Evaluating
12. Construct a cohesive paragraph that supports or rejects the claim that flooding has a negative effect on an ecosystem. In the paragraph, consider the quality of evidence and limitations. Ensure your argument is supported by evidence and reasoning and that language and text features are appropriate for a council report.
Flooding is a natural phenomenon that can have significant impacts on an ecosystem. While some may argue that flooding can create new habitats or add nutrients to the soil, the negative effects cannot be ignored. In areas where flooding occurs frequently, the soil can become waterlogged, leading to a loss of oxygen and the suffocation of plant roots. This, in turn, can have a serious impact on the food chain and biodiversity of the area. Additionally, flooding can cause erosion and sedimentation, leading to changes in water quality and the loss of valuable fish and wildlife habitats. It is important to note, however, that the severity of the negative effects can depend on a variety of factors, including the frequency, duration, and intensity of the flooding. Furthermore, the implementation of effective management strategies, such as the construction of levees or the restoration of wetlands, can help mitigate the negative impacts of flooding on ecosystems. Overall, while it is important to recognize the potential benefits of flooding, it is essential to take into account the potential negative impacts and implement management strategies accordingly.
13. Examine how proposed plan to restore the Caboolture River health may impact on society and explore ethical, environmental, social, and economic considerations. Construct a cohesive paragraph summarising this information.
The proposed plan to restore the Caboolture River health has the potential to impact society in various ways. From an ethical standpoint, restoring the river health is the responsible and right thing to do as it will prevent further degradation of the environment. From an environmental perspective, the restoration can improve water quality, increase biodiversity, and create new habitats. Socially, the restoration can provide recreational opportunities and promote community engagement with the natural environment. However, some economic considerations may include the costs of implementation and potential economic losses incurred by the fishing industry. Additionally, the plan may create job opportunities in the restoration sector and provide an economic boost to the surrounding tourism industry. Overall, the proposed plan to restore the Caboolture River health may have both positive and negative impacts on society and requires careful consideration of ethical, environmental, social and economic factors.
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Your teacher surveyed the class to determine the number of hours that each student spent on social media. Your teacher created a table and scatterplot graph that displayed the number of hours and the average final grade based on the hours. The trend line (equation) for the data is y=−7.2x+98.9. Interpret the slope. How many points does the average final grade decrease for 1 hour on social media?(1 point)
The slope of the trend line is -7.2. The negative slope indicates a negative correlation between the number of hours spent on social media and the average final grade. For every one-hour increase in time spent on social media, the average final grade decreases by 7.2 points.
Your teacher surveyed the class to determine the number of hours that each student spent on social media. Your teacher created a table and scatterplot graph that displayed the number of hours and the average final grade based on the hours. The trend line (equation) for the data is y=−7.2x+98.9. Interpret the y-intercept. What is the average grade if a student was on social media for 0 hours?(1 point)
The y-intercept of the trend line is 98.9. This means that if a student spent 0 hours on social media, then the average final grade is predicted to be 98.9.
Your company asked you to analyze the investment of their advertising campaign. You create a scatterplot graph of the advertising dollars spent on advertising, x, and compare it to the revenue generated, y, for January to December of the campaign. You find the equation of the trend line to be y=2.53x+43. Predict the revenue generated if your company invests $200.00 in advertising. Write the revenue in dollars and cents.
Using the equation of the trend line, y = 2.53x + 43, we can predict the revenue generated for an advertising investment of $200.
Substitute x = 200 into the equation:
y = 2.53(200) + 43
y = 506 + 43
y = 549
Therefore, if the company invests $200.00 in advertising, the predicted revenue generated is $549.00.
You work for a manufacturing company on a production line that manufactures cell phones. You are paid $30 a day plus $0.75 for each phone that you assemble. Predict your wages if you assemble 100 phone in one day, using the equation of the trend line y=0.75x+30, where x is the number of phones assembled in one day and y is the total wages. Write your wages in dollars and cents.
Using the equation of the trend line, y = 0.75x + 30, we can predict the total wages earned for assembling 100 phones.
Substitute x = 100 into the equation:
y = 0.75(100) + 30
y = 75 + 30
y = 105
Therefore, if you assemble 100 phones in one day, your predicted wages are $105.00.
You work for a manufacturing company on a production line that manufactures cell phones. You are paid $20 a day plus $1.50 for each phone that you assemble. Interpret the slope and y-intercept of the equation of the trend line y=1.50x+20
The slope of the equation of the trend line, y = 1.50x + 20, is 1.50. This means that for every additional phone assembled, the total wages earned increase by $1.50.
The y-intercept of the equation of the trend line is 20. This means that even if no phones are assembled, the worker still earns $20. This $20 may represent a base pay that the worker earns regardless of the number of phones assembled.
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An illustration shows the first quadrant of a coordinate plane titled Population of a City Since 1900.
The x-axis shows years since 1900 and ranges from 0 to 80 in increments of 10. The y-axis shows population per thousand and ranges from 0 to 80 in increments of 5. Nine points are plotted on the graph. The points are plotted at approximate coordinates left parenthesis 0 comma 20 right parenthesis, left parenthesis 10 comma 28 right parenthesis, left parenthesis 20 comma 30 right parenthesis, left parenthesis 30 comma 35 right parenthesis, left parenthesis 40 comma 47 right parenthesis, left parenthesis 50 comma 55 right parenthesis, left parenthesis 60 comma 57 right parenthesis, left parenthesis 70 comma 68 right parenthesis, and left parenthesis 80 comma 66 right parenthesis. An upward slanting line starts at left parenthesis 0 comma 20 right parenthesis and continues to left parenthesis 60 comma 57 right parenthesis.
The population growth of a city since 1900 is represented by a linear model. Interpret the slope and the y-intercept. Estimate the slope to the nearest hundredth.
(1 point)
Responses
For every year since 1900, the population grew 1.59 thousand. in 1900, the population was 20 thousand.
For every year since 1900, the population grew 1.59 thousand. in 1900, the population was 20 thousand.
For every year since 1900, the population grew 0.63 thousand. In 1900, the population was 20 thousand.
For every year since 1900, the population grew 0.63 thousand. In 1900, the population was 20 thousand.
For every year since 1900, the population grew 0.03 thousand.
For every year since 1900, the population grew 0.03 thousand.
For every 0.63 of a year since 1900, the population grew 1,000. In 1900, the population was 20 thousand.
For every 0.63 of a year since 1900, the population grew 1,000. In 1900, the population was 20 thousand.
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The slope of the linear model is approximately 0.63. This means that for every year since 1900, the population of the city grew by 0.63 thousand per thousand people.
The y-intercept of the linear model is 20. This means that in the year 1900, the population of the city was 20 thousand.
Your teacher surveyed the class to determine the number of hours that each student spent on social media. Your teacher created a table and scatterplot graph that displayed the number of hours, x, and the average final grade percentage, y, based on the hours. Using the equation of the trend line of the data, y=–7.2x+98.9, predict the average final grade percentage, to the nearest whole number, if a student spent 10 hours on social media.(1 point)
Responses
A) The average final grade is 99% if a student spent 10 hours on social media.
B) The average final grade is 92% if a student spent 10 hours on social media.
C)The average final grade is 27% if a student spent 10 hours on social media.
D) The average final grade is 7.2 if a student spent 10 hours on social media.
Using the equation of the trend line, y = -7.2x + 98.9, we can predict the average final grade percentage for a student who spent 10 hours on social media.
Substitute x = 10 into the equation:
y = -7.2(10) + 98.9
y = -72 + 98.9
y = 26.9
Rounding to the nearest whole number, the predicted average final grade percentage for a student who spent 10 hours on social media is 27%.
Therefore, the correct option is C) The average final grade is 27% if a student spent 10 hours on social media.
You are snow skiing down a mountain that is represented by the linear model y=–30x+6,000, where y is the number of feet after x seconds. Predict your elevation level in feet if you ski 60 seconds. (1 point)
Responses
A) After 60 seconds of skiing, you will be 7,800 feet high.
B) After 60 seconds of skiing, you will be 5,820 feet high.
C) After 60 seconds of skiing, you will be 6,030 feet high.
D) After 60 seconds of skiing, you will be 4,200 feet high.
Using the equation of the linear model, y = -30x + 6,000, we can predict the elevation level in feet for skiing 60 seconds.
Substitute x = 60 into the equation:
y = -30(60) + 6,000
y = -1,800 + 6,000
y = 4,200
Therefore, after 60 seconds of skiing, you will be at an elevation of 4,200 feet high.
Hence, the correct answer is D) After 60 seconds of skiing, you will be 4,200 feet high.