During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?
To find the net force of the system, we need to add the forces together. Since the force to the right is assigned a negative value, we can consider it as a force of -50 N. Thus, the net force is given by:
Net force = 70 N + (-50 N) = 70 N - 50 N
Simplifying, we get:
Net force = 20 N
Therefore, the net force of this system is 20 N.
A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?
To find the momentum of the hockey puck, we use the formula:
Momentum (p) = mass (m) * velocity (v).
Given that the mass of the hockey puck is 0.12 kg and the velocity is 150 m/s, we can substitute these values into the formula:
p = 0.12 kg * 150 m/s
Calculating, we get:
p = 18 kg·m/s.
Therefore, the momentum of the hockey puck is 18 kg·m/s.
Students are going to conduct an experiment to study the effect of a net force applied to an object on the object’s motion. In each trial of the experiment,%C2%A0the students will apply a net force on the object. They also need to take two other measurements. What are the other quantities they should measure in each trial of the experiment?
In addition to measuring the net force applied to the object, the students should also measure the following two quantities in each trial of the experiment:
1. Acceleration: The students should measure the acceleration of the object. Acceleration is the rate at which an object's velocity changes with time when a net force is applied to it. By measuring the acceleration, the students can determine how the object's motion changes in response to the applied force.
2. Mass: The students should measure the mass of the object. Mass is a fundamental property of an object that determines its inertia and resistance to changes in motion. By measuring the mass, the students can take into account the object's mass when analyzing the effect of the net force on its motion.
By measuring the net force, acceleration, and mass, the students can gather comprehensive data to analyze the relationship between net force and an object's motion according to Newton's second law of motion (F = ma).
Velocity and Acceleration Quick Check 2 of 52 of 5 Items Question Use the data table to answer the question.%C2%A0It shows the acceleration of a body when a net force is applied to it. Net force (N) Mass (kg) Acceleration (m/s2) 5.0 5.0 1.0 10.0 5.0 2.0 20.0 5.0 %C2%A0 Which value would complete the last cell?
To determine the value that would complete the last cell, let's analyze the data provided in the table. The table shows the relationship between the net force applied to a body, its mass, and its resulting acceleration.
In the first row, when a net force of 5.0 N is applied to a body with a mass of 5.0 kg, the body's acceleration is 1.0 m/s^2. In the second row, when a net force of 10.0 N is applied to the same 5.0 kg body, the acceleration increases to 2.0 m/s^2.
Based on this pattern, we can see that doubling the net force (from 5.0 N to 10.0 N) leads to a doubling of the acceleration (from 1.0 m/s^2 to 2.0 m/s^2). Therefore, if we double the net force again from 10.0 N to 20.0 N, we can assume that the acceleration will also double from 2.0 m/s^2.
Hence, the value that would complete the last cell is 4.0 m/s^2.
Which statement makes an accurate comparison of the motions for objects C and D?
Unfortunately, the data for objects C and D is missing from the information provided. Without information about their motions, we cannot accurately compare the motions of objects C and D.
Use this graph of velocity vs. time for two objects to answer the question.%0D%0A%0D%0A%0D%0A%0D%0AWhich statement makes an accurate comparison of the motions for objects C and D?
Apologies, but I'm unable to assist.
Use the equation for motion to answer the question. x=x0+v0t+12at2 An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
To find the final position of the object after 1 second, we can use the equation for motion:
x = x0 + v0*t + (1/2)*a*t^2
Given:
Initial position (x0) = 2 m
Initial velocity (v0) = 15 m/s
Time (t) = 1 s
Plugging these values into the equation, we get:
x = 2 m + 15 m/s * 1 s + (1/2) * a * (1 s)^2
Since the object is moving at a constant speed, there is no acceleration (a = 0). Therefore, the equation becomes:
x = 2 m + 15 m/s * 1 s + 0
Simplifying the equation, we get:
x = 2 m + 15 m + 0
Thus, the final position (x) of the object after 1 second is:
x = 17 m
Therefore, the final position of the object after 1 second is 17 meters.
The graph of an object's position over time is a horizontal line and%C2%A0y is not equal to 0. What must be true about the object's motion?
If the graph of an object's position over time is a horizontal line and y is not equal to 0, this means that the object's position is constant over time.
In other words, the object is not moving or changing its position. Its position remains the same throughout the entire time period represented by the graph.
A line of dominos is knocked down. Which explanation is true
The explanation that is true for a line of dominoes being knocked down is that when the first domino in the line is toppled, it transfers its potential energy to kinetic energy, which causes it to fall onto the next domino. This transfer of energy continues down the line, with each domino falling due to the energy transferred from the previous one. The process continues until all the dominos in the line have fallen, demonstrating the concept of kinetic energy transfer and the chain reaction effect.
A line of dominos is knocked down. Which explanation is true?%C2%A0(1 point) Responses An increase in force caused a decrease in acceleration.%C2%A0 An increase in force caused a decrease in acceleration.%C2%A0 An increase in force caused an increase in acceleration.%C2%A0 An increase in force caused an increase in acceleration.%C2%A0 An increase in acceleration caused a decrease in force. An increase in acceleration caused a decrease in force. An increase in acceleration caused an increase in force.
An increase in force caused an increase in acceleration.
When raindrops form, the force of gravity pulls them toward the ground. Which statement is correct about this chain of events?
The correct statement about this chain of events is that the force of gravity causes raindrops to fall towards the ground.
A student observes that for the same net force, heavier objects accelerate less. Which statement describes a correct conclusion?
The correct conclusion is that mass and acceleration are inversely proportional when the net force is constant. Heavier objects accelerate less because they have greater inertia, which resists changes in motion. Therefore, it takes more force to accelerate a heavier object compared to a lighter object.
Correlation and Causation Quick Check 3 of 53 of 5 Items Question A student observes that for the same net force, heavier objects accelerate less. Which statement describes a correct conclusion?(1 point) Responses An decrease in acceleration causes the mass to increase.%C2%A0 An decrease in acceleration causes the mass to increase.%C2%A0 An increase in acceleration causes the mass to increase.%C2%A0 An increase in acceleration causes the mass to increase.%C2%A0 There is a negative correlation between mass and acceleration.%C2%A0 There is a negative correlation between mass and acceleration.%C2%A0 There is a positive correlation between mass and acceleration.
The correct conclusion is that there is a negative correlation between mass and acceleration. When the net force is the same, heavier objects accelerate less, indicating a negative relationship between mass and acceleration.
Correlation and Causation Quick Check 4 of 54 of 5 Items Question A nonzero net force acts on a moving ball, and the ball comes to a stop. Which statement is correct about the relationship between the net force and the ball's movement?(1 point) Responses An increase in acceleration causes the net force to be nonzero because causation works in both directions. An increase in acceleration causes the net force to be nonzero because causation works in both directions. The net force causes an increase in acceleration because without the force the ball's velocity would remain the same. The net force causes an increase in acceleration because without the force the ball's velocity would remain the same. A decrease in acceleration causes the net force to be nonzero because causation works in both directions. A decrease in acceleration causes the net force to be nonzero because causation works in both directions. The net force causes a decrease in acceleration because without the force the ball's velocity would remain the same.
The net force causes a decrease in acceleration because without the force, the ball's velocity would remain the same.
Correlation and Causation Quick Check%0D%0A5 of 55 of 5 Items%0D%0A%0D%0AQuestion%0D%0AA student places five books next to each other on their ends. She then pushes the first book with her finger, and a few seconds later, the last book falls. Which statement is correct about this chain of events?(1 point)%0D%0AResponses%0D%0A%0D%0AThere is a positive correlation between the force of the finger and number of books.%0D%0AThere is a positive correlation between the force of the finger and number of books.%0D%0A%0D%0AThere is causation between the force of the finger and the number of books.%0D%0AThere is causation between the force of the finger and the number of books.%0D%0A%0D%0AThe acceleration of the books as they fall causes the force of the finger.%0D%0AThe acceleration of the books as they fall causes the force of the finger.%0D%0A%0D%0AThe force of the finger causes the books to accelerate and fall.%0D%0AThe force of the finger causes the books to accelerate and fall.
The force of the finger causes the books to accelerate and fall.
Net Force and Acceleration Quick Check 1 of 51 of 5 Items Question If multiple forces are acting on an object, which statement is always true?(1 point) Responses The acceleration will be directed in the direction of the gravitational force. The acceleration will be directed in the direction of the gravitational force. The acceleration will be directed in the direction of the net force. The acceleration will be directed in the direction of the net force. The acceleration will be directed in the direction of the normal force. The acceleration will be directed in the direction of the normal force. The acceleration will be directed in the direction of the applied force. The acceleration will be directed in the direction of the applied force. Skip to navigation page 11 of 11
The acceleration will be directed in the direction of the net force.
Net Force and Acceleration Quick Check 2 of 52 of 5 Items Question If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball?(1 point) Responses The net force on the ball is zero. The net force on the ball is zero. The net force on the ball is directed upward. The net force on the ball is directed upward. The gravitational force is greater than the drag. The gravitational force is greater than the drag. The drag is greater than the gravitational force.
The net force on the ball is directed upward.
A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?
To find the magnitude of the net force acting on the boy, we need to subtract the force of drag and friction from the total force applied.
Given:
Force exerted by the boy = 300 N
Force exerted by the friend = 75 N
Force of drag and friction = 5 N
To find the net force, we subtract the force of drag and friction from the total applied force:
Net force = (Force exerted by the boy + Force exerted by the friend) - Force of drag and friction
Net force = (300 N + 75 N) - 5 N
Net force = 375 N - 5 N
Net force = 370 N
Therefore, the magnitude of the net force acting on the boy is 370 N.
Four friends push on the same block in different directions. Allie pushes on the block to the north with a force of 18 N. Bill pushes on the block to the east with a force of 14 N. Chris pushes on the block to south with a force of 23 N. Debra pushes on the block to the west with a force of 20 N. Assuming it does not move vertically, in which%C2%A0directions will the block move?
To determine the direction in which the block will move, we need to analyze the net force acting on the block in each direction.
Given:
Allie pushes north with a force of 18 N.
Bill pushes east with a force of 14 N.
Chris pushes south with a force of 23 N.
Debra pushes west with a force of 20 N.
We can break down the forces in the horizontal (east-west) and vertical (north-south) directions:
Horizontal forces:
Total force in the east direction = 14 N (Bill)
Total force in the west direction = 20 N (Debra)
Since the force in the west direction is greater than the force in the east direction, the block will move in the west direction.
Vertical forces:
Total force in the north direction = 18 N (Allie)
Total force in the south direction = 23 N (Chris)
Since the force in the south direction is greater than the force in the north direction, the block will move in the south direction.
To summarize, the block will move in the west and south directions.
Net Force and Acceleration Quick Check 5 of 55 of 5 Items Question %C2%A0Two teams are playing tug of war. The tables show the members of each team and how much pulling force each team member applies to the rope. Team A Members Pulling Force (N) Darlene 360 Eric 400 Keshawn 450 Team B Members Pulling Force (N) Anita 350 Frank 390 Molly 490 If Team A pulls to the right and Team B pulls to the left, what is the total horizontal net force applied to the rope?
To find the total horizontal net force applied to the rope, we need to sum up the individual forces exerted by each member of the teams in opposite directions.
Given:
Team A:
Darlene's pulling force = 360 N (to the right)
Eric's pulling force = 400 N (to the right)
Keshawn's pulling force = 450 N (to the right)
Team B:
Anita's pulling force = 350 N (to the left)
Frank's pulling force = 390 N (to the left)
Molly's pulling force = 490 N (to the left)
Total horizontal net force = (Sum of forces to the right) - (Sum of forces to the left)
Total horizontal net force = (360 N + 400 N + 450 N) - (350 N + 390 N + 490 N)
Total horizontal net force = (1210 N) - (1230 N)
Total horizontal net force = -20 N
Therefore, the total horizontal net force applied to the rope is -20 N.
If Team A pulls to the right and Team B pulls to the left, what is the total horizontal net force applied to the rope?
To find the total horizontal net force applied to the rope, we need to consider the forces in opposite directions exerted by Team A and Team B.
Given:
Team A:
Darlene's pulling force = 360 N (to the right)
Eric's pulling force = 400 N (to the right)
Keshawn's pulling force = 450 N (to the right)
Team B:
Anita's pulling force = 350 N (to the left)
Frank's pulling force = 390 N (to the left)
Molly's pulling force = 490 N (to the left)
To calculate the net force, we subtract the sum of the forces pulling to the left from the sum of the forces pulling to the right:
Total horizontal net force = (360 N + 400 N + 450 N) - (350 N + 390 N + 490 N)
Total horizontal net force = 1210 N - 1230 N
Total horizontal net force = -20 N
Therefore, the total horizontal net force applied to the rope is -20 N.