A(n) is a two-dimensional diagram that can be folded to form a three-dimensional (1 point) net Oorthographic drawing isometric drawing geometric solid
The correct answer is net.
How would you write the name of a segment differently than the name of a line? would you use?
To differentiate between the name of a segment and the name of a line, you can use notation as follows:
1. For a segment: Use two capital letters, such as AB or CD, to represent the endpoints of the segment.
2. For a line: Use a single capital letter, such as L or M, to represent the line. You can also add a lowercase letter as a subscript, like line l or line m, to identify different lines.
It is important to note that segment names are written using two capital letters, and line names only use one capital letter.
How is constructing a perpendicular bisector similar to constructing an angle bisector? How different?
Constructing a perpendicular bisector and constructing an angle bisector are similar in that both involve dividing a line or an angle into two equal parts. However, they differ in terms of the geometric elements they work with:
1. Perpendicular Bisector: When constructing a perpendicular bisector, you draw a line that cuts another line segment into two equal halves at a right angle (90 degrees). It involves constructing a line that intersects the given line segment at its midpoint, forming two congruent segments.
2. Angle Bisector: When constructing an angle bisector, you draw a line that divides an angle into two equal angles. It involves constructing a line that intersects the angle and divides it into two congruent angles.
In summary, both the perpendicular bisector and the angle bisector involve dividing a given geometric element (line segment or angle) into two equal parts, but the perpendicular bisector works with line segments and creates right angles, while the angle bisector works with angles and divides them into two equal angles.
a process you would use to create the perpendicular bisector to a segment AB using on arked straightedge and an unmarked compass . ts)
To construct a perpendicular bisector to a segment AB using only a straightedge and an unmarked compass, follow these steps:
1. Place the compass point on point A and adjust the compass width to any length greater than half the length of segment AB.
2. Without changing the compass width, draw two arcs, one above and one below the segment, cutting the line on both sides. Label these points of intersection as C and D.
3. With the compass point on C, adjust the compass width to a length greater than half the length of segment CD.
4. Without changing the compass width, draw an arc intersecting the first arc drawn. Label this point of intersection as E.
5. Switch the compass point to D (keeping the width the same) and repeat step 4. Label this point of intersection as F.
6. Use a straightedge to draw a line through points E and F. This line is the perpendicular bisector to segment AB.
By constructing these arcs and intersecting them, you can find the midpoint of segment AB (point C) and extend the perpendicular bisector line through it.
How would you write the name of a segment differently than the name of a line? What symbols would you use?
To differentiate between the name of a segment and the name of a line, you can use different symbols or notation:
1. Segment: In general, segments are denoted by two uppercase letters representing the endpoints of the segment. For example, if the segment connects points A and B, it can be written as segment AB or simply as AB with a line segment symbol (a horizontal line segment) drawn over it.
2. Line: Lines are typically denoted by a single uppercase letter. For example, a line can be represented as line L, line M, or any other letter of choice. To emphasize that it is a line, you can add a small arrow on top of the letter, such as L→ or M→.
It is important to note that the specific symbols used to represent segments and lines can vary depending on the notation style or mathematical convention being used.
MUse the diagram to answer the question . Which angle forms a vertical pair with angle OSN S ( 1 point ) N angle LSO; angle LSM Figure 2. angle NSM; angle LMS
Based on the given diagram and the options provided, the angle that forms a vertical pair with angle OSN is angle NSM.
Use the number line to answer the question. Which two points are 4 units from K? ( 1 point) and M and L and N G and
Without a specific number line or further information, it is not possible to determine which two points are exactly 4 units from point K. Please provide a number line or additional context for a more accurate response.
G H L N NO Use the number line to answer the questic Which segment is congruent to segment -6 (1point); overline HL; overline MO; overline KN IM
To determine which segment is congruent to segment -6, we need to locate the points that are 6 units away from point K. Looking at the provided points on the number line, the segment congruent to segment -6 is overline MO.
G H J LMN0 12 Use the number line to answer the questio What is the midpoint of NH? ( 1 point)
To find the midpoint of NH, locate points N and H on the number line and find the point exactly halfway between them.
However, the provided points (G, H, J, L, M, N, O) and the number line values (1, 2, 12) do not include the points N and H. Without the specific values for N and H on the number line, we cannot determine the midpoint of NH. Please provide the values for N and H or a more complete number line.
angle1 and angle2 are supplementary angles . m / 1 is 4y + 7 and m / 2 is 9u + 4 Find m / 2
If angle1 and angle2 are supplementary angles, it means that the sum of their measures is 180 degrees.
Given that m/1 is equal to 4y + 7 and m/2 is equal to 9u + 4, we can set up the equation:
m/1 + m/2 = 180
Substituting the given angles, we have:
4y + 7 + 9u + 4 = 180
Simplifying the equation by combining like terms:
4y + 9u + 11 = 180
To find m/2, we can isolate 9u and solve for u:
9u = 180 - 11 - 4y
9u = 169 - 4y
Dividing both sides by 9:
u = (169 - 4y) / 9
Therefore, m/2 is equal to 9u + 4 or (9(169 - 4y) / 9) + 4, which simplifies to:
m/2 = 169 - 4y + 4
m/2 = 173 - 4y
rangle bisects angle DGH so that m angle DGI is x - 3 and m angle IGH is 2x - 13 Find the value of .
To find the value of x, you can set up an equation using the fact that the angle bisector divides the angle into two congruent angles.
Given that m angle DGI is x - 3 and m angle IGH is 2x - 13, we have:
x - 3 = 2x - 13
Simplifying the equation, move the x terms to one side:
x - 2x = -13 + 3
-x = -10
Multiply both sides by -1 to isolate x:
x = 10
Therefore, the value of x is 10.
The midpoint of overline UV is (5, - 11) The coordinates of one endpoint are U(3, 5) Find the coordinates of endpoint V.
To find the coordinates of endpoint V, we can use the midpoint formula, which states that the midpoint of a line segment is the average of the coordinates of its endpoints.
Given that the midpoint of overline UV is (5, -11) and one endpoint is U(3, 5), we can use the formula:
Midpoint = ( (x1 + x2)/2 , (y1 + y2)/2 )
Substitute the values into the formula:
(5, -11) = ( (3 + x)/2 , (5 + y)/2 )
To find the value of x, we can set up an equation:
(3 + x)/2 = 5
Solving for x:
3 + x = 10
x = 7
To find the value of y, we set up another equation:
(5 + y)/2 = -11
Solving for y:
5 + y = -22
y = -27
Therefore, the coordinates of endpoint V are V(7, -27).
Find the distance between points M(6, 16) and Z(- 1, 14) to the nearest tenth
To find the distance between two points, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Given that M(6, 16) and Z(-1, 14), we can substitute the coordinates into the formula:
Distance = √((-1 - 6)^2 + (14 - 16)^2)
Simplifying:
Distance = √((-7)^2 + (-2)^2)
Distance = √(49 + 4)
Distance = √53
Calculating the square root of 53, we find:
Distance ≈ 7.2801
Rounded to the nearest tenth, the distance between points M(6, 16) and Z(-1, 14) is approximately 7.3 units.