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chemistry
When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 1.0500 x 10^4 K. According to the Clausius Clapeyron equation, Hvap is kJ/mol. ?
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 9.500 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is kJ/mol.
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 8.000 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is ? kJ/mol.
asked by jin on February 1, 2008 
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 8.000 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is ? kJ/mol.
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 8.000 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is ? KJ/mol
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The total pressure in a flask containing air and ethanol at 25.7C is 878 mm Hg. The pressure of the air in the flask at 25.7C is 762 mm Hg. If the flask is immersed in a water bath at 45.0C , the total pressure is 980 mm Hg. The
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Find the pressure of a gas that originally had a volume of 25 L, pressure of 67kPa at a temperature of 100 Kelvin. When the gas was heated to 200 Kelvin, it had a volume of 56L. How many moles would be present if the gas in the
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