Given the sum 70=25+45, rewrite 25+45 using their GCF and multiplication.(1 point)
The Greatest Common Factor (GCF) of 25 and 45 is 5.
To rewrite 25+45 using their GCF and multiplication, we can factor out the GCF from both terms:
25 = 5 x 5
45 = 5 x 9
So, 25 + 45 can be rewritten as:
25 + 45 = (5 x 5) + (5 x 9) = 5(5 + 9)
Given the sum 99=33+66, rewrite 33+66 using their GCF and multiplication.(1 point)
The Greatest Common Factor (GCF) of 33 and 66 is 33 since it is the largest number that divides both 33 and 66 without leaving a remainder.
To rewrite 33 + 66 using their GCF and multiplication, we can factor out the GCF from both terms:
33 = 33 x 1
66 = 33 x 2
So, 33 + 66 can be rewritten as:
33 + 66 = (33 x 1) + (33 x 2) = 33(1 + 2) = 33(3)
Given the sum 30=12+18, rewrite 12+18 using their GCF and multiplication.(1 point)
The Greatest Common Factor (GCF) of 12 and 18 is 6.
To rewrite 12 + 18 using their GCF and multiplication, we can factor out the GCF from both terms:
12 = 6 * 2
18 = 6 * 3
So, 12 + 18 can be rewritten as:
12 + 18 = (6 * 2) + (6 * 3) = 6(2 + 3) = 6 * 5
Given the sum 85, rewrite 35+50 using their GCF and multiplication.(1 point)
To rewrite 35+50 using their Greatest Common Factor (GCF) and multiplication, we need to find the GCF first.
The GCF of 35 and 50 is 5.
Now, let's factor out the GCF from both terms:
35 = 5 * 7
50 = 5 * 10
So, 35 + 50 can be rewritten as:
35 + 50 = (5 * 7) + (5 * 10) = 5(7 + 10)
Given the sum 100=25+75, rewrite 25+75 using their GCF and multiplication.(1 point)
To rewrite 25+75 using their Greatest Common Factor (GCF) and multiplication, we need to find the GCF first.
The GCF of 25 and 75 is 25.
Now, let's factor out the GCF from both terms:
25 = 25 * 1
75 = 25 * 3
So, 25 + 75 can be rewritten as:
25 + 75 = (25 * 1) + (25 * 3) = 25(1 + 3) = 25 * 4
Philip is sorting acorns he collected. He has 92 acorns: 66 still have their tops, 26 do not. Philip wants to sort the acorns into groups with the same number of acorns, including some with and without tops. He wants each group to have an equal number of acorns with tops and an equal number of acorns without tops. Which answer best shows how Philip can represent how he should sort the acorns?(1 point)
Responses
6(11+4)
6 left parenthesis 11 plus 4 right parenthesis
2(33+13)
2 left parenthesis 33 plus 13 right parenthesis
24(3+1)
24 left parenthesis 3 plus 1 right parenthesis
1(66+26)
The best representation of how Philip can sort the acorns is:
2(33 + 13)
This means he can create two groups, where each group has 33 acorns with tops and 13 acorns without tops.
Mei is playing a game with numbers. She decides to rewrite the number 78 using the Distributive Property. Which answer is a correct way to rewrite 78 using the Distributive Property of Multiplication over Addition?(1 point)
Responses
78=18+60=(6×3)+(6×10)=6(3+10)
78 equals 18 plus 60 equals left parenthesis 6 times 3 right parenthesis plus left parenthesis 6 times 10 right parenthesis equals 6 left parenthesis 3 plus 10 right parenthesis
78=22+56=(2×11)+(2×28)=2(11×28)
78 equals 22 plus 56 equals left parenthesis 2 times 11 right parenthesis plus left parenthesis 2 times 28 right parenthesis equals 2 left parenthesis 11 times 28 right parenthesis
78=24+54=(6×4)+(6×9)=6(4×9)
78 equals 24 plus 54 equals left parenthesis 6 times 4 right parenthesis plus left parenthesis 6 times 9 right parenthesis equals 6 left parenthesis 4 times 9 right parenthesis
78=11+67=(1×11)+(1×67)=1(11×67)
The correct way to rewrite 78 using the Distributive Property of Multiplication over Addition is:
78 = 24 + 54 = (6 × 4) + (6 × 9) = 6(4 × 9)
Sven is making a school supply display. Sven has 52 notebooks and 42 binders. Sven wants to group the supplies in the display so that there are an equal number of supplies in each group. If we know that Sven puts the same number of notebooks and the same number of binders into each group, how many groups did he display and how many of each item went into each group? Represent your answer using the Distributive Property of Multiplication over Addition.(1 point)
Responses
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis .
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52×42).
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 times 42 right parenthesis .
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 times 21 right parenthesis .
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52+42).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21).
Given the sum 100=64+36, rewrite 64+36 using their GCF and multiplication.(1 point)
Responses
1(64+36)
1 left parenthesis 64 plus 36 right parenthesis
2(32+18)
2 left parenthesis 32 plus 18 right parenthesis
4(16+9)
4 left parenthesis 16 plus 9 right parenthesis
4(16×9)
The Greatest Common Factor (GCF) of 64 and 36 is 4.
To rewrite 64+36 using their GCF and multiplication, we can factor out the GCF from both terms:
64 = 4 * 16
36 = 4 * 9
So, 64 + 36 can be rewritten as:
64 + 36 = (4 * 16) + (4 * 9) = 4(16 + 9) = 4(25)
Given the sum 18=6+12, rewrite 6+2 using their GCF and multiplication.(1 point)
Responses
3(2+4)
3 left parenthesis 2 plus 4 right parenthesis
6(1+2)
6 left parenthesis 1 plus 2 right parenthesis
1(6+12)
1 left parenthesis 6 plus 12 right parenthesis
6(1×2)
The Greatest Common Factor (GCF) of 6 and 12 is 6.
To rewrite 6 + 12 using their GCF and multiplication, we can factor out the GCF from both terms:
6 = 6 * 1
12 = 6 * 2
So, 6 + 12 can be rewritten as:
6 + 12 = (6 * 1) + (6 * 2) = 6(1 + 2) = 6(3)