find the 19th term to: 4,6,8,10
An arithmetic sequence with
a = 4, d = 2
term(19) = a+18d
= 4 + 18(2)
= 40
To find the 19th term of the sequence 4, 6, 8, 10, we can observe that this is an arithmetic sequence with a common difference of 2.
To find the 19th term, we can use the arithmetic sequence formula:
a_n = a_1 + (n-1)d
where:
a_n is the nth term
a_1 is the first term
n is the term number
d is the common difference
Given:
a_1 = 4 (the first term)
d = 2 (the common difference)
n = 19 (the term number we are looking for)
Using the formula, we can substitute the values:
a_19 = 4 + (19-1) * 2
Simplifying further:
a_19 = 4 + 18 * 2
a_19 = 4 + 36
a_19 = 40
Therefore, the 19th term in the sequence 4, 6, 8, 10 is 40.
To find the 19th term of the given sequence (4, 6, 8, 10), we can first observe that the sequence is an arithmetic sequence. An arithmetic sequence is a sequence where the difference between consecutive terms remains constant.
In this case, the difference between each term is 2. So, with the first term being 4 and the common difference being 2, we can use the formula for the nth term of an arithmetic sequence:
nth term = first term + (n - 1) * common difference
Substituting the given values into the formula:
19th term = 4 + (19 - 1) * 2
Now, let's do the calculations:
19th term = 4 + 18 * 2
19th term = 4 + 36
19th term = 40
Therefore, the 19th term of the sequence 4, 6, 8, 10 is 40.