Calculate 6.25 × 106 - 4.73 × 10. Express your answer in scientific notation to 2 decimal places. (1 point)
The calculation would be 6.25 × 10^6 - 4.73 × 10^1.
To subtract these numbers, we need to ensure that the exponents (powers of 10) are the same. In the given calculation, the exponent in the second number is 1, while the exponent in the first number is 6. To make the exponents the same, we can rewrite the second number as 4.73 × 10^1 = 0.0473 × 10^2.
Now that the exponents are the same, we can subtract the numbers:
6.25 × 10^6 - 0.0473 × 10^6 = (6.25 - 0.0473) × 10^6 = 6.20 × 10^6.
Hence, the answer in scientific notation to two decimal places is 6.20 × 10^6.
Calculate 6.25 × 10^6 - 4.73 × 10^6. Express your answer in scientific notation to 2 decimal places. (1 point)
To subtract these numbers, the exponents (powers of 10) must be the same. In this case, they are both 6.
To find the result, subtract the coefficients:
6.25 - 4.73 = 1.52
Therefore, the result in scientific notation is 1.52 × 10^6 (to two decimal places).
The average distance from Earth to Mars is 2.25 × 10 km, and the distance from Earth to Neptune is 4.3514 × 10° km. How much farther is Neptune from Earth than Mars? Express your answer in scientific notation. Do not round your answer. (1 point)
To find the difference in distance between Neptune and Mars, we subtract the distance to Mars from the distance to Neptune.
4.3514 × 10° km - 2.25 × 10 km
To subtract these numbers, we need to make sure the exponents (powers of 10) are the same. In this case, the exponent for Neptune is ° and the exponent for Mars is 1. To make them the same, we can rewrite the distance to Mars as 2.25 × 10° km.
Now that the exponents are the same, we can subtract the distances:
4.3514 × 10° km - 2.25 × 10° km = (4.3514 - 2.25) × 10° km = 2.1014 × 10° km.
Hence, Neptune is 2.1014 × 10° km farther from Earth than Mars.
Human hair grows at a rate of about 6.849 × 10-4 cm per hour to 2.329 x 10-2 cm per hour. The rate depends on gender, genetics, age, and health. Find the difference between the high end and the low end of the range. Express your answer in scientific notation. Do not round your answer.
To find the difference between the high end and low end of the range, we subtract the low end value from the high end value.
High end value: 2.329 × 10^(-2) cm per hour
Low end value: 6.849 × 10^(-4) cm per hour
Difference = High end value - Low end value
Difference = 2.329 × 10^(-2) cm per hour - 6.849 × 10^(-4) cm per hour
To subtract these numbers, we need to make sure the exponents (powers of 10) are the same. In this case, both numbers have -2 as the exponent. Therefore, we can subtract the coefficients:
2.329 - 6.849 = -4.52
Therefore, the difference between the high end and low end of the range is -4.52 × 10^(-2) cm per hour.
Find 0.078 (5.2 x 10 3). Express your answer in scientific notation. Do not round your answer.
To find the product of 0.078 and 5.2 x 10^3, we multiply the two numbers:
0.078 x (5.2 x 10^3)
To simplify this product, we can multiply the two coefficients (numbers) and add the exponents:
0.078 x 5.2 = 0.4056
10^3 x 10^0 = 10^(3+0) = 10^3
Therefore, the product of 0.078 and 5.2 x 10^3 is 0.4056 x 10^3 in scientific notation.
Find 0.078
(5.2 x 10-3). Express your answer in scientific notation. Do not round your answer. (1 point)
_ ×10-2
To find the product of 0.078 and 5.2 x 10^-3, we multiply the two numbers:
0.078 x (5.2 x 10^-3)
To simplify this product, we can multiply the two coefficients (numbers) and add the exponents:
0.078 x 5.2 = 0.4056
10^-3 x 10^-2 = 10^(-3-2) = 10^-5
Therefore, the product of 0.078 and 5.2 x 10^-3 is 0.4056 x 10^-5 in scientific notation.
Earth's radius is approximately 3,959 miles, while Jupiter's radius is approximately 4.3441 × 10* miles. How much bigger is Jupiter's radius compared to Earth's? Express your answer in scientific notation. Do not round your answer.
(1 point)
To find out how much bigger Jupiter's radius is compared to Earth's, we need to subtract Earth's radius from Jupiter's radius.
Jupiter's radius: 4.3441 × 10^* miles
Earth's radius: 3,959 miles
To subtract these numbers, we need to ensure that the units (exponents of 10) are the same. Since Jupiter's radius is already expressed in scientific notation, we can rewrite Earth's radius as 3,959 × 10^0 miles.
Now that the units are the same, we can subtract the radii:
4.3441 × 10^* miles - 3,959 × 10^0 miles = (4.3441 - 3,959) × 10^* miles.
Therefore, Jupiter's radius is (4.3441 - 3,959) × 10^* miles bigger than Earth's radius. Note that the exponent in this case is not explicitly given, so the final answer will also have this unknown exponent.
Subtract 4.66 × 10-5
4.5866 × 10-5
- 4.5866 × 10-5
- 2.68 × 102
2.68 × 10?
7.34 × 10-7
Let's subtract the given numbers:
(4.66 × 10^-5) - (4.5866 × 10^-5) - (4.5866 × 10^-5) - (2.68 × 10^2) + (2.68 × 10?)
When subtracting numbers in scientific notation, the exponents must be the same.
(4.66 × 10^-5) - (4.5866 × 10^-5) - (4.5866 × 10^-5) can be calculated as:
4.66 - 4.5866 - 4.5866 = -4.5066
Next, we add (2.68 × 10?) to the result:
-4.5066 + (2.68 × 10?)
Since the exponent is not specified for (2.68 × 10?), we cannot directly add it to the previous result.
Lastly, we subtract (2.68 × 10^2) from the result:
-4.5066 - (2.68 × 10^2)
We cannot directly subtract the numbers since they are in different forms.
Overall, with the information given, it is not possible to determine the exact result in scientific notation.
what’s the answer
Apologies for the confusion earlier. Let's reconsider the subtraction:
(4.66 × 10^-5) - (4.5866 × 10^-5) - (4.5866 × 10^-5) - (2.68 × 10^2) + (2.68 × 10?)
(4.66 - 4.5866 - 4.5866) × 10^-5 - (2.68 × 10^2) + (2.68 × 10?)
= -4.5066 × 10^-5 - (2.68 × 10^2) + (2.68 × 10^?)
Without information about the exponent for (2.68 × 10?), we can simplify the subtraction part:
-4.5066 × 10^-5 - (2.68 × 10^2)
To subtract these numbers, we subtract the coefficient part and keep the exponent the same:
-4.5066 - 2.68 = -7.1866
Thus, the result is approximately -7.1866 × 10^2.
The weight of an ant averages about 3 × 10-6 kg. There are about 1 x 1016 ants in the world. What is the approximate weight in kilograms of ai the ants in the world? Write the answer in scientific notation.
To find the weight of all the ants in the world, we need to multiply the weight of a single ant by the total number of ants:
Weight of a single ant: 3 × 10^-6 kg
Total number of ants: 1 x 10^16 ants
To calculate the weight of all the ants, we multiply the two numbers:
(3 × 10^-6 kg) * (1 x 10^16 ants)
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
3 * 1 = 3
10^-6 * 10^16 = 10^(-6+16) = 10^10
Therefore, the approximate weight of all the ants in the world is 3 x 10^10 kg in scientific notation.
The average human heart beats about 3.5 × 107 times per year. The current population of Massachusetts is about 7 x 10° people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find the approximate number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per year by the population of Massachusetts:
Average number of heartbeats per year: 3.5 × 10^7
Population of Massachusetts: 7 x 10^0
To calculate the number of heartbeats in Massachusetts per year, we multiply the two numbers:
(3.5 × 10^7) * (7 x 10^0)
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
3.5 * 7 = 24.5
10^7 * 10^0 = 10^(7+0) = 10^7
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5 x 10^7 in scientific notation.
The sun generates about 4 × 1026 joules of energy every second. There are about 3.15 × 107 seconds in a year.
About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find the number of joules of energy the sun generates in a year, we multiply the energy generated per second by the number of seconds in a year:
Energy generated per second: 4 × 10^26 joules
Number of seconds in a year: 3.15 × 10^7 seconds
To calculate the total energy generated in a year, we multiply the two numbers:
(4 × 10^26 joules) * (3.15 × 10^7 seconds)
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
4 * 3.15 = 12.6
10^26 * 10^7 = 10^(26+7) = 10^33
Therefore, the number of joules of energy the sun generates in a year is approximately 12.6 x 10^33 joules in scientific notation.
The average newborn weighs 7.5 pounds. About 4.1 × 10 babies are born in the United States every year. Wh the approximate total weight in pounds of all the babies born in the U.S. in a year? Write the answer in scientific notation, expressed to the exact decimal place.
To find the approximate total weight of all the babies born in the United States in a year, we need to multiply the average weight of a newborn by the number of babies born:
Average weight of a newborn: 7.5 pounds
Number of babies born: 4.1 × 10 babies
To calculate the total weight, we multiply the two numbers:
(7.5 pounds) * (4.1 × 10 babies)
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
7.5 * 4.1 = 30.75
10^0 * 10^10 = 10^(0+10) = 10^10
Therefore, the approximate total weight of all the babies born in the United States in a year is 30.75 x 10^10 pounds in scientific notation.
In a given year, about 1.52 × 101 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place.
To find the total cost to deliver all the pieces of first-class mail in the U.S., we need to multiply the number of pieces of mail by the cost per stamp:
Number of pieces of mail: 1.52 × 10^1
Cost per stamp: $0.55
To calculate the total cost, we multiply the two numbers:
(1.52 × 10^1) * ($0.55)
To multiply numbers in scientific notation, we multiply the coefficients and keep the exponent the same:
1.52 * 0.55 = 0.836
Therefore, the total cost to deliver all the pieces of first-class mail in the U.S. is $0.836, or approximately $0.84.
What is 5.5 × 104 multiplied by 2.2 × 10-& Write the answer in scientific notation.
To multiply 5.5 × 10^4 by 2.2 × 10^-6, we multiply the coefficients and add the exponents:
(5.5 × 2.2) × 10^(4 + (-6))
= 12.1 × 10^-2
In scientific notation, we express the coefficient as a decimal between 1 and 10 and adjust the exponent accordingly.
12.1 can be written as 1.21 × 10^1, so the final answer is:
1.21 × 10^1 × 10^-2
Simplifying, we can add the exponents:
= 1.21 × 10^(1 + (-2))
= 1.21 × 10^(-1)
Therefore, 5.5 × 10^4 multiplied by 2.2 × 10^-6 is equal to 1.21 × 10^(-1) in scientific notation.
When multiplying two numbers in scientific notation, what operations do you use on the coefficients and the
exponents of the powers of 10? (1 point)
• Add the coefficients and multiply the exponents of the powers of 10.
• Multiply the coefficients and add the exponents of the powers of 10.
• Multiply the coefficients and multiply the exponents of the powers of 10.
• Add the coefficients and add the exponents of the powers of 10.
When multiplying two numbers in scientific notation, you multiply the coefficients and add the exponents of the powers of 10.
A tape dispenser holds 1.14 × 10* mm of tape that is 12.7 mm wide. Multiply the two numbers to find the total area in square millimeters of tape. Write the product in scientific notation. (1 point)
O 1.4478 × 104 mm?
O 14.478 × 10° mm?
O 14.478 × 104 mm?
O 1.4478 × 105 mm?
To find the total area in square millimeters of the tape, we multiply the length of the tape by the width of the tape:
Length of the tape: 1.14 × 10^* mm
Width of the tape: 12.7 mm
To calculate the total area, we multiply the two numbers:
(1.14 × 10^* mm) * (12.7 mm)
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
1.14 * 12.7 = 14.478
10^* * 10^0 = 10^(*+0) = 10^*
Therefore, the total area in square millimeters of the tape is 14.478 × 10^* mm^2 in scientific notation.
A sugar cube has a volume of about 4.9 ml. What is the total volume in milliliters of 1.5 × 10€ sugar cubes? /
O 7.35 × 106 ml
O 7.35 × 105 ml
O 0.735 × 107 ml
O 7.35 × 107 ml
To find the total volume of 1.5 × 10€ sugar cubes, we need to multiply the volume of one sugar cube by the number of sugar cubes:
Volume of one sugar cube: 4.9 ml
Number of sugar cubes: 1.5 × 10€
To calculate the total volume, we multiply the two numbers:
(4.9 ml) * (1.5 × 10€)