which of the following compounds contains the lowest percentage by mass of nitrogen?
1) NH4NO3
2) (NH4)2 SO4
3) NaNO3
4) NH3
can someone please help me??what method should i use?how do i do this?
Find the molar mass of each compound by adding the molar masses of every atom (including N) in the compound and divide the the total molar mass of nitrogen (only N) in the compound by that value. (14.0067* (# of N atoms))/(compound molar mass) This should give you each percentage of mass of nitrogen. Good Luck!!!
To find the compound with the lowest percentage by mass of nitrogen, you can use the method of calculating the molar mass and then dividing the molar mass of nitrogen by the total molar mass of each compound. Here's how you can do it:
1) NH4NO3:
- Molar mass of NH4NO3 = (1*4.0026) + (4*1.00784) + (1*14.0067) + (3*15.999) = 80.0434 g/mol
- Percentage by mass of nitrogen = (1*14.0067)/(80.0434) = 0.1749 or 17.49%
2) (NH4)2SO4:
- Molar mass of (NH4)2SO4 = (2*4.0026) + (8*1.00784) + (1*32.06) + (4*16.00) = 132.1392 g/mol
- Percentage by mass of nitrogen = (2*14.0067)/(132.1392) = 0.4235 or 42.35%
3) NaNO3:
- Molar mass of NaNO3 = (1*22.98977) + (1*14.0067) + (3*15.999) = 85.01 g/mol
- Percentage by mass of nitrogen = (1*14.0067)/(85.01) = 0.1647 or 16.47%
4) NH3:
- Molar mass of NH3 = (1*14.0067) + (3*1.00784) = 17.0307 g/mol
- Percentage by mass of nitrogen = (1*14.0067)/(17.0307) = 0.8217 or 82.17%
From these calculations, we can see that NH3 has the highest percentage by mass of nitrogen, while NH4NO3 has the lowest percentage by mass of nitrogen.
Therefore, the compound with the lowest percentage by mass of nitrogen is NH4NO3 (17.49%).