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Math
Consider the initial value problem y'' +5y'+6y=0, y(0)=4.87 and y'(0)=Beta where Beta>0 Determine the coordinates t_m and y_m of the maximum point of the solution as functions of Beta.
asked by Yarielis on March 3, 2014 
Calculus  Second Order Differential Equations
Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2
asked by COFFEE on July 9, 2007 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,
asked by COFFEE on July 10, 2007 
Math
A series circuit contains a resistor with R = 24 , an inductor with L = 2 H, a capacitor with C = 0.005 F, and a generator producing a voltage of E(t) = 12 sin(10t). The initial charge is Q = 0.001 C and the initial current is 0.
asked by COFFEE on July 10, 2007 
physics please help
Find Beta and Gamma for an electron that has a kinetic energy of 6.00 keV. gamma = KE/MoC^2 + 1 Beta = 1/gamma^2 + 1 gamma = 1.011723381 Beta = 1.9769592 I am getting gamma right but I am getting Beta wrong what I'm I doing
asked by Andy on April 18, 2010

Trig.
I have answers for these problems, but I wanted to check if I had them right because I wasn't sure on some of them....Thanks. Solve the triangle: 1. a=4, b=8, alpha=30 deg. answer beta=90 deg., gamma=60 deg., c=7 2. a=5, b=7,
asked by ashley on December 12, 2006 
Calculus  Second Order Differential Equations
Posted by COFFEE on Monday, July 9, 2007 at 9:10pm. download mp3 free instrumental remix Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8))
asked by COFFEE on July 10, 2007 
Pre Calc Trig Bit
Determine whether the given information resutls in one triangle, two triangles, or no triangle at all. Solve any triangle(s) that results. b = 4 c = 6 beta = 20 Ok... I checked my answers in the back of the book and got the first
asked by Pre Calc Trig Bit on September 20, 2009 
calc check: curve length
Find the length of the curve y=(1/(x^2)) from ( 1, 1 ) to ( 2, 1/4 ) [set up the problem only, don't integrate/evaluate] this is what i did.. let me know asap if i did it right.. y = (1/(x^2)) dy/dx = (2/(x^3)) L = integral from
asked by COFFEE on July 2, 2007 
math
How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1cos(beta)) on the right, sin^2 = 1cos^2, that factor to 1cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec
asked by michelle on June 13, 2007