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maths
Hi, could someone please tell me how I would go about working these out: (the answer must be in the form a(sqroot)b where a and b are integers and b is as small as possible.) 1) Simplify (sqroot)500 2) Simplify (sqroot)50 x
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Simplify 3(x2)^2/x2 Is the answer 3x^210x+10? If not then what is? When p= sqrt2 and q= sqrt6 write pq in the form a(sqrt)b where a and b are integers and b is as small as possible. Multiply out these brackets. Give your answer
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ALGEBRA 1
change 50 to 25*2 sqrt 50 = 5 sqrt2 change 8 to 4*2 Nope: (sqrt3sqrt5)(sqrt3sqrt5). remember (ab)(ab)= a^22ab + b^2 Simplify.Express in simpliest radical form. 1.3sqrt2 +sqrt50 Cannot be solve. Terms have unlike radicals
asked by bobpursley on April 11, 2007 
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evaluate and simplify 6  square root20  2 The square root of 20= sqrt (4*5)= sqrt4 * sqrt5= 2 sqrt5 The square root of 20= sqrt (4*5)= sqrt4 * sqrt5= 2 sqrt5
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algebra,math,help
Use Property 2 to simplify each of the following radical expressions. sqrt (10)/ sqrt(49) My answer: sqrt (10) / (7) THis next one i need help: Use the properties for radicals to simplify each of the following expressions. Assume
asked by jas20 on March 9, 2007 
algebra
Can someone help me with this problem please? rationalize the denominator and simlify the answer: 5/2 + the square root of 3 Do you mean 5/(2 + sqrt 3) ? What you wrote could also be interpreted as 2.5 + sqrt 3. You need to be
asked by Maria on March 1, 2007 
Math  check my answers :)
1. Find the amplitude, if it exists, and the period of y=tan 1/4È Answer: No limits in amplitude, y=tanÈ/4 period is 4pi 2.Solve x = Arctan(sqrt3) Work: Pythagorean theorem: sqrt(1^2+3)= sqrt4=2 in length. Triangle is 1, sqrt
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Two more I would like to check my work on: Solve using the square root property: (x+6)^2 = 4 x+6 = sqrt4 x+6 = sqrt4 x+6 = 2 x+6 = 2 x+66 = 26 x+66 = 26 x = 4 x = 8 Solve by completing the square: x^2+6x+1=0 x^2+6x+11 =
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Algebra
Multiplying sq rts sqrt18a^7b times sqrt27a^8b^6 Jake 1214 18 = 9 * 2 then sqrt 18 = 3sqrt2 sqrt a^7 = a^3 * sqrt a 27 = 9 * 3 then sqrt 27 = 3 sqrt3 sqrt a^8 = a^4 sqrt b^6 = b^3 Now just multiply the liketerms together. 3sqrt6
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Algebra 2
Express log A in terms of the 2 logarithms of prime numbers: A= (sqrt(3)*sqrt4(125))/7^3
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