x^249y^2)/(6x^2+42y)] / (x^2  7xy) [(x^249y^2)/(6x^2+42y)]*[1/(x^2  7xy)]
asked by Jane on October 6, 2007 
Algebra
Would someone please check these answers? Simplify. 3/x5+1/14/x5 For this answer I got: x2/x9 Divide. x^249y^2/6x^2+42y/(x^27xy) For this answer I got: (x+7y)/6x(x^2+7y) Add. Express your answer in simplest for. x/6+3x/6
asked by Linda on July 12, 2007 
intro cal
the first 3 term of a geometric progression are k4, 2k4, 4k+4. what is the value of k? can someone help please! in any geometric progression any term divided by its previous term gives you the common ratio, so .... (2k4)/(k4)
asked by Emma on May 18, 2007 
Math...PLease Help Me...
Problem: 63x 25  *  5 4x8 *I have to multiply the expression and simplify it.Thanks for your help. The five goes into the twenty five, and you can factor out a three from the first term in the numerator, and a two from
asked by Margie on February 27, 2007 
Algebra
O.k. this is similar to the other one I posted. There is a technique in my book how to solve similar ones but the examples aren't so good, so I have no clue were to even start. 1(1/x)(12/x^2) divide top by bottom
asked by Sara on July 21, 2007 
intermidate algebra
Just not good at this, factor complete, or state that the polynomial is prime. 9y^4+42y^3+49y^2 (9+y)(9y)+42(y+3)(y3)^2+49(y+2(y2) I can not seem to get it right. so help me please
asked by Keaton on May 17, 2010 
Algebra
Which pattern could have been used to create the sequence? 20, –40, 80, –160, 320 Multiply the previous term by –2 Divide the previous term by 2 Subtract 60 from the previous term. Add –60 to the previous term.
asked by Reyrey on April 23, 2016 
algebra
64y^3125 9y^4+42y^3+49y^2 I need help I cannot get the right answer. factor complete, or state that the polynomial is prime.
asked by Angelia Jo on May 17, 2010 
Maths
The sixth term of GP is 16 and the third term is 2.Find the first term and common ratio. 6th term =16 3rd term=2 So ar^5=16 and ar^2=2, then divide. So r^3=8, and r^3 =2^3. Therefore r =2 and a=1/2
asked by Vin Mwale on December 3, 2015 
alg2 (sequences)
how do i find the pattern for: 4,8,12,16 if the last number is negative, multiply by 1 then add 4 if the last number is positive, add 4, then multiply by 1 or how about termn+1 = (abs(termn))*(1)^n, where term1 = 4, n>0 oops
asked by lily on May 3, 2007