This is for my daughter.
find the product of
x^2 -4/5 X x + 2/x - 2
could you please show us the work so we can try to understand how it works?
[(x^2-4)/5] * (x+2)/(x-2) ??? maybe???
(x+2)(x-2)/5 * (x+2)/(x-2)
(x+2)^2 /5
or
(x^2 + 4 x + 4)/5
Use parentheses to make things easier.
[(x^2)-(4x/5)]*[(2/x)-2]
[(x^2)*5/5-(4x/5)]*[(2/x)-2*x/x)
(5x^2-4x) * (2-2x)
--------- ----
5 * x
Multiply through to get:
10x^3+18x^2-8x
--------------
5x
4(4x-1)(x-2)=0
(7f6)(-3tc-3)
what is 27-5x<3(4x+5)
Of course! To find the product of the given expression, we need to multiply all the terms together. Let's break it down step by step:
Given expression: \(x^2 - \frac{4}{5}x \times x + \frac{2}{x} - 2\)
Step 1: Multiply the terms \(x^2\) and \(- \frac{4}{5}x\).
To multiply these terms, we can multiply the coefficients (numbers) and add the exponents of the variable \(x\):
\(x^2 \times (- \frac{4}{5}x) = - \frac{4}{5}x^3\)
Step 2: Multiply \(- \frac{4}{5}x\) and \(x\).
Again, multiply the coefficients and add the exponents of \(x\):
\((- \frac{4}{5}x) \times x = - \frac{4}{5}x^2\)
Step 3: Multiply \(- \frac{4}{5}x\) and \(\frac{2}{x}\).
In this step, we need to simplify first by canceling out a factor of \(x\) in the numerator and the denominator:
\((- \frac{4}{5}x) \times \frac{2}{x} = (- \frac{4}{5}) \times 2 = - \frac{8}{5}\)
Step 4: Multiply \(- \frac{4}{5}x\) and \(-2\).
Multiply the coefficients:
\((- \frac{4}{5}x) \times (-2) = \frac{8}{5}x\)
Step 5: Combine all the terms.
Now, combine all the simplified terms from Steps 1-4:
\(x^2 - \frac{4}{5}x \times x + \frac{2}{x} - 2 = - \frac{4}{5}x^3 - \frac{4}{5}x^2 - \frac{8}{5} + \frac{8}{5}x\)
This is the product of the given expression: \(- \frac{4}{5}x^3 - \frac{4}{5}x^2 - \frac{8}{5} + \frac{8}{5}x\).