A net of a rectangular prism is gown below. The surface area of each face is labeled.
12m^2 30m^2 12m^2 40m^2 30m^2 40m^2
Which values represent the dimensions, in meters, of the rectangular prism?
A. 12,30,40
B. 3,4,10
C. 2,5,6
D. 2,6,8
To determine the dimensions of the rectangular prism, we need to find three values that represent the lengths of each side of the prism.
Looking at the net, we can see that the two sides with a surface area of 12 m^2 are adjacent to each other. This means that these two sides represent the dimensions of the length and width of the prism. Therefore, one side is 12 m and the other side is 30 m.
Next, we can see that the side with a surface area of 40 m^2 is opposite to the side with a surface area of 30 m^2. This means that the 40 m side represents the height of the prism.
Therefore, the dimensions of the rectangular prism are 12, 30, and 40.
The correct answer is A. 12, 30, 40.
The table shows the different prizes customers could win at the fair and the number of times that prize was selected.
Type of
Prize water bottle | 36
sunglasses | 26
pencil | 14
stuffed animal | 24
A 3/5
B 2/5
C 4/5
D 1/5
To find the probability of selecting each prize, we need to divide the number of times each prize was selected by the total number of selections.
The total number of selections can be found by adding up the number of times each prize was selected:
36 + 26 + 14 + 24 = 100
Now we can find the probability of selecting each prize:
Probability of selecting water bottle = 36 / 100 = 0.36 = 36/100 = 3/5
Probability of selecting sunglasses = 26 / 100 = 0.26 = 26/100 = 2/5
Probability of selecting pencil = 14 / 100 = 0.14 = 14/100 = 1/5
Probability of selecting stuffed animal = 24 / 100 = 0.24 = 24/100 = 2/5
Therefore, the correct answer is A. 3/5
The table shows the different prizes customers could win at the fair and the number of times that prize was selected.
Type of
Prize water bottle | 36
sunglasses | 26
pencil | 14
stuffed animal | 24
A 3/5
B 2/5
C 4/5
D 1/5
To find the probability of selecting each prize, we need to divide the number of times each prize was selected by the total number of selections.
The total number of selections can be found by adding up the number of times each prize was selected:
36 + 26 + 14 + 24 = 100
Now we can find the probability of selecting each prize:
Probability of selecting water bottle = 36 / 100 = 0.36 = 36/100 = 9/25
Probability of selecting sunglasses = 26 / 100 = 0.26 = 26/100 = 13/50
Probability of selecting pencil = 14 / 100 = 0.14 = 14/100 = 7/50
Probability of selecting stuffed animal = 24 / 100 = 0.24 = 24/100 = 6/25
Therefore, the correct answer is not listed.
× The spinner shown is divided into congruent sections that are labeled from 1 through 9. If the spinner is spun one time, what is the probability of the arrow not landing on a section labeled with an
A 5/9
B 4/9
C 1/3
D1/2
To find the probability of the arrow not landing on a section labeled with an A, we need to determine the number of sections that are not labeled with an A.
Looking at the spinner, there are 9 sections in total, and 2 sections are labeled with an A (assuming A represents the sections labeled with an A).
Therefore, the number of sections not labeled with an A is 9 - 2 = 7.
Since the spinner is spun one time and can land on any section with equal probability, the total number of equally likely outcomes is 9.
The probability of the arrow not landing on a section labeled with an A is then 7/9.
Therefore, the correct answer is not listed.
4× Jose ran 7 kilometers. One mile is approximately equal to 1.6 kilometers. Which measurement is closest to the number of miles Jose ran?
A 11.2
B 4.4
C 5.4
D 20.3
To find the number of miles Jose ran, we need to divide the number of kilometers he ran by the conversion factor of 1.6 kilometers per mile.
7 kilometers ÷ 1.6 kilometers per mile ≈ 4.375 miles
Since we want to find the measurement that is closest to the number of miles Jose ran, we can round 4.375 to the nearest tenth.
Rounding 4.375 to the nearest tenth, we get 4.4.
Therefore, the closest measurement to the number of miles Jose ran is B. 4.4.
A jacket is reduced from $20 to $14. By what percentage was the price of the jacket reduced?
A 25%
B 20%
C 15%
D 30%
To find the percentage by which the price of the jacket was reduced, we can use the formula:
Percentage reduction = (Original price - Reduced price) / Original price × 100
In this case, the original price of the jacket was $20 and the reduced price was $14.
Percentage reduction = (20 - 14) / 20 × 100 = 6 / 20 × 100 = 0.3 × 100 = 30%
Therefore, the price of the jacket was reduced by 30%. The correct answer is D. 30%.
{× Which equation is true when the value of wis-18?
A 15- 1/2w=21
B 3w + 4 = -45
C 24 - 3w = 78
D 2w + 10 = 26
To check which equation is true when the value of w is -18, we can substitute -18 for w in each equation and see which equation is satisfied.
A) 15 - 1/2w = 21
Substituting w = -18:
15 - 1/2(-18) = 21
15 + 9 = 21
24 = 21
This is not true.
B) 3w + 4 = -45
Substituting w = -18:
3(-18) + 4 = -45
-54 + 4 = -45
-50 = -45
This is not true.
C) 24 - 3w = 78
Substituting w = -18:
24 - 3(-18) = 78
24 + 54 = 78
78 = 78
This is true.
D) 2w + 10 = 26
Substituting w = -18:
2(-18) + 10 = 26
-36 + 10 = 26
-26 = 26
This is not true.
Therefore, the equation that is true when w is -18 is C) 24 - 3w = 78.
× What is the solution to this equation?4
4/5 * -1/3 = 1/3
A x=0
B x= 8/15
C x = 5/6
D x = 6/5
To find the solution to the equation 4/5 * -1/3 = 1/3, we need to multiply the fractions on the left side:
4/5 * -1/3 = (4 * -1)/(5 * 3) = -4/15
The equation becomes -4/15 = 1/3.
To isolate x, we can multiply both sides of the equation by the reciprocal of -4/15, which is -15/4:
(-4/15) * (-15/4) = (1/3) * (-15/4)
This simplifies to:
1 = -5/4
The equation is not true.
Therefore, there is no solution to the equation.
The correct answer is not listed.
*× What is the solution set for x? 6 ≤ 9?
The inequality given is 6 ≤ 9.
In this case, 6 is indeed less than or equal to 9.
Since the inequality is true for all values of x, the solution set for x is all real numbers.
Therefore, the solution set for x is (-∞, +∞), or in interval notation, (-∞, +∞).