4Fe(s)+3 O2(g)------ 2Fe2 O3(s)
How many grams of Fe will be needed to react with sufficient amount of O2 to produce 1.OOkg of Fe2 O3 ?
How many moles is 1kg of IronIII oxide? Wouldn't you need twice that number of moles of Fe?
To find out how many grams of Fe are needed to react with sufficient O2 to produce 1.00 kg of Fe2O3, we need to use stoichiometry.
The balanced equation shows that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe2O3.
1 mole of Fe2O3 has a molar mass of (2 x 55.85) + (3 x 16.00) = 159.69 g/mol.
To convert 1.00 kg to grams, we multiply by 1000:
1.00 kg = 1000 g.
Now we can calculate the moles of Fe2O3:
1.00 kg x (1 mol/159.69 g) = 6.26 mol of Fe2O3.
According to the stoichiometry, the molar ratio between Fe and Fe2O3 is 4:2, which simplifies to 2:1. Therefore, we need twice the amount of moles of Fe as compared to Fe2O3.
2 x 6.26 mol = 12.52 mol of Fe.
To calculate the grams of Fe, we multiply by the molar mass of Fe:
12.52 mol x (55.85 g/mol) = 698.29 g of Fe.
Therefore, approximately 698.29 grams of Fe will be needed to react with enough O2 to produce 1.00 kg of Fe2O3.
To determine the grams of Fe needed to produce 1.00kg of Fe2O3, we will use the balanced equation provided:
4Fe(s) + 3O2(g) -> 2Fe2O3(s)
First, we need to find the molar mass of Fe2O3:
Fe2O3 = (2 x Atomic mass of Fe) + (3 x Atomic mass of O)
Fe2O3 = (2 x 55.845 g/mol) + (3 x 16.00 g/mol)
Fe2O3 = 159.69 g/mol
Now, we can calculate the number of moles of Fe2O3 in 1.00kg:
1.00kg = 1000g
Number of moles = Mass in grams / Molar mass
Number of moles = 1000g / 159.69 g/mol
Number of moles ≈ 6.26 mol
Since the stoichiometry ratio between Fe2O3 and Fe is 2:4, or when simplified 1:2, we need twice the number of moles of Fe compared to Fe2O3.
Therefore, the number of moles of Fe required would be:
2 x 6.26 mol = 12.52 mol
To find the mass of Fe required, we can use the molar mass of Fe (55.845 g/mol):
Mass of Fe = Number of moles x Molar mass
Mass of Fe = 12.52 mol x 55.845 g/mol
Mass of Fe ≈ 698.3g
Hence, approximately 698.3 grams of Fe would be needed to react with a sufficient amount of O2 to produce 1.00kg of Fe2O3.