Given the following dataset, what are the extremes?
58, 32, 8, 25, 13, 12, 3, 11, 22, 10(1 point)
The lowest extreme is 3 and the highest extreme is 58.
The amounts of rainfall measured in inches in downtown Los Angeles during the six rainy seasons from 2000 to 2006 are given as a dataset.
15.56, 4.16, 10.38, 8.61, 26.51, 10.89
Find the range of this dataset.
(1 point)
The average temperatures in December in Washington, D.C., from 1993 to 1998 are given as a dataset.
38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.
To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).
To find Q1:
1. Put the data in order from least to greatest:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
2. Find the median of the lower half of the data:
35.6, 38.1, 41.0
Median = 38.1
Q1 = 38.1
To find Q3:
1. Put the data in order from least to greatest:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
2. Find the median of the upper half of the data:
43.0, 44.2, 44.4
Median = 44.2
Q3 = 44.2
Now that we know Q1 and Q3, we can find the IQR:
IQR = Q3 - Q1
IQR = 44.2 - 38.1
IQR = 6.1
Therefore, the interquartile range of the dataset is 6.1.
Identify the first quartile in the following dataset:
5, 7, 9, 4, 3, 2, 1, 0, 11, 12, 6, 3, 4, 3, 2, 6(1 point)
Responses
6.5
6.5
2.5
2.5
4
4
0
0
To find the first quartile, we need to arrange the data in order from lowest to highest:
0, 1, 2, 2, 3, 3, 3, 4, 4, 5, 6, 6, 7, 9, 11, 12
There are different methods for finding the first quartile, but one common way is to take the median of the lower half of the data. In this case, the lower half consists of:
0, 1, 2, 2, 3, 3, 3, 4
The median of this lower half is (2+3)/2 = 2.5.
Therefore, the first quartile is 2.5.
Identify the third quartile in the following dataset:
53.3, 46.9, 48.1, 49.7, 52.1, 47.5, 47.2, 45.5(1 point)
Responses
53.3
53.3
47.8
47.8
47.05
47.05
50.9
50.9
To find the third quartile, we need to arrange the data in order from lowest to highest:
45.5, 46.9, 47.2, 47.5, 48.1, 49.7, 52.1, 53.3
There are different methods for finding the third quartile, but one common way is to take the median of the upper half of the data. In this case, the upper half consists of:
48.1, 49.7, 52.1, 53.3
The median of this upper half is (49.7+52.1)/2 = 50.9.
Therefore, the third quartile is 50.9.
Find the range of the given data set.
51, 13, 98, 42, 76, 28
(1 point)
Responses
98
98
85
85
13
13
23
To find the range, we first need to find the highest and lowest values in the dataset.
Highest value = 98
Lowest value = 13
Range = highest value - lowest value
Range = 98 - 13
Range = 85
Therefore, the range of the dataset is 85.
Find the interquartile range of the given dataset.
11, 13, 22, 17, 14, 21, 27, 15
(1 point)
Responses
8
8
21.5
21.5
13.5
13.5
6.5
To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).
To find Q1:
1. Put the data in order from least to greatest:
11, 13, 14, 15, 17, 21, 22, 27
2. Find the median of the lower half of the data:
11, 13, 14, 15
Median = (13+14)/2 = 13.5
Q1 = 13.5
To find Q3:
1. Put the data in order from least to greatest:
11, 13, 14, 15, 17, 21, 22, 27
2. Find the median of the upper half of the data:
21, 22, 27
Median = (22+21)/2 = 21.5
Q3 = 21.5
Now that we know Q1 and Q3, we can find the IQR:
IQR = Q3 - Q1
IQR = 21.5 - 13.5
IQR = 8
Therefore, the interquartile range of the dataset is 8.
The heights in inches of six basketball players at a local high school are given as a dataset.
70, 78, 74, 82, 68, 75
Find the range and the interquartile range of the dataset.
(1 point)
Responses
The range is 14, and the interquartile range is 8.
The range is 14, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.
The range is 14, and the interquartile range is 4.5.
The range is 14, and the interquartile range is 4.5.
The range is 14, and the interquartile range is 74.5.
To find the range, we first need to find the highest and lowest values in the dataset.
Highest value = 82
Lowest value = 68
Range = highest value - lowest value
Range = 82 - 68
Range = 14
To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).
To find Q1:
1. Put the data in order from least to greatest:
68, 70, 74, 75, 78, 82
2. Find the median of the lower half of the data:
68, 70, 74
Median = 70
Q1 = 70
To find Q3:
1. Put the data in order from least to greatest:
68, 70, 74, 75, 78, 82
2. Find the median of the upper half of the data:
75, 78, 82
Median = 78
Q3 = 78
Now that we know Q1 and Q3, we can find the IQR:
IQR = Q3 - Q1
IQR = 78 - 70
IQR = 8
Therefore, the range of the dataset is 14 and the interquartile range is 8.
Given the following dataset, what is the first quartile? Round to the nearest tenth if necessary.
42, 82, 67, 34, 54, 62, 17, 47, 56, 18, 20
To find the first quartile, we need to arrange the data in order from lowest to highest:
17, 18, 20, 34, 42, 47, 54, 56, 62, 67, 82
There are a couple of methods for finding the first quartile, but one common way is to take the median of the lower half of the data. In this case, the lower half consists of:
17, 18, 20, 34, 42
The median of this lower half is 20.
Therefore, the first quartile is 20.
To find the range, we first need to find the highest and lowest values in the dataset.
Highest value = 26.51
Lowest value = 4.16
Range = highest value - lowest value
Range = 26.51 - 4.16
Range = 22.35
Therefore, the range of the dataset is 22.35 inches.