benzene ring-N-H-CH3

H
\
N-benzene ring
/
CH3

select the class of compound from the choice below.
1-acetal
2-alcohol
3-alkene
4-amide
5-amine
6-carboxylic acid
7-ester
8-haloalkane

IS THAT AMINE

To determine the class of compound, you need to consider the functional groups present in the molecule. In the given structure, we have a benzene ring bonded to nitrogen (N), which is in turn bonded to a methyl group (CH3).

Looking at the options provided, we can eliminate some choices based on the given structure:

1. Acetal: This compound is characterized by a carbon bonded to four other groups including two ether groups (-OR). Since this structure does not contain such groups, we can eliminate this option.

2. Alcohol: Alcohols have a hydroxyl group (-OH) attached to a carbon atom. There is no hydroxyl group in the given structure, so this option can be eliminated.

3. Alkene: Alkenes have a carbon-carbon double bond. We do not have a double bond in the given structure, so this option can also be eliminated.

4. Amide: Amides consist of a carbonyl group (C=O) linked to a nitrogen atom. While there is a nitrogen atom in the given structure, there is no carbonyl group present, so we can eliminate this option.

5. Amine: Amines are characterized by nitrogen atoms bonded to carbon atoms or hydrogen atoms. In this case, we have a nitrogen atom bonded to a benzene ring and a methyl group, so amine is a possible class of compound.

6. Carboxylic acid: Carboxylic acids have a carboxyl functional group (-COOH). There is no carboxyl group present in this structure, so this option can be eliminated.

7. Ester: Esters contain the carbonyl group (-CO-) bonded to an oxygen atom which is in turn bonded to a carbon atom. Since we don't have these groups in the given structure, this option can be eliminated.

8. Haloalkane: Haloalkanes have a halogen atom (e.g., chlorine, bromine) attached to a carbon atom. There are no halogen atoms in the given structure, so this option can be eliminated.

Based on the analysis, the most suitable class of compound for the given structure is amine.

Yes, the compound you have described is an amine. Amines have a nitrogen (N) atom bonded to one or more carbon (C) atoms. In this case, there is a nitrogen atom attached to a benzene ring, followed by a carbon atom bonded to a methyl group (CH3).

Looks like a secondary amine to me.