he water level of a river is below normal levels. Its water level is at 1 1/2 meters below sea level. During the summer, the river drops another 2 1/3 meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer.(1 point)
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didnt work
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still wrong
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who deleted like half the answers on this question i am sure there were about 53 answers on here the night before
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hey bot
@someone
To find the water level at the end of summer, we need to add the initial drop of 1 1/2 meters below sea level to the additional drop of 2 1/3 meters below sea level.
To add these fractions, we need to find a common denominator. The common denominator for 2 and 3 is 6.
1 1/2 meters below sea level is equivalent to (6/6)(1 1/2) = 9/6 - 3/2 = 3/2 meters below sea level.
2 1/3 meters below sea level is equivalent to (6/6)(2 1/3) = 10/6 - 2/6 = 8/6 meters below sea level.
Adding 3/2 meters below sea level and 8/6 meters below sea level gives us a water level of (3/2 + 8/6) meters below sea level.
To add these fractions, we need to find a common denominator. The common denominator for 2 and 6 is 6.
(3/2 + 8/6) meters below sea level is equivalent to (9/6 + 8/6) meters below sea level = 17/6 meters below sea level.
Therefore, the water level at the end of summer is 17/6 meters below sea level.
I apologize for the incorrect calculation. Let's try it again.
The initial water level is 1 1/2 meters below sea level, which can be written as -1 1/2 meters.
The additional drop during the summer is 2 1/3 meters below sea level, which can be written as -2 1/3 meters.
To find the total drop, we need to add -1 1/2 meters and -2 1/3 meters.
-1 1/2 meters + -2 1/3 meters = -3/2 - 7/3 meters (finding a common denominator)
= (-9/6) - (14/6) meters
= -23/6 meters
Therefore, the water level at the end of summer is -23/6 meters below sea level.
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I apologize for the confusion. Let's try another approach.
The initial water level is 1 1/2 meters below sea level, which can be written as -1 1/2 meters.
The additional drop during the summer is 2 1/3 meters below sea level, which can be written as -2 1/3 meters.
To find the total drop, we need to add -1 1/2 meters and -2 1/3 meters.
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6.
Converting the fractions to have a denominator of 6:
-1 1/2 meters below sea level is equivalent to -3/2 meters below sea level (since 1 1/2 = 3/2).
-2 1/3 meters below sea level is equivalent to -7/3 meters below sea level.
Now, let's add the fractions:
-3/2 + (-7/3) = -9/6 + (-14/6) = -23/6
Therefore, the water level at the end of summer is -23/6 meters below sea level.