The temperatures (in °F) in a city on randomly selected days during the summer are 89, 85, 90, 87, 86, 91, 88, and 89. What is the mean temperature? Round your answer to one decimal place.
I'm sorry about that! Let me try again.
To find the mean temperature, we add up all the temperatures and divide by the total number of temperatures:
89 + 85 + 90 + 87 + 86 + 91 + 88 + 89 = 705
There are 8 temperatures, so we divide the sum by 8:
705 / 8 = 88.125
Rounded to one decimal place, the mean temperature is 88.1°F.
To find the median temperature, we need to first put the temperatures in order from lowest to highest:
-11°, -9°, -9°, -8°, -3°, 1°, 2°
There are seven temperatures, so the median is the middle temperature. In this case, the middle temperature is -8° because it is the fourth temperature in the ordered list.
Therefore, the median low temperature for that week was -8°F.
I'm sorry about that, let me try again.
To find the median age, we need to count the number of ages we have from the stem-and-leaf plot, which is 8. Since there are an even number of ages, the median is the average of the two middle values when sorted in ascending or descending order.
Writing the ages out in ascending order, we have:
28, 31, 32, 34, 42, 47, 49, 54
The two middle values are 34 and 42, so the median age is:
(34 + 42) / 2 = 38
Therefore, the median age is 38 years.
incorrect
The low temperatures during one week in January were 2°, −3°, −9°, −11°, 1°, −8°, and −9°. What was the median low temperature that week?
The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8=28 years
incorrect
Here are the math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?
To find the mean score of each sample, we need to add up all the scores and divide by the number of scores.
For Class 1:
(75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 84
The mean score for Class 1 is 84.
For Class 2:
(83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 83.6
The mean score for Class 2 is 83.6.
Comparing the mean scores, we can see that Class 1 has a higher mean score than Class 2. Therefore, based on the mean, Class 1 generally performed better on the math test.
class 1 is incorrect
Kat and Joshua want to know which pizza shop has the fastest delivery time. Kat took a random sample of 8 delivery times from pizza shop 1 over a period of six months. Joshua did the same for pizza shop 2. The delivery times (in minutes) for each pizza shop are shown in the following table.
Pizza Shop 1 Pizza Shop 2
18 20
23 17
15 16
22 38
21 21
24 20
28 18
20 25
Find the median delivery time for each pizza shop. Based on the median, which pizza shop has the fastest delivery time?
To find the median delivery time for each pizza shop, we need to first order the delivery times from smallest to largest.
For Pizza Shop 1:
15, 18, 20, 21, 22, 23, 24, 28
The median delivery time for Pizza Shop 1 is the middle number, which is 22.5. Since this is an even number of delivery times, we take the average of the two middle numbers, which are 22 and 23.
For Pizza Shop 2:
16, 17, 18, 20, 21, 25, 38
The median delivery time for Pizza Shop 2 is also the middle number, which is 20.
Comparing the medians, Pizza Shop 2 has the faster median delivery time of 20 minutes.
recheck you're answer
The ages, in years, of randomly selected employees are 34, 41, 28, 35, 27, 44, 48, 29, 33, and 39. Determine the mean age.
To find the mean age, we need to add up all the ages and divide by the number of ages:
34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39 = 358
There are 10 ages, so we divide the sum by 10:
358 / 10 = 35.8
Therefore, the mean age is 35.8 years.
For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo. The table shows the data.
Daily High Temperatures (in °F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?
(1 point)
To find the median daily high temperature for each city, we need to first order the temperatures from lowest to highest.
For Dayton:
77, 79, 82, 85, 85, 86, 87, 88, 90, 91
The median daily high temperature for Dayton is the middle temperature, which is 86 degrees.
For Laredo:
79, 80, 81, 82, 84, 86, 87, 88, 88, 92
The median daily high temperature for Laredo is also the middle temperature, which is 86 degrees.
Since both cities have the same median daily high temperature, we conclude that neither city has a higher median daily high temperature.
one has to be higher
I apologize for the confusion in my previous response.
Comparing the two lists:
Dayton: 77, 79, 82, 85, 85, 86, 87, 88, 90, 91
Laredo: 79, 80, 81, 82, 84, 86, 87, 88, 88, 92
We can see that the lower half of the Dayton temperatures (77, 79, 82, 85, 85) is lower than the lower half of the Laredo temperatures (79, 80, 81, 82, 84).
However, all of the remaining values in both lists (86, 87, 88, 90, 91 and 86, 87, 88, 88, 92) are equal.
Therefore, we conclude that Laredo has a higher median daily high temperature, since the median temperature value in Laredo is higher than the median temperature value in Dayton.
To find out how much higher Laredo's median is than Dayton's median, we need to subtract the median temperature value in Dayton from the median temperature value in Laredo:
Median temperature in Laredo - Median temperature in Dayton = 86 - 86 = 0
So Laredo's median daily high temperature is not higher by any amount compared to Dayton's.
which one?
Dayton has a higher median daily high temperature than Laredo by 0.3°F.
Dayton has a higher median daily high temperature than Laredo by , 0.3 degree , F.
Dayton has a higher median daily high temperature than Laredo by 0.5°F.
Dayton has a higher median daily high temperature than Laredo by , 0.5 degree , F.
Laredo has a higher median daily high temperature than Dayton by 1°F.
Laredo has a higher median daily high temperature than Dayton by , 1 degree , F.
Laredo has a higher median daily high temperature than Dayton by 0.5°F.
I apologize for the earlier response, here is another attempt.
To find the median daily high temperature for each city, we first need to order the temperatures from lowest to highest.
For Dayton:
77, 79, 82, 85, 85, 86, 87, 88, 90, 91
The median daily high temperature for Dayton is the middle temperature, which is 86°F.
For Laredo:
79, 80, 81, 82, 84, 86, 87, 88, 88, 92
The median daily high temperature for Laredo is also the middle temperature, which is 86°F.
The medians for both cities are the same, so we can conclude that neither city has a higher median daily high temperature.
Therefore, the correct option is:
Neither city has a higher median daily high temperature.
The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies.
Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25
Which of the following statements is true?
(1 point)
Responses
The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from Company A have a higher mean highway fuel efficiency that Company B.
To determine which of the following statements is true, let's first calculate and compare the measures of central tendency for each company.
For Company A:
Mean = (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 32.625
Median = middle two numbers = (30 + 35) / 2 = 32.5
For Company B:
Mean = (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 31.5
Median = middle two numbers = (33 + 34) / 2 = 33.5
The mode is the most frequent value in the distribution. In this case, Company A has three modes: 35, 30, and 31, each of which appears twice. Company B has two modes: 34 and 27, each of which appears twice.
Comparing the measures of central tendency, we can see that:
- The cars from Company A do not have a higher median highway fuel efficiency than Company B. In fact, Company B has the higher median.
- The cars from both companies do not have the same mean, median, and modal highway fuel efficiency.
- The cars from Company B do not have higher modal highway fuel efficiency than Company A. Company A has more modes than Company B.
- The cars from Company A do not have a higher mean highway fuel efficiency than Company B. Company B has the higher mean.
Therefore, none of the given statements are true, and we cannot draw any clear conclusion based on the measures of central tendency alone.
To find the mean, we add up all the temperatures and divide by the number of temperatures:
(89 + 85 + 90 + 87 + 86 + 91 + 88 + 89) / 8 = 86.5
So the mean temperature is 86.5°F. Rounded to one decimal place, the answer is 86.5°F.
To find the median age, we need to first write out all the ages in order from lowest to highest. From the stem-and-leaf plot, we can see that the ages are:
28, 31, 32, 34, 42, 47, 49, and 54
There are eight ages in total, which means the median is the value in the middle, so we need to find the fourth age:
28, 31, 32, 34, 42, 47, 49, 54
The fourth age is 34, so the median age is 34.
I'm sorry about that, here's another try:
To find the mean score of each sample, we need to add up all the scores and divide by the number of scores:
For Class 1:
(75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 85.6
The mean score for Class 1 is 85.6.
For Class 2:
(83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 83.6
The mean score for Class 2 is 83.6.
Comparing the mean scores, we can see that Class 1 has a higher mean score than Class 2. Therefore, based on the mean, Class 1 generally performed better on the math test.
I apologize for the mistake in my previous response.
To find the median delivery time for each pizza shop, we first order the delivery times from smallest to largest.
For Pizza Shop 1:
15, 18, 20, 21, 22, 23, 24, 28.
Since there are an even number of delivery times, we take the average of the two middle numbers:
median = (22 + 23) / 2 = 22.5
For Pizza Shop 2:
16, 17, 18, 20, 21, 25, 38.
Here, the median is the middle number:
median = 20
Comparing the medians, we see that Pizza Shop 2 has a faster median delivery time of 20 minutes. Therefore, based on the median, Pizza Shop 2 would be the better pick if you are looking for the fastest delivery time.