Arrange the expressions below in order from least to greatest. Place the least at the top and greatest at the bottom.
(72÷8)−2×3+1
72÷(8−2)×3+1
72÷(8−2)×(3+1)
72÷8−2×(3+1)
72÷8−2×(3+1) < (72÷8)−2×3+1 < 72÷(8−2)×3+1 < 72÷(8−2)×(3+1)
Simplified:
9 - 8 < 7 < 54 < 18
can you do it from top to bottom with the least being at the top and the greatest being at the bottom?
Sure! Here are the expressions arranged from least to greatest:
(72÷8)−2×3+1
72÷(8−2)×3+1
72÷(8−2)×(3+1)
72÷8−2×(3+1)
Drag the operation signs to make the equation true. An operation may be used once. more than once, or not at all
+−×÷
12
(
7
−
4
)
+
5
3 = 19
(7 ÷ 4) + 5 × 3 = 19
can you use the numbers but add math symbols and use pemdas?
Sure! Here's one possible solution using PEMDAS:
12 ÷ (7 - 4) + 5 × 3 = 4 + 15 = 19
Note that we first perform the subtraction inside the parentheses (7 - 4), then the division (12 ÷ 3), then the multiplication (5 × 3), and finally the addition (4 + 15) from left to right to get the result of 19.
Select all of the expressions that are equal to
8
×
35
.
A.
8
×
(
30
+
5
)
B.
5
+
3
×
35
C.
(
8
×
30
)
+
(
8
×
5
)
D.
(
8
+
30
)
×
(
8
+
5
)
E.
8
×
(
20
+
15
)
A. 8 × (30 + 5) = 8 × 35 = 280
B. 5 + 3 × 35 = 5 + 105 = 110 (not equal to 8 × 35)
C. (8 × 30) + (8 × 5) = 240 + 40 = 280
D. (8 + 30) × (8 + 5) = 38 × 13 = 494 (not equal to 8 × 35)
E. 8 × (20 + 15) = 8 × 35 = 280
Therefore, the expressions that are equal to 8 × 35 are A, C, and E.
Phillipa rode her bicycle every day over the weekend. Phillipa rode
[
(
13
.
5
+
8
.
5
)
÷
2
]
miles on Friday,
[
18
−
(
2
×
4
)
]
miles on Saturday and
[
20
−
(
5
−
3
)
]
miles on Sunday.
On which day did Phillipa ride her bicycle the most?
She rode her bicycle the most on
First, we need to simplify the distances Phillipa rode on each day:
- Friday: ([13.5 + 8.5] ÷ 2) miles = 11 miles
- Saturday: (18 − [2 × 4]) miles = 10 miles
- Sunday: (20 − [5 − 3]) miles = 18 miles
Therefore, Phillipa rode her bicycle the most on Sunday, when she rode 18 miles.
Evan and Peter have a radio show which consists of 2 segments. They need 4 less than 11 songs in the first segment. In the second segment, they need 5 less than 3 times the number of songs in the first segment.
Part A
Write an expression for the total number of songs they need for their show.
A.
(
11
−
4
)
+
3
×
11
−
4
−
5
B.
(
11
−
4
)
+
3
×
(
11
−
4
)
−
5
C.
(
11
−
4
)
+
3
−
4
×
11
−
5
D.
(
11
−
4
)
+
3
−
5
×
(
11
−
4
)
The expression for the total number of songs they need is the sum of the number of songs in the first and second segments:
Let x be the number of songs needed in the first segment.
Then, the number of songs needed in the second segment is 3x - 5.
The total number of songs needed is:
x + (3x - 5) = 4x - 5
Simplifying:
4x - 5 = (11 - 4) + 3(11 - 4) - 5
4x - 5 = 7 + 3(7) - 5
4x - 5 = 16
4x = 21
x = 5.25
We can't have a fractional number of songs, so we'll round up to the nearest whole number: x = 6.
Therefore, the total number of songs they need for their show is:
4x - 5 = (4 × 6) - 5 = 24 - 5 = 19
Answer: A. (11 - 4) + 3×11 - 4 - 5
Evaluate the expression.
A.
39 songs
B.
31 songs
C.
25 songs
D.
23 songs
We don't have the expression to evaluate in the question. Please provide the expression.
expression:(
11
−
4
)
+
3
×
11
−
4
−
5
Using the order of operations (PEMDAS), we perform the multiplication first, then the addition and subtraction from left to right:
(11 - 4) + 3 × 11 - 4 - 5
= 7 + 33 - 4 - 5
= 26
Therefore, the value of the expression is 26.
Answer: There are no options to select from as none of the given options is equal to 26.
use pemdas pls
Using PEMDAS, we perform the multiplication first, then the addition and subtraction from left to right:
(11 - 4) + 3 × (11 - 4) - 5
= 7 + 3 × 7 - 5
= 7 + 21 - 5
= 23
Therefore, the value of the expression is 23.
Answer: D. 23 songs