The last one which you were asking where the b came from I typed the wrong problem sorry.
the problem is 49-a^2b^2
Is the answer: (7+ab)-(7ab)
(7-ab)(7+ab)
the difference of two squares
(sqrt first + sqrt second)(sqrt first - sqrt second)
Check these by multiplying them out.
How about answering your own question.
will I get 49-a^2b^2 if I simplify (7+ab)-(7ab) ??
now try (7 + ab)(7 - ab)
Thank you now I understand how to check them to see if there right. Thanks Damon, and thanks Reiny.
No problem! Let's solve the expression 49 - a^2b^2.
To simplify this expression, we need to remember the formula for the difference of squares, which states that a^2 - b^2 = (a + b)(a - b).
In this case, we have 49 - a^2b^2. Let's see if we can rewrite it in the form of the difference of squares.
49 - a^2b^2 can be rewritten as (7^2) - (ab)^2.
Now, we can see that (7^2) is the square of 7, and (ab)^2 is the square of ab. So we can apply the formula for the difference of squares:
49 - a^2b^2 = (7 + ab)(7 - ab).
Therefore, the answer to the expression 49 - a^2b^2 is (7 + ab)(7 - ab).