What does the Law of Conservation of Mass state?(1 point)
The Law of Conservation of Mass states that mass cannot be created or destroyed in a chemical reaction, but can only be rearranged.
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artasticdrawing
09/08/2022
Chemistry
High School
answered • expert verified
Pls Help ASAP! 2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
O 10 grams
O 7 grams
O 2 grams
O 5 grams
According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.
In this case, 2 grams of potassium (K) reacts with 5 grams of oxygen (O).
To find the mass of potassium oxide (K2O) produced, we can look at the balanced chemical equation:
2K + O2 -> 2K2O
From the balanced equation, we can see that 2 moles of K react with 1 mole of O2 to produce 2 moles of K2O.
The molar mass of K2O is 94 grams. Therefore, 2 moles of K2O is equal to 188 grams.
Since the balanced equation shows that 2 moles of K react to produce 2 moles of K2O, we can conclude that the mass of K2O produced will be equal to the mass of K used.
Therefore, the answer is 2 grams.
2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced? (1 point) Responses 5 grams
Apologies for the mistake in my previous response. Let's re-calculate it correctly.
According to the balanced chemical equation:
4K + O2 → 2K2O
We can see that 4 moles of K react with 1 mole of O2 to produce 2 moles of K2O.
To find the number of moles of K and O2, we can use the formula:
moles = mass / molar mass
For K:
moles of K = 2 g / 39.1 g/mol (molar mass of K) = 0.051 mol
For O2:
moles of O2 = 5 g / 32 g/mol (molar mass of O2) = 0.156 mol
From the balanced equation, we can see that the ratio of K2O to K is 2:4, which simplifies to 1:2. Therefore, the moles of K2O produced will be half of the moles of K.
moles of K2O = 0.051 mol / 2 = 0.0255 mol
To find the mass of K2O:
mass = moles × molar mass
mass of K2O = 0.0255 mol × 94.2 g/mol (molar mass of K2O) = 2.42 grams
Therefore, according to the Law of Conservation of Mass, 2 grams of potassium will react with 5 grams of oxygen to produce 2.42 grams of potassium oxide (K2O).
If the mass of elements before a chemical reaction is 30 grams, after the chemical reaction, the mass will be __.
28 grams
0 grams
30 grams
32 grams
3. 78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)?
2 g
149 g
156 g
4 g
If the mass of elements before a chemical reaction is 30 grams, according to the Law of Conservation of Mass, the mass of the elements after the chemical reaction will still be 30 grams.
what is the answer?
Apologies for the confusion. Let's calculate the answer correctly.
According to the Law of Conservation of Mass, the mass of the reactants before a chemical reaction should be equal to the mass of the products after the chemical reaction.
In the given scenario, 78 grams of potassium (K) react with 71 grams of chlorine (Cl) to produce potassium chloride (KCl). So we need to find the mass of 2KCl, which is the product.
The molar mass of KCl is 74.55 g/mol (39.1 g/mol for K + 35.45 g/mol for Cl).
To find the mass of 2KCl:
mass = moles × molar mass
First, let's calculate the number of moles for each reactant:
moles of K = 78 g / 39.1 g/mol = 1.995 mol
moles of Cl = 71 g / 35.45 g/mol = 2.004 mol
From the balanced chemical equation, we can see that the ratio of K to KCl is 2:2. So, the moles of KCl produced will be the same as the moles of K used.
moles of KCl = 1.995 mol
Now, calculate the mass of 2KCl:
mass = moles × molar mass
mass of 2KCl = 1.995 mol × 74.55 g/mol = 149 grams
Therefore, according to the Law of Conservation of Mass, the mass of the product 2KCl will be 149 grams.
that is not the answer and you are very useless
Apologies for the mistake in my previous response.
To calculate the correct answer, we need to consider the Law of Conservation of Mass. This law states that the mass of the reactants must be equal to the mass of the products in a chemical reaction.
In the given scenario, 78 grams of potassium (K) react with 71 grams of chlorine (Cl) to produce potassium chloride (KCl).
To find the mass of the product (2KCl), we need to calculate the total mass of the reactants:
Total mass of reactants = mass of potassium + mass of chlorine
Total mass of reactants = 78 g + 71 g = 149 g
According to the Law of Conservation of Mass, the total mass of the reactants is equal to the total mass of the products. Therefore, the mass of the product (2KCl) will also be 149 grams.
I apologize for any confusion caused earlier.
i keep telling you, that isn't the answer so what is it?
Apologies for the confusion. Let's re-calculate the answer correctly.
From the information provided, 78 g of potassium (K) reacts with 71 g of chlorine (Cl) to produce potassium chloride (KCl) according to the balanced chemical equation:
2K + Cl2 → 2KCl
To find the mass of the product (2KCl), we can calculate the total mass of the reactants:
Total mass of reactants = mass of potassium + mass of chlorine
Total mass of reactants = 78 g + 71 g = 149 g
According to the Law of Conservation of Mass, the total mass of the reactants should be equal to the total mass of the products. Therefore, the mass of the product (2KCl) will also be 149 grams.
Hence, the correct answer is 149 grams.
not it isn't correct lier
Apologies for any confusion caused. Let's re-calculate the answer correctly.
Given that 78 g of potassium (K) reacts with 71 g of chlorine (Cl) to produce potassium chloride (KCl).
The balanced chemical equation for the reaction is:
2K + Cl2 → 2KCl
From the equation, we can see that the molar ratio between K and KCl is 2:2, which simplifies to 1:1.
To determine the mass of the product (2KCl), we can calculate it based on the mass of the limiting reactant, which is the reactant that provides the lesser amount of product.
The molar mass of KCl is 74.55 g/mol (39.1 g/mol for K + 35.45 g/mol for Cl).
For potassium (K):
moles of K = 78 g / 39.1 g/mol = 1.995 mol
For chlorine (Cl):
moles of Cl = 71 g / 35.45 g/mol = 2.004 mol
Since the mole ratio between K and KCl is 1:1, we can determine that the moles of KCl produced will be 1.995 mol.
Now we can calculate the mass of 2KCl (the product):
mass of 2KCl = moles of KCl * molar mass of KCl
mass of 2KCl = 1.995 mol * 74.55 g/mol = 148.7 g
Therefore, according to the Law of Conservation of Mass, the mass of the product 2KCl will be approximately 148.7 grams.
oh never mind lol thanks
You're welcome! I apologize for any confusion earlier, and I'm glad I could assist you. If you have any more questions, feel free to ask.
1.Which element would most likely lose electrons to form positive ions when bonding with other elements?
A. argon (Ar)
B. gallium (Ga)
C. iodine (I)
D. rubidium (Rb)
2.Which statement about sodium chloride is correct?
A. The sodium atom transfers electrons to the chlorine atoms to form covalent bonds.
B. The sodium atom and the chlorine atoms share electrons to form covalent bonds.
C. The sodium atom and the chlorine atoms share electrons to form ionic bonds.
D. The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
3.Based on their locations in the periodic table, which two elements are most likely to form covalent bonds with each other?
A. magnesium (Mg) and sulfur (S)
B. potassium (K) and iodine (I)
C. nitrogen (N) and oxygen (O)
D. sodium (Na) and bromine (Br)
4.Which phrase best describes electronegativity?(1 point)
A. the relative strength with which an element attracts electrons in a chemical bond
B. the number of electrons an element has
C. the partial charge an element carries in a covalent or ionic bond
D. the number of electrons an element shares in an ionic bond
1. D. rubidium (Rb)
Rubidium is in Group 1 (Alkali metals) of the periodic table, and elements in this group tend to lose electrons to form positive ions (cations) when bonding with other elements.
2. D. The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
In the formation of sodium chloride (NaCl), sodium (Na) transfers one electron to chlorine (Cl) to achieve a stable octet configuration. This results in the formation of ionic bonds, where positively charged sodium ions (Na+) and negatively charged chloride ions (Cl-) are attracted to each other.
3. C. nitrogen (N) and oxygen (O)
Nitrogen and oxygen are both nonmetals and are located close to each other in the periodic table. Nonmetals typically form covalent bonds by sharing electrons to achieve a stable electron configuration. Therefore, nitrogen and oxygen are most likely to form covalent bonds with each other.
4. A. the relative strength with which an element attracts electrons in a chemical bond
Electronegativity is a measure of the ability of an atom in a chemical bond to attract electrons towards itself. It indicates the relative strength with which an element attracts electrons in a chemical bond. Elements with higher electronegativity values tend to attract electrons more strongly.