The total pressure in a flask containing air and ethanol at 257C is 878 mm Hg. The pressure of the air in the flask at 257C is 762 mm Hg. If the flask is immersed in a water bath at 300C, the total pressure is 980 mm Hg. The vapor pressure of ethanol at the new temperature is mm Hg.
Hint: you will need to correct the pressure of air at the new temperature using the Gas Law: P1T1 = P2T2
* 25.7 and 30.0 for the temperature
Did you make an error in the decimal points? Is P1T1 = P2T2 correct? I don't think so. Check all of your numbers so make sure they are right.
if you mean 30C then here is the answer
Air pressure =
763mmHg
298.7K
ethanol pressure
? mmHG
303 K
Total pressure of water=
980 mmHG
303 K
you need to change air pressure to be based on 303 K after its been placed or immersed in water.
P1/T1= P2/T2
(762 X 303)/ 298.7 = ?
? = 772.96 mmHG
now you can simply subtract the air from the total pressure under water and get the pressure of ethanol
980- 772.96= 207.04
To find the vapor pressure of ethanol at the new temperature, we can use the equation P1T1 = P2T2, which relates pressure and temperature.
First, let's consider the given information:
- The total pressure in the flask containing air and ethanol at 25°C is 878 mm Hg.
- The pressure of the air in the flask at 25°C is 762 mm Hg.
- The flask is then immersed in a water bath at 30°C, and the total pressure becomes 980 mm Hg.
Using the equation P1T1 = P2T2, we can set up the following equation:
(878 mm Hg)(25°C) = (980 mm Hg)(30°C)
To solve for the pressure of air at the new temperature, we rearrange the equation as follows:
(762 mm Hg)(25°C) = P2(30°C)
Now, we can solve for P2:
P2 = (762 mm Hg)(25°C) / (30°C)
P2 = 635.5 mm Hg
Therefore, the pressure of air at the new temperature of 30°C is approximately 635.5 mm Hg.
To find the vapor pressure of ethanol at the new temperature, we know that the total pressure is 980 mm Hg and the pressure of air at the new temperature is 635.5 mm Hg.
Therefore, the vapor pressure of ethanol can be calculated as:
Vapor pressure of ethanol = Total pressure - Pressure of air
Vapor pressure of ethanol = 980 mm Hg - 635.5 mm Hg
Vapor pressure of ethanol at the new temperature is approximately 344.5 mm Hg.