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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 20000 K. According to the Clausius Clapeyron equation, (triangle)Hvap is ? kJ/mol 
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 8.000 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is ? kJ/mol. 
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When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to 8.000 x 10^3 K. According to the Clausius Clapeyron equation, Hvap is ? KJ/mol 
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