Here are the answers to the Grammer Unit Test for ONLY 8th graders
1. are
2. dependent clause
3. My collection of stamps is extensive
4. are/has
5. they
6. Missouri and Illinois are states along the Missouri River
7. Staring down the mountain, Jack was excited for a day of skiing
8. the test was moved to Wednesday
9. While the neighbors were walking to the store, they dropped their money and the wind blew it away.
10. When looking out the window, they saw the first leaf fall.
11. the team lost the game because the players made mistakes
12. the team collected statistics on every shot made and attempted
13. the students organized the bake sale
14. (Sorry i can't help)
15. (Sorry i can't help)
Unfortunately, I cannot help with questions 14 and 15 as the answers were not provided.
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I apologize for the inconvenience, but I am unable to provide answers for questions 14 and 15.
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Which of the following phrases helps you remember the spaces on a bass clef? (1 point) Responses Every Good Boy Does Fine Every Good Boy Does Fine Good Boys Do Fine Always Good Boys Do Fine Always All Cows Eat Grass All Cows Eat Grass F,A,C,E F,A,C,E
The phrase that helps you remember the spaces on a bass clef is "All Cows Eat Grass" (option D).
Scott is making costumes for a dance recital. He has 12 yards of purple fabric. Each costume uses
yard of purple fabric. How many costumes can Scott make?
A.
3
B.
4
C.
9
D.
16
To determine the number of costumes Scott can make, we divide the total amount of purple fabric (12 yards) by the amount of fabric needed for each costume (1 yard).
12 yards ÷ 1 yard = 12 costumes
Therefore, Scott can make 12 costumes. None of the given options match this answer, so it seems like there might be a mistake.
Scott is making costumes for a dance recital. He has 12 yards of purple fabric. Each costume uses 3/4
yard of purple fabric. How many costumes can Scott make?
A.
3
B.
4
C.
9
D.
16
To determine the number of costumes Scott can make, we divide the total amount of purple fabric (12 yards) by the amount of fabric needed for each costume (3/4 yard).
12 yards ÷ (3/4 yards) = 16 costumes
Therefore, Scott can make 16 costumes. The correct answer is option D.
What is the quotient of 5/12 and 1 1/6
?
To find the quotient of 5/12 and 1 1/6, we first need to convert the mixed number to an improper fraction.
1 1/6 can be converted to an improper fraction as follows:
1 1/6 = (6/6) + (1/6) = 7/6
Now, we can divide the fractions:
(5/12) ÷ (7/6)
To divide fractions, we multiply the first fraction by the reciprocal of the second fraction.
(5/12) * (6/7) = (5 * 6) / (12 * 7) = 30/84
Lastly, we simplify the fraction:
30/84 = 5/14
Therefore, the quotient of 5/12 and 1 1/6 is 5/14.
Mrs. Patel has two plants. The first plant has a height of 0.6 meter. The height of the second plant is 0.25 meter shorter.
What is the height of Mrs. Patel’s second plant?
A.
0.3 meter
B.
0.35 meter
C.
0.4 meter
D.
0.85 meter
The height of Mrs. Patel's second plant is 0.6 meter - 0.25 meter = 0.35 meter.
Therefore, the height of Mrs. Patel's second plant is 0.35 meter. The correct answer is option B.
Sara has a gift card for Six Town's Bakery and bought the following items.
6 muffins for $0.45 each
2 boxes of cookies for $2.70 each
1 coffee cake for $3.72
Sara estimates she has $8.00 left on her gift card. What assumption did Sara use to make her estimate?
A.
The gift card started with $7.00.
B.
The gift card started with $12.00.
C.
The gift card started with $15.00.
D.
The gift card started with $20.00.
To determine the assumption Sara used to make her estimate, we need to calculate the total amount spent on the items she bought.
6 muffins at $0.45 each: 6 x 0.45 = $2.70
2 boxes of cookies at $2.70 each: 2 x 2.70 = $5.40
1 coffee cake for $3.72
The total amount spent on the items is $2.70 + $5.40 + $3.72 = $11.82.
Sara estimated that she has $8.00 left on her gift card. This indicates that she assumed the gift card started with an amount of money higher than $11.82.
Among the given options, the assumption that Sara used is closest to option C - The gift card started with $15.00.
Therefore, the assumption Sara used to make her estimate is option C - The gift card started with $15.00.
3
5
2
15
5
5
7
The table shows the items Stevie bought from a garage sale and their prices.
What is the mean price of the items Stevie bought?
A.
36
B.
5
C.
21
D.
6
To find the mean (average) price of the items Stevie bought, we need to add up the prices of all the items and divide by the total number of items.
The sum of the prices is 3 + 5 + 2 + 15 + 5 + 5 + 7 = 42.
Stevie bought a total of 7 items.
To find the mean, we divide the sum by the total number of items: 42 / 7 = 6.
Therefore, the mean price of the items Stevie bought is $6. The correct answer is option D.
A group of 15 students were assigned a novel to read during class. The data below represents the number of pages each student read.
8, 8, 10, 11, 12, 12, 13, 14, 16, 16, 18, 18, 18, 20, 24
Which of the following box plots correctly summarizes the data?
A.
The end of the first whisker is at 8, the box starts at 12, the line inside the box is at 16, the box ends at 18, and the end of the second whisker is at 24.
B.
The end of the first whisker is at 8, the box starts at 11, the line inside the box is at 14, the box ends at 18, and the end of the second whisker is at 24.
C.
The end of the first whisker is at 8, the box starts at 11, the line inside the box is at 16, the box ends at 18, and the end of the second whisker is at 24.
D.
The end of the first whisker is at 8, the box starts at 11, the line inside the box is at 14, the box ends at 20, and the end of the second whisker is at 24.
To summarize the data using a box plot, we need to identify the minimum, lower quartile (Q1), median (Q2), upper quartile (Q3), and maximum values.
First, let's sort the data in ascending order: 8, 8, 10, 11, 12, 12, 13, 14, 16, 16, 18, 18, 18, 20, 24.
Minimum: 8
Q1 (Lower quartile): The median of the lower half of the data. In this case, it's between 10 and 11, so Q1 ≈ 10.5.
Q2 (Median): The middle value of the data, which is 14.
Q3 (Upper quartile): The median of the upper half of the data. In this case, it's between 18 and 20, so Q3 ≈ 19.
Maximum: 24
Now, let's analyze the given options.
Option A: The end of the first whisker is at 8 (correct), the box starts at 12 (incorrect), the line inside the box is at 16 (incorrect), the box ends at 18 (incorrect), and the end of the second whisker is at 24 (correct).
Option B: The end of the first whisker is at 8 (correct), the box starts at 11 (incorrect), the line inside the box is at 14 (correct), the box ends at 18 (correct), and the end of the second whisker is at 24 (correct).
Option C: The end of the first whisker is at 8 (correct), the box starts at 11 (correct), the line inside the box is at 16 (incorrect), the box ends at 18 (correct), and the end of the second whisker is at 24 (correct).
Option D: The end of the first whisker is at 8 (correct), the box starts at 11 (correct), the line inside the box is at 14 (incorrect), the box ends at 20 (incorrect), and the end of the second whisker is at 24 (correct).
Based on our analysis, the box plot that correctly summarizes the data is option B. The end of the first whisker is at 8, the box starts at 11, the line inside the box is at 14, the box ends at 18, and the end of the second whisker is at 24.
Tia, Bill, Kay, and Marco counted the number of fireflies they saw each day for a week in the summer. They each put their numbers in order from least to greatest.
Tia: 9, 12, 15, 18, 21, 24, 27
Bill: 3, 6, 8, 18, 20, 21, 22
Kay: 14, 15, 16, 18, 24, 27, 32
Marco: 2, 6, 10, 14, 18, 22, 26
Whose data is skewed left?
A.
Tia's data
B.
Bill's data
C.
Kay's data
D.
Marco's data
To determine whose data is skewed left, we need to analyze the distribution of the data sets and identify any outliers or unusual patterns.
Looking at the data sets:
Tia: Increasing values with no outliers.
Bill: Increasing values with no outliers.
Kay: Increasing values with no outliers.
Marco: Increasing values with no outliers.
Based on the given data sets, we can see that none of them display a left skew. Left skew occurs when the tail of the distribution is on the left side, indicating that there are more lower values and fewer higher values. None of the data sets show this pattern.
Therefore, none of the options (A, B, C, or D) accurately represent data that is skewed left.