in parallelogram abcd, diagonals ac and bd intersect at e. AE=3x-4, and EC=x+12.
what is the value of x?
i believe that x=8. i set them as equal and i minus x from 3x and 4 from 12. is this right?
To find the value of x in the given parallelogram, you need to use the fact that diagonals of a parallelogram bisect each other.
Since AE = EC, we can set up an equation:
3x - 4 = x + 12
To solve this equation, you need to isolate the variable x on one side.
First, let's simplify the equation by combining like terms:
3x - x = 12 + 4
Simplifying further:
2x = 16
Now divide both sides of the equation by 2:
(2x)/2 = 16/2
This simplifies to:
x = 8
So you are correct. The value of x in this case is indeed 8. Your method of setting the two expressions equal to each other and solving for x was correct.