The number of words Mr. Ahmad’s students read per minute is 109, 89, 112, 98, 101, 105, 120, 106. What is the mean absolute deviation of the dataset? Round the answer to the nearest tenth.(1 point)
Which urban area of Texas was heavily damaged in 1947 when a ship carrying ammonium nitrate fertilizer exploded?
A. Bastrop County
B. Port Arthur
C. San Marcos
D. Texas City
D. Texas City
Which events have had a lasting impact on the Texas economy? Select all that apply.
A. Bolivar
B. Galveston
C. Spindletop
D. Victoria
C. Spindletop
Where in Texas would you go if you wanted to visit the site of Texas' most famous battle and see Spanish missions?
A. Austin
B. San Antonio
C. San Jacinto
D. Goliad
B. San Antonio
What business sector benefited from the Texas real estate boom of the 1970s and 1980s ?
A. agriculture
B. health care
C.transportation
D. banking
D. banking
The number of words Mr. Ahmad’s students read per minute is 109, 89, 112, 98, 101, 105, 120, 106. What is the mean absolute deviation of the dataset? Round the answer to the nearest tenth.(1 point)
We have already solved this problem. The mean absolute deviation of the dataset is 6.9.
that is incorrect
I'm sorry for the error. Let me solve it correctly:
First, calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(109+89+112+98+101+105+120+106) / 8 = 103.5
Next, find the deviation of each number from the mean by subtracting the mean from each number:
|109-103.5| = 5.5
|89-103.5| = 14.5
|112-103.5| = 8.5
|98-103.5| = 5.5
|101-103.5| = 2.5
|105-103.5| = 1.5
|120-103.5| = 16.5
|106-103.5| = 2.5
Then, find the mean of these deviations by adding up all the deviations and dividing by the total number of numbers:
(5.5+14.5+8.5+5.5+2.5+1.5+16.5+2.5) / 8 = 6.5
Finally, round this answer to the nearest tenth:
6.5 rounds to 6.5
Therefore, the mean absolute deviation of the dataset is 6.5.
you are incorrect 109+89+112+98+101+105+120+106) / 8= 105
You are correct, I apologize for the oversight. Let me correct the rest of the calculations based on the correct mean:
First, calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(109+89+112+98+101+105+120+106) / 8 = 105
Next, find the deviation of each number from the mean by subtracting the mean from each number:
|109-105| = 4
|89-105| = 16
|112-105| = 7
|98-105| = 7
|101-105| = 4
|105-105| = 0
|120-105| = 15
|106-105| = 1
Then, find the mean of these deviations by adding up all the deviations and dividing by the total number of numbers:
(4+16+7+7+4+0+15+1) / 8 = 6.875
Finally, round this answer to the nearest tenth:
6.875 rounds to 6.9
Therefore, the mean absolute deviation of the dataset is 6.9.
The table lists Jude’s data for how many people walk into a store each half hour. The mean is 22.3. Identify the absolute deviation for each missing value. Round each value to the nearest tenth.
(1 point)
Data Point Absolute Deviation
5 17.3
10 12.3
45
12 10.3
27
35 12.7
To find the absolute deviation for each missing value, we need to find the distance of each missing value from the mean, or the absolute difference between the missing value and the mean.
- The absolute deviation for the missing value of 45 is: |45 - 22.3| = 22.7
- The absolute deviation for the missing value of 27 is: |27 - 22.3| = 4.7
Therefore, the completed table with the absolute deviation for each data point would be:
Data Point | Absolute Deviation
--- | ---
5 | 17.3
10 | 12.3
45 | 22.7
12 | 10.3
27 | 4.7
35 | 12.7
Leon counts the number of bugs he finds on his tomato plants each day and collects the following data: 18, 24, 15, 9, 10. The mean is 15.2. What is the final equation that he would use in determining the mean absolute deviation? Round each value to the nearest tenth.(2 points)
÷ =
To determine the mean absolute deviation, we need to find the absolute deviation of each data point from the mean by taking the absolute value of the difference between each data point and the mean, then find the mean of those absolute deviations.
Here is the final equation that Leon would use in determining the mean absolute deviation:
(Mean Absolute Deviation) = (|18 - 15.2| + |24 - 15.2| + |15 - 15.2| + |9 - 15.2| + |10 - 15.2|) / 5
Simplifying this expression gives:
(Mean Absolute Deviation) = (2.8 + 8.8 + 0.2 + 6.2 + 5.2) / 5
(Mean Absolute Deviation) = 23.2 / 5
(Mean Absolute Deviation) = 4.64 (rounded to the nearest tenth)
Therefore, the final equation that Leon would use in determining the mean absolute deviation is:
(Mean Absolute Deviation) = (|Data Point - Mean|) / Number of Data Points
What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.(1 point)
To find the sum of the absolute deviations, we need to find the absolute deviation of each data point from the mean by taking the absolute value of the difference between each data point and the mean, then add up those absolute deviations.
Here are the steps to solve the problem:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(63+25+74+52+63+12+46) / 7 = 47.9
2. Find the deviation of each number from the mean by subtracting the mean from each number:
|63-47.9| = 15.1
|25-47.9| = 22.9
|74-47.9| = 26.1
|52-47.9| = 4.1
|63-47.9| = 15.1
|12-47.9| = 35.9
|46-47.9| = 1.9
3. Find the sum of these absolute deviations by adding up all the deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 121.1
4. Round the answer to the nearest tenth:
121.1 rounds to 121.1
Therefore, the sum of the absolute deviations in the dataset is 121.1.
Find the mean absolute deviation of the following dataset: 8.4, 9.4, 14.2, 5.6, 8.3, 9.0, 10.2. Round the answer to the nearest tenth.(1 point)
Here are the steps to find the mean absolute deviation of the dataset:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(8.4+9.4+14.2+5.6+8.3+9.0+10.2) / 7 = 9.5
2. Find the deviation of each number from the mean by subtracting the mean from each number:
|8.4 - 9.5| = 1.1
|9.4 - 9.5| = 0.1
|14.2 - 9.5| = 4.7
|5.6 - 9.5| = 3.9
|8.3 - 9.5| = 1.2
|9.0 - 9.5| = 0.5
|10.2 - 9.5| = 0.7
3. Find the mean of these deviations by adding up all the deviations and dividing by the total number of numbers:
(1.1 + 0.1 + 4.7 + 3.9 + 1.2 + 0.5 + 0.7) / 7 = 1.8 / 7
4. Round the answer to the nearest tenth:
0.2571 rounds to 0.3
Therefore, the mean absolute deviation of the dataset is 0.3.
(8.4+9.4+14.2+5.6+8.3+9.0+10.2) / 7 = 9.3
I apologize for the error. You are correct that the mean of the dataset is 9.3, not 9.5.
Therefore, the mean absolute deviation of the dataset would be:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(8.4+9.4+14.2+5.6+8.3+9.0+10.2) / 7 = 9.3
2. Find the deviation of each number from the mean by subtracting the mean from each number:
|8.4 - 9.3| = 0.9
|9.4 - 9.3| = 0.1
|14.2 - 9.3| = 4.9
|5.6 - 9.3| = 3.7
|8.3 - 9.3| = 1.0
|9.0 - 9.3| = 0.3
|10.2 - 9.3| = 0.9
3. Find the mean of these deviations by adding up all the deviations and dividing by the total number of numbers:
(0.9 + 0.1 + 4.9 + 3.7 + 1 + 0.3 + 0.9) / 7 = 12.8 / 7
4. Round the answer to the nearest tenth:
1.8286 rounds to 1.8
Therefore, the mean absolute deviation of the dataset is 1.8.
you are incorrect (0.9 + 0.1 + 4.9 + 3.7 + 1 + 0.3 + 0.9) =11.8
I apologize for the mistake. You are correct. The sum of the absolute deviation must be calculated without dividing by the number of observations.
Here are the revised steps to calculate the mean absolute deviation:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(8.4+9.4+14.2+5.6+8.3+9.0+10.2) / 7 = 9.3
2. Find the deviation of each number from the mean by subtracting the mean from each number:
|8.4 - 9.3| = 0.9
|9.4 - 9.3| = 0.1
|14.2 - 9.3| = 4.9
|5.6 - 9.3| = 3.7
|8.3 - 9.3| = 1.0
|9.0 - 9.3| = 0.3
|10.2 - 9.3| = 0.9
3. Find the sum of these deviations by adding up all the deviations:
0.9 + 0.1 + 4.9 + 3.7 + 1 + 0.3 + 0.9 = 11.8
4. Calculate the mean absolute deviation by dividing the sum of the deviations by the total number of observations (in this case, 7):
Mean Absolute Deviation = 11.8 / 7
5. Round the answer to the nearest tenth:
Mean Absolute Deviation = 1.7 (rounded to the nearest tenth)
Therefore, the mean absolute deviation of the dataset is 1.7.
The number of visitors to a museum per hour recorded in one day is 106, 122, 134, 150, 120, 92, 75. What is the mean absolute deviation for this dataset? Round the answer to the nearest tenth.(1 point)
Here are the steps to find the mean absolute deviation of the dataset:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(106+122+134+150+120+92+75) / 7 = 113.29 (rounded to two decimal places)
2. Find the deviation of each number from the mean by subtracting the mean from each number, and taking the absolute value of the result:
|106 - 113.29| = 7.29
|122 - 113.29| = 8.71
|134 - 113.29| = 20.71
|150 - 113.29| = 36.71
|120 - 113.29| = 6.71
|92 - 113.29| = 21.29
|75 - 113.29| = 38.29
3. Find the mean of these absolute deviations by adding up all the deviations and dividing by the total number of numbers:
(7.29 + 8.71 + 20.71 + 36.71 + 6.71 + 21.29 + 38.29) / 7 = 139.91 / 7
4. Round the answer to the nearest tenth:
Mean Absolute Deviation = 19.99 (rounded to the nearest tenth)
Therefore, the mean absolute deviation of the dataset is 19.99.
am I incorrect in thinking that(106+122+134+150+120+92+75) / 7 = 114.1(rounded to tenths) so your incorrect
I apologize for the calculation error. You are correct that the mean of the dataset is 114.1, rounded to the nearest tenth.
With this correction, the revised steps to find the mean absolute deviation of the dataset are:
1. Calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(106+122+134+150+120+92+75) / 7 = 114.1 (rounded to one decimal place)
2. Find the deviation of each number from the mean by subtracting the mean from each number, and taking the absolute value of the result:
|106 - 114.1| = 8.1
|122 - 114.1| = 7.9
|134 - 114.1| = 19.9
|150 - 114.1| = 35.9
|120 - 114.1| = 5.9
|92 - 114.1| = 22.1
|75 - 114.1| = 39.1
3. Find the mean of these absolute deviations by adding up all the deviations and dividing by the total
A dataset includes the point 34.6. The mean of the set is 32.1. What is the absolute deviation for this data point? Round the answer to the nearest tenth.(1 point)
First, calculate the mean of the dataset by adding up all the numbers and dividing by the total number of numbers:
(109+89+112+98+101+105+120+106) / 8 = 103.5
Next, find the deviation of each number from the mean by subtracting the mean from each number:
|109-103.5| = 5.5
|89-103.5| = 14.5
|112-103.5| = 8.5
|98-103.5| = 5.5
|101-103.5| = 2.5
|105-103.5| = 1.5
|120-103.5| = 16.5
|106-103.5| = 2.5
Then, find the mean of these deviations by adding up all the deviations and dividing by the total number of numbers:
(5.5+14.5+8.5+5.5+2.5+1.5+16.5+2.5) / 8 = 6.875
Finally, round this answer to the nearest tenth:
6.875 rounds to 6.9
Therefore, the mean absolute deviation of the dataset is 6.9.