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(4 points)
The Wonderful World of Synthetic Chemistry The Dangerous World of Synthetic Chemistry
Synthetic products are made from natural resources.
The Wonderful World of Synthetic Chemistry – Synthetic products are made from natural resources.
The Dangerous World of Synthetic Chemistry – Synthetic products are made from natural resources.
Synthetic products can be useful and can even save lives.
The Wonderful World of Synthetic Chemistry – Synthetic products can be useful and can even save lives.
The Dangerous World of Synthetic Chemistry – Synthetic products can be useful and can even save lives.
Synthetic products can be toxic for people and the planet.
The Wonderful World of Synthetic Chemistry – Synthetic products can be toxic for people and the planet.
The Dangerous World of Synthetic Chemistry – Synthetic products can be toxic for people and the planet.
People should avoid using synthetic products whenever possible.
The Dangerous World of Synthetic Chemistry – People should avoid using synthetic products whenever possible.
How do you expect synthetic materials to compare to the natural resources used to make them?
(1 point)
Responses
The synthetic materials have the same properties as the raw materials because chemical reactions took place.
The synthetic materials have the same properties as the raw materials because chemical reactions took place.
The synthetic materials have different properties from the raw materials because chemical reactions took place.
The synthetic materials have different properties from the raw materials because chemical reactions took place.
The synthetic materials have the same properties as the raw materials because chemical reactions did not take place.
The synthetic materials have the same properties as the raw materials because chemical reactions did not take place.
The synthetic materials have different properties from the raw materials because chemical reactions did not take place.
The synthetic materials have different properties from the raw materials because chemical reactions took place.
Drag and drop each item into the correct column in order to sort the synthetic materials vs. the natural materials.
(2 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
synthetic materials natural materials
I apologize, but as a text-based AI, I am unable to perform drag and drop actions. However, I can help you sort the synthetic materials and natural materials into columns. Please provide me with the list of materials, and I will assist you in sorting them correctly.
Sunscreen spray latex paint water cotton paint oak tree plastic bottle liquid petroleum nylon shorts
synthetic materials: sunscreen spray, latex paint, plastic bottle, liquid petroleum, nylon shorts
natural materials: water, cotton, oak tree
n the video, 1 gram of ammonium chloride is added to 5 mL of water. The following reaction takes place.
NH4
Cl + H2
O → NH4
OH + HCl
starting temperature ending temperature
20o
C 14o
C
Fill in the blanks to complete the following description.
(6 points)
In this reaction, the temperature changed from
to
. This means the temperature
. This type of reaction is categorized as
. This type of reaction causes the surrounding to feel
, which is why it is a good reaction to use when designing a
In this reaction, the temperature changed from 20°C to 14°C. This means the temperature decreased. This type of reaction is categorized as an endothermic reaction. This type of reaction causes the surroundings to feel cooler, which is why it is a good reaction to use when designing a cooling system.
i got a f
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<SDBHMVj
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ok can you help me do my math
Of course! I'll do my best to assist you with your math problem. Please go ahead and let me know what specific math problem or concept you need help with.
Use the properties of operations and rules for multiplying and dividing to solve:
(−2)×(15)÷(23)×(−56)÷(34)
(1 point)
Responses
16
Start Fraction 1 over 6 End Fraction
23
Start Fraction 2 over 3 End Fraction
−16
negative Start Fraction 1 over 6 End Fraction
−23
To solve the expression (-2) × (15) ÷ (23) × (-56) ÷ (34), you can follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).
First, multiply -2 and 15:
(-2) × (15) = -30.
Then, divide -30 by 23:
-30 ÷ 23 ≈ -1.3043 (rounded to four decimal places).
Next, multiply -1.3043 by -56:
-1.3043 × (-56) ≈ 73.0262 (rounded to four decimal places).
Finally, divide 73.0262 by 34:
73.0262 ÷ 34 ≈ 2.1472 (rounded to four decimal places).
Therefore, the solution to the given expression is approximately 2.1472.
Use the properties of operations and rules for multiplying and dividing to solve:
(−2)×(15)÷(23)×(−56)÷(34)
(1 point)
Responses
16
Start Fraction 1 over 6 End Fraction
2/3
Start Fraction 2 over 3 End Fraction
−1/6
negative Start Fraction 1 over 6 End Fraction
−2/3
To solve the expression (-2) × (15) ÷ (23) × (-56) ÷ (34), you can perform the operations in the following order:
Multiply (-2) and (15):
(-2) × (15) = -30
Divide -30 by 23:
-30 ÷ 23 ≈ -1.3043 (rounded to four decimal places)
Multiply -1.3043 and -56:
-1.3043 × -56 ≈ 73.0262 (rounded to four decimal places)
Divide 73.0262 by 34:
73.0262 ÷ 34 ≈ 2.1472 (rounded to four decimal places)
Therefore, the solution to the expression is approximately 2.1472.
Use the properties of operations and rules for multiplying and dividing to solve:
(−2)×(1/5)÷(2/3)×(−5/6)÷(3/4)
(1 point)
Responses
1/6
Start Fraction 1 over 6 End Fraction
2/3
Start Fraction 2 over 3 End Fraction
−1/6
negative Start Fraction 1 over 6 End Fraction
−2/3
To solve the expression (-2) × (1/5) ÷ (2/3) × (-5/6) ÷ (3/4), you can follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).
First, multiply -2 and 1/5:
(-2) × (1/5) = -2/5.
Then, divide -2/5 by 2/3:
(-2/5) ÷ (2/3) = (-2/5) × (3/2) = -6/10 = -3/5.
Next, multiply -3/5 by -5/6:
(-3/5) × (-5/6) = (3/5) × (5/6) = 15/30 = 1/2.
Finally, divide 1/2 by 3/4:
(1/2) ÷ (3/4) = (1/2) × (4/3) = 4/6 = 2/3.
Therefore, the solution to the given expression is 2/3.
se the properties of operations and rules for multiplying and dividing to solve:
(9)÷(54)×(79)×(−5)÷(72)
(1 point)
Responses
−8
negative 8
−1,225/8
negative Start Fraction 1,225 over 8 End Fraction
8
8
1,225/8
To solve the expression (9) ÷ (54) × (79) × (-5) ÷ (72), you can perform the operations in the following order:
First, perform the division 9 ÷ 54:
9 ÷ 54 = 1/6
Next, multiply the result by 79:
(1/6) × 79 = 79/6
Then, multiply the previous result by -5:
(79/6) × (-5) = -395/6
Finally, divide the result by 72:
(-395/6) ÷ 72 = -395/432
Therefore, the solution to the expression is -395/432.