solve (2x+3) exponet2over3=3

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(2x+3)^(2/3) = 3 ??
cube both sides:
(2x+3)^2 = 27
now take √ of both sides
2x + 3 = ± √27
2x = -3 ± √27
x = (-3 ± √27)/2

To solve the equation (2x + 3)^(2/3) = 3, we'll go through the following steps:

Step 1: Isolate the exponentiated term.
Start by subtracting 3 from both sides of the equation:
(2x + 3)^(2/3) - 3 = 0

Step 2: Remove the exponent.
To remove the exponent, we need to raise both sides of the equation to the reciprocal of the exponent:
[(2x + 3)^(2/3) - 3]^3/2 = 0

Step 3: Expand the equation.
Expand the left side of the equation by applying the power of a difference formula:
[(2x + 3) - 3^3/2]^3 = 0

Simplifying further:
(2x)^3 = 0

Step 4: Solve for x.
Cube both sides of the equation:
8x^3 = 0

Divide both sides by 8:
x^3 = 0

Take the cube root of both sides to isolate x:
x = 0

So the solution to the equation (2x + 3)^(2/3) = 3 is x = 0.