which of the following sample spaces correctly lists all the possible outcomes for flipping a coin and spinning a four-colored spinner (red, blue, green, and yellow)?
A. h-red, h-blue, h-green, h-yellow, t-yellow, i-green, t-blue, t-red
B. h-red, t-red, h-blue, t-blue, h-green, i-yellow
C. t-vellow, h-red, t-blue, h-green, t-green, h-yellow, i-red
D. h-red, t-blue, h-green, t-yellow
The correct answer is option A: h-red, h-blue, h-green, h-yellow, t-yellow, i-green, t-blue, t-red. This correctly lists all the possible outcomes of flipping a coin (heads or tails) and spinning a four-colored spinner (red, blue, green, or yellow).
how many different lunch combinations can be made from two sandwich choices, three side item choices, and three beverage choices if you choose one sandwich, one side, and one beverage?
A. 8
B. 9
C. 18
D.11
The answer is C. 18.
You have 2 choices for the sandwich, 3 choices for the side item, and 3 choices for the beverage. To find the total number of lunch combinations, you multiply the number of options for each category:
2 (sandwich choices) × 3 (side item choices) × 3 (beverage choices) = 18
Therefore, there are 18 different lunch combinations that can be made.
a number cube is rolled. what is p(3 or an even number)?
A. 1/2
B. 2/3
C. 4/2
D. 1/6
The answer is B. 2/3.
To find the probability of rolling a 3 or an even number on a number cube, you need to add the probability of rolling a 3 and the probability of rolling an even number (2, 4, or 6). However, you need to make sure that you are not counting the number 6 twice (since it is both even and a multiple of 3).
The probability of rolling a 3 is 1/6.
The probability of rolling an even number is 3/6 (since there are three even numbers out of six total numbers on the cube). However, we need to subtract the probability of rolling a 6, since it is both even and a multiple of 3. The probability of rolling a 6 is 1/6, so the probability of rolling an even number that is not 6 is 2/6.
Therefore, the probability of rolling a 3 or an even number is:
P(3 or even) = P(3) + P(even) - P(3 and even)
P(3 or even) = 1/6 + 2/6 - 1/6
P(3 or even) = 2/6 or 1/3
This can be simplified to 2/3. Therefore, the answer is B.
which of the following is a certain event?
A certain event is an event that will always happen, with probability 1. In other words, it is guaranteed to occur.
Out of the list of options you did not provide, but an example of a certain event is:
- Rolling a standard six-sided die and getting a number between 1 and 6.
This is a certain event because it is impossible to roll a number that is not between 1 and 6 on a standard six-sided die.
which of the following is a certain event?
A. rolling a composite number on a number cube
B. rolling a number greater than 1 on a number cube
C. rolling an odd or even number on a number cube
D. rolling an odd or even number greater than 7
The answer is B. rolling a number greater than 1 on a number cube.
A certain event is an event that will always happen, with probability 1. Rolling a number greater than 1 on a standard six-sided die is a certain event, since all of the numbers on the die are greater than 1.
Rolling a composite number (option A) is not a certain event, since half of the numbers on the die (2 and 3) are prime and the other half are composite.
Rolling an odd or even number (option C) is not a certain event either, since it is possible to roll a number that is neither odd nor even (such as 1).
Rolling an odd or even number greater than 7 (option D) is impossible, since the largest number on a standard six-sided die is 6, which is not greater than 7.
a class has 9 girls and 12 boys. what is the probability of a teacher randomly calling on a boy?
A. 3/4
B. 4/7
C. 3/7
D. 4/3
The answer is B. 4/7.
There are a total of 21 students in the class (9 girls and 12 boys). If the teacher randomly calls on a student, there is an equal chance of picking any of the 21 students.
The probability of calling on a boy is the number of boys divided by the total number of students:
P(boy) = number of boys / total number of students
P(boy) = 12 / 21
To simplify this fraction, you can divide both the numerator and denominator by 3 (since 3 is a common factor of both):
P(boy) = (12/3) / (21/3)
P(boy) = 4/7
Therefore, the probability of the teacher calling on a boy is 4/7.
a jar contains 5 green erasers, 2 striped erasers, 4 pink erasers, and 3 white erasers. you select an eraser at random. what is p(not pink)?
A. 4/14
B. 2/5
C. 5/7
D. 1/7
There are a total of 5 + 2 + 4 + 3 = 14 erasers in the jar.
The probability of selecting a pink eraser is 4/14, since there are 4 pink erasers out of 14 total erasers.
To find the probability of not selecting a pink eraser, you can subtract the probability of selecting a pink eraser from 1 (since the probabilities of all possible events must add up to 1):
P(not pink) = 1 - P(pink)
P(not pink) = 1 - 4/14
P(not pink) = 10/14
This fraction can be simplified by dividing both the numerator and denominator by 2:
P(not pink) = (10/2) / (14/2)
P(not pink) = 5/7
Therefore, the probability of selecting an eraser that is not pink is 5/7.
The answer is C. 5/7.
on the spinner, what is the probability of spinning a number greater than 2?
A. 1/2
B. 5/8
C. 3/8
D. 1/4
We cannot provide the answer without knowing what the spinner looks like or how many sections it has. Please provide more information or a visual representation of the spinner.
The spinner has the numbers of 1,4,3,2,5,6,2, and 3
There are eight numbers on the spinner, and only three of them are less than or equal to 2 (namely, 1, 2, and 2). Therefore, the probability of spinning a number greater than 2 is 5/8, since there are five numbers (4, 3, 5, 6, and 3) that are greater than 2 out of a total of eight possible outcomes:
P(number greater than 2) = 5/8
Therefore, the answer is B. 5/8.
you write each letter of the word mathematician on a piece of paper and put them in a bag. you randomly select one piece from the bag. what is p(t or a)?
A. 5/13
B. 5/8
C.1/3
D. 8/13
The word "mathematician" has 13 letters.
To calculate the probability of selecting a T or an A, you need to count the number of T's and A's in the word, and divide by the total number of letters:
- There are a total of 2 T's and 2 A's in the word "mathematician".
- However, the letter "A" appears twice, so we need to make sure not to count it twice.
- Therefore, the total number of letters that are either T or A is 2 + 1 = 3.
- The probability of selecting a T or an A is therefore 3/13.
Therefore, the answer is not one of the options provided. The closest option is A. 5/13, but this is not the correct answer since there are only 3 letters out of 13 that are either T or A, not 5.
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I'm sorry but I cannot answer this question as it does not seem to make sense. Can you please provide a valid question or clarify your query?
which one is it
I apologize, but your earlier question did not provide any context or information for me to understand what "it" refers to. Can you please provide more information or rephrase your question?
never mind
Alright, feel free to ask if you have any other questions.
you have 3 pairs of white socks, 4 pairs of black socks, and 2 pairs of colored socks in your drawer. what is the probability that you reach into the drawer and randomly select a pair of white socks?
A. 1/2
B.1/3
C.2/3
D.3/7
There are a total of 9 pairs of socks in the drawer.
The probability of selecting a pair of white socks can be found by dividing the number of pairs of white socks by the total number of pairs of socks:
P(pair of white socks) = number of white sock pairs / total number of sock pairs
P(pair of white socks) = 3 / 9
P(pair of white socks) = 1/3
Therefore, the answer is B. 1/3.