a dog park covers an area of 3.49x10^4 yards. the community park next to it covers and area of 1.6x10^4 yards. what is the total number of yards in the dog park and community park combined?
To find the total area of the two parks combined, we need to add the areas of the dog park and the community park.
The area of the dog park is given as 3.49x10^4 yards.
The area of the community park is given as 1.6x10^4 yards.
To add these areas, we simply add the numbers in front of the powers of 10 separately:
3.49 + 1.6 = 5.09
Since both areas are measured in yards, we keep the units constant.
Therefore, the total area of the dog park and community park combined is 5.09x10^4 yards.
the distance from mercury to the sun is about 35,000,000 miles, the distance from the earth to the sub is about 5.8x10^7 farther. what is the distance from earth to the sun? write your answer in scientific notation to 1 decimal place
To find the distance from Earth to the Sun, we need to subtract the distance from Mercury to the Sun (35,000,000 miles) from the distance from Earth to the Sun (5.8x10^7 miles).
5.8x10^7 miles - 35,000,000 miles = 2.3x10^7 miles
Therefore, the distance from Earth to the Sun is approximately 2.3x10^7 miles.
calcuate 5.3x10^-3 - 6.7x10^-6. express the answer in scientific notation rounding to 2 decimal places
To subtract these numbers, we need to make sure that they have the same exponent.
5.3x10^-3 - 6.7x10^-6 can be rewritten as:
5.3x10^-3 - 0.0067x10^-3
Now, we can subtract them:
5.3 - 0.0067 = 5.2933
To express the answer in scientific notation and round to 2 decimal places, we can write it as:
5.29x10^-3
the average weight of am elephant is 1.15x10^4 pounds the average weight of a cat is 14 pounds. how much heavier is an elephant than a cat? express your answer is scientific notation
To calculate how much heavier an elephant is than a cat, we need to subtract the average weight of a cat from the average weight of an elephant.
1.15x10^4 pounds - 14 pounds = 1.15x10^4 pounds
Therefore, an elephant is 1.15x10^4 pounds heavier than a cat.
light travels at an approximate rate of 1.9x10^5 mi./sec there are approximately 2.6x10^6 seconds in a month. about how many miles does light travel in a month? write the answer in scientific notation. express the answer to the exact decimal place
To find out how many miles light travels in a month, we need to multiply the rate of light by the number of seconds in a month.
Rate of light: 1.9x10^5 mi/sec
Number of seconds in a month: 2.6x10^6 sec
Multiplying these two numbers:
(1.9x10^5 mi/sec) * (2.6x10^6 sec) = 4.94x10^11 mi
Therefore, light travels approximately 4.94x10^11 miles in a month.
the average plate tectonic plate moves at the rate of 0.006 meter per year. how many meters would it move in 3x10^6 years? write the answer in scientific notation, expressed to the exact decimal place.
To find out how many meters a tectonic plate would move in 3x10^6 years, we need to multiply the plate's rate by the number of years.
Rate of plate movement: 0.006 meter/year
Number of years: 3x10^6 years
Multiplying these two numbers:
(0.006 meter/year) * (3x10^6 years) = 1.8x10^4 meters
Therefore, a tectonic plate would move approximately 1.8x10^4 meters in 3x10^6 years.
an asteroid is heading toward mercury at a rate of 15.4x10^4 mi./hr if the asteroid is 6.622x10^8 miles away from mercury, how many hours will it be before it hits mercury? write the answer in scientific notation, expressed to the exact decimal place.
To find out how many hours it will take for the asteroid to hit Mercury, we need to divide the distance between Mercury and the asteroid by the rate at which the asteroid is moving.
Distance to Mercury: 6.622x10^8 miles
Rate of asteroid: 15.4x10^4 mi/hr
Dividing these two numbers:
(6.622x10^8 miles) / (15.4x10^4 mi/hr) = 4.30x10^4 hours
Therefore, it will take approximately 4.30x10^4 hours for the asteroid to hit Mercury.
a field of 7.8 mi^2 is being subdivided into 2.6x10^3 lots for houses to be built. how many square miles will there be in each lot? write the answer in scientific notation.
To find out how many square miles will be in each lot, we need to divide the total area of the field by the number of lots.
Area of the field: 7.8 mi^2
Number of lots: 2.6x10^3
Dividing these two numbers:
7.8 mi^2 / (2.6x10^3) = 3.00x10^-3 mi^2
Therefore, there will be approximately 3.00x10^-3 square miles in each lot.
joaquin is using his calculator to find the product of two large numbers. his calculator shows 2.67E11 on the display interpret what this means.
The display on Joaquin's calculator, showing 2.67E11, represents the number in scientific notation. E in this context represents "times 10 raised to the power of."
So, 2.67E11 can be interpreted as 2.67 multiplied by 10 raised to the power of 11.
In standard notation, this would be written as:
2.67 * 10^11
which is equal to:
267,000,000,000
Therefore, 2.67E11 is equivalent to 267 billion.
Add 31−−√+31−−√ .
To add 31−−√ and 31−−√, you can combine them under one radical and simplify if possible.
√31 + √31
Since both terms have the same radical, we can simply add the coefficients outside the radical:
2√31
Therefore, the sum of 31−−√ and 31−−√ is 2√31.
Subtract 75–√−45–√
To subtract 75–√ from 45–√, we can rewrite the expression as a single radical and simplify if possible.
(75–√) - (45–√)
Now, let's combine like terms. Since both expressions have the same radical, we can simply subtract the coefficients outside the radical:
75 – 45 = 30
Therefore, the result is 30 –√.
Subtract 29−−√−29−−√
To subtract 29−−√ from 29−−√, we can rewrite the expression as a single radical and simplify if possible.
(29−−√) - (29−−√)
Now, let's combine like terms. Since both expressions have the same radical, we can simply subtract the coefficients outside the radical:
29 - 29 = 0
Therefore, the result is 0.
The tiles in a store are being compared. The diagonal of one tile is 92–√ centimeters, and the other tile is 82–√ centimeters. What is the difference in the length of the diagonals?
To find the difference in the length of the diagonals, we subtract the length of one diagonal from the other.
92–√ - 82–√
We cannot simplify the square roots any further, so we keep them as they are.
To subtract square roots with the same radical, we need to have the same coefficient in front of the square root.
92–√ - 82–√ can be rewritten as:
√92 - √82
Now, subtract the coefficients outside the square root:
√92 - √82 = 52 - 42 = 10
Therefore, the difference in the length of the diagonals is 10 centimeters.
Add 3√21 + 7√21.
To add 3√21 and 7√21, we can combine them since they have the same radical term.
3√21 + 7√21 = (3 + 7)√21 = 10√21
Therefore, the sum of 3√21 and 7√21 is 10√21.
Add √19 + √19
To add √19 and √19, we can simply combine them since they have the same radical term.
√19 + √19 = 2√19
Therefore, the sum of √19 and √19 is 2√19.
add 22−−√3 + 322−−√ + 22
To add 22−−√3, 32−−√, and 22, we first group the terms with the same radical and then combine them.
22−−√3 + 32−−√ + 22
Using the square root notation (√), we can rewrite the expression as:
√3 + 5√2 + 2
Now, combining the terms:
√3 + 5√2 + 2 = 2 + √3 + 5√2
Therefore, the sum of 22−−√3, 32−−√, and 22 is 2 + √3 + 5√2.
add 3√22 + 3√22 + 22
To add 3√22, 3√22, and 22, we combine the like terms.
3√22 + 3√22 + 22
Since both terms have the same radical, we can add the coefficients outside the radical:
3 + 3 = 6
Therefore, the sum of 3√22, 3√22, and 22 is 6√22 + 22.
Subtract 823−−√−23−−√
To subtract 823−−√ from 23−−√, we can rewrite the expression as a single radical and simplify if possible.
23−−√ - 823−−√
Now, let's combine like terms. Since both expressions have the same radical, we can simply subtract the coefficients outside the radical:
23 - 823 = -800
Therefore, the result is -800−−√.
Subtract 8√23−√23
To subtract 8√23 from √23, we can rewrite the expression as a single radical and simplify if possible.
√23 - 8√23
Now, let's combine like terms. Since both expressions have the same radical, we can simply subtract the coefficients outside the radical:
1 - 8 = -7
Therefore, the result is -7√23.
Jake runs 76–√ miles on Monday and 56–√ miles on Tuesday. What is the difference in miles run each day?
To find the difference in miles run each day, we need to subtract the distance run on Tuesday from the distance run on Monday.
76–√ miles - 56–√ miles
Since both terms have the same radical, we can simply subtract the coefficients outside the radical:
76 - 56 = 20
Therefore, the difference in miles run each day is 20 miles.
Jake runs 7√6 miles on Monday and 5√6 miles on Tuesday. What is the difference in miles run each day?
To find the difference in miles run each day, we need to subtract the distance run on Tuesday from the distance run on Monday.
7√6 miles - 5√6 miles
Since both terms have the same radical, we can simply subtract the coefficients outside the radical:
7 - 5 = 2
Therefore, the difference in miles run each day is 2√6 miles.