Please take a look at my work below and provide a good critique:

Solve the differential equation using the method of undetermined coefficients or variation of parameters.

y'' - 3y' + 2y = sin(x)

yc(x)= c1*e^2x+c2*e^x

r1=1, r2=2
A-3B=0 and B+3A=1
A=3B, B+3B=1
A=3/4, B=1/4

This did not come out correctly. I am trying to solve for yp(x). Where have I made an error and how can I fix it? Thanks.

from that line, to the next,
I think you should have

check my adding.

got it, thanks.

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asked by COFFEE

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