The cost, C, to bowl at Bowl-O-Rama is $5 per game, g, plus $4 for shoe rental. The cost, C, to bowl at Bowling Pinz is $4 per game, g, plus $8 for shoe rental. Write the pair of linear equations that model this situation.(1 point) Equation to represent the cost at Bowl-O-Rama: C= Equation to represent the cost at Bowling Pinz: C=
Equation to represent the cost at Bowl-O-Rama: C = 5g + 4
Equation to represent the cost at Bowling Pinz: C = 4g + 8
Equation to represent the total number of students: g + a = 100
Equation to represent the total cost of the gift cards: 40g + 25a = 4000
At the Henderson Middle School awards ceremony, the principal is going to honor outstanding students with gift cards. The gift cards for excellent grades, g, are worth $40, and the gift cards for perfect attendance, a, are worth $25. The principal has $4,000 allotted for this event, and he is going to recognize 100 students. Write the pair of linear equations that model this situation.(1 point) Equation to represent the total number of students: = 100 Equation to represent the total cost of the gift cards: = 4,000
40g + 25a
Apologies for the incorrect equation. The correct equation to represent the total cost of the gift cards is:
40g + 25a = 4000
he Highland Booster Club sells refreshments at the concession stand for local football games. Combination 1 includes 4 hot dogs and 2 sodas for $10. Combination 2 includes 6 hot dogs and 3 sodas for $15. Let h represent the cost of a hot dog, and let s represent the cost of a soda. Write the pair of linear equations that model this situation.(1 point) Equation for Combination 1: = 10 Equation for Combination 2: = 15
Equation for Combination 1: 4h + 2s = 10
Equation for Combination 2: 6h + 3s = 15
Mrs. Gonzalez is going to rent a car for a business trip for one week. The total cost, C, for Top-Notch Car Rental is $150 plus $0.35 per mile, m. The total cost, C, for Fleetwood Car Rental is $200 and $0.10 per mile, m. Which company is less expensive for a 300-mile trip and by how much? Use 1 for Top-Notch Car Rental and 2 for Fleetwood Car Rental in the answer.(1 point) The less expensive company is by $.
To determine which company is less expensive for a 300-mile trip, we can calculate the total cost for each company and compare them.
For Top-Notch Car Rental:
C1 = 150 + 0.35 * 300 = 150 + 105 = $255
For Fleetwood Car Rental:
C2 = 200 + 0.10 * 300 = 200 + 30 = $230
Therefore, Fleetwood Car Rental (Company 2) is less expensive for a 300-mile trip by $25.
The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C , $500 for the ballroom rental fee and $75 per student, s , for the meal. The Greenhill Country Club charges, C , $1,000 for the ballroom rental fee and $65 per student, s , for the meal. Create a pair of linear equations that represent this real-world problem.(1 point) Responses Regal Hotel: C=75s+1,000; Greenhill Country Club: C=65s+500 Regal Hotel: upper C equals 75 s plus 1,000 ; Greenhill Country Club: upper C equals 65 s plus 500 Regal Hotel: C=500s+75; Greenhill Country Club: C=1,000s+65 Regal Hotel: upper C equals 500 s plus 75 ; Greenhill Country Club: upper C equals 1,000 s plus 65 Regal Hotel: C=75s+500; Greenhill Country Club: C=65s+1,000 Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000 Regal Hotel: C=1,000s+75; Greenhill Country Club: C=500s+65
Regal Hotel: C = 75s + 500
Greenhill Country Club: C = 65s + 1,000
The Jackson Jammers are giving away bags and caps at their next game. The bags, b, cost them $10 each, and the caps, c, cost them $5 each. They plan to give away 2,000 total items and have a budget of $12,500. Write the pair of linear equations that model this situation.(1 point) Responses b+c=2,000; 10b+5c=12,500 b plus c equals 2,000 ; 10 b plus 5 c equals 12,500 b+c=12,500; 10b+5c=2,000 b plus c equals 12,500 ; 10 b plus 5 c equals 2,000 b+c=2,000; 5b+10c=12,500 b plus c equals 2,000 ; 10 b plus 10 c equals 12,500 b+c=12,500; 5b+10c=2,000
b + c = 2000
10b + 5c = 12500
Solve this real-world problem using a system of equations. The O’Donnells are having a birthday party for their son, and they plan to have a clown bring balloons to the party. Balloon Express charges $2 per balloon and $10 for delivery. Balloon Mania charges $1.50 per balloon and $20 for delivery. If the O’Donnells plan to order 30 balloons, which company should they choose, and how much will they save?(1 point) Responses Balloon Mania; $25 Balloon Mania; $25 Balloon Express; $5 Balloon Express; $5 Balloon Mania; $5 Balloon Mania; $5 Balloon Express; $25
To determine which company the O'Donnells should choose and how much they will save, we need to calculate the total cost for each company.
For Balloon Express:
Cost = (2 * 30) + 10 = 60 + 10 = $70
For Balloon Mania:
Cost = (1.50 * 30) + 20 = 45 + 20 = $65
Therefore, the O'Donnells should choose Balloon Mania and they will save $5 compared to Balloon Express.
The Spanish Club at Santa Fe Middle School wants to sell mini quiches to raise money for a field trip. The culinary department at their school will make the quiches for $30 plus $0.50 per quiche for the ingredients. The Spanish Club wants to sell each quiche for $2. How many quiches will they need to sell in order to break even?(1 point) Responses 20 quiches 20 quiches 75 quiches 75 quiches 12 quiches 12 quiches 45 quiches
To determine how many quiches the Spanish Club will need to sell in order to break even, we need to set up an equation to represent the cost and the revenue.
Let x be the number of quiches they need to sell.
Cost = $30 + $0.50x
Revenue = $2x
To break even, the cost must equal the revenue:
$30 + $0.50x = $2x
Subtracting $0.50x from both sides:
$30 = $1.50x
Dividing both sides by $1.50:
x = 20
Therefore, the Spanish Club will need to sell 20 quiches in order to break even.
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point) Responses 200 hot dogs and 100 pretzels 200 hot dogs and 100 pretzels 250 hot dogs and 50 pretzels 250 hot dogs and 50 pretzels 100 hot dogs and 200 pretzels 100 hot dogs and 200 pretzels 50 hot dogs and 250 pretzels 50 hot dogs and 250 pretzels
Let's assume they sell x hot dogs and y pretzels.
Based on the given information, we can set up the following system of equations:
4x + 2y = 800 (equation representing the income goal)
x + y = 300 (equation representing the total number of hot dogs and pretzels)
Now, we can solve this system of equations to find the values of x and y.
From the second equation, we can isolate x as x = 300 - y.
Substituting x = 300 - y into the first equation:
4(300 - y) + 2y = 800
Expanding and simplifying:
1200 - 4y + 2y = 800
-2y = -400
y = 200
Substituting y = 200 back into the second equation:
x + 200 = 300
x = 100
Therefore, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800.