A hotel maintenance crew wants to estimate how many of the 12,000 lamps in their 30-story hotel need a new light bulb. Which of the following is a random sample of lamps to be inspected?(1 point)
almost all of the answers given are incorrect, if someone else is looking at them for answers DO NOT USE.
A hotel maintenance crew wants to estimate how many of the 12,000 lamps in their 30-story hotel need a new light bulb. Which of the following is a random sample of lamps to be inspected?(1 point)
Responses
400 lamps on the first 10 floors
400 lamps on the first 10 floors
all lamps in booked rooms
all lamps in booked rooms
all lamps from the rooms with king-sized beds
all lamps from the rooms with king-sized beds
100 lamps on each floor chosen randomly
To find an estimate of the number of patrons who borrow novels, we can use the proportion of patrons who borrow novels in the sample of 80 patrons.
Proportion of patrons who borrow novels in the sample = 3/80
To estimate the number of patrons who borrow novels in the whole library, we can multiply this proportion by the total number of patrons in the library:
Estimated number of patrons who borrow novels = Proportion of patrons who borrow novels in the sample * Total number of patrons in the library
Estimated number of patrons who borrow novels = (3/80) * 345
Estimated number of patrons who borrow novels = 12.9375
Rounding to the nearest whole number, we estimate that approximately 13 patrons borrow novels when they visit the library.
The mean time Group A spent shopping is:
(18 + 20 + 46 + 34 + 58 + 31 + 41) / 7 = 32.3 minutes
The mean time Group B spent shopping is:
(15 + 21 + 32 + 42 + 29 + 57 + 39) / 7 = 34.3 minutes
The mean times Group A and Group B spent shopping differ by:
34.3 - 32.3 = 2 minutes
To find the mean daily high temperature of each sample, we add up all the temperatures and divide by the number of temperatures:
Mean of Sample 1: (78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88) / 10 = 85.1°F
Mean of Sample 2: (81 + 79 + 80 + 86 + 89 + 92 + 82 + 88 + 84 + 87) / 10 = 85°F
The mean daily high temperature of Sample 1 is 85.1°F and the mean daily high temperature of Sample 2 is 85°F.
To find the difference between these mean temperatures, we subtract the mean temperature of Sample 2 from the mean temperature of Sample 1:
85.1°F - 85°F = 0.1°F
Therefore, the mean daily high temperatures of the two samples differ by 0.1°F.
A randomly selected 500 lamps from throughout the hotel.
100 lamps on each floor chosen randomly
A local library manager randomly surveys 80 patrons about the type of book they borrow when they visit the library. The manager finds that 3 patrons borrow novels. If the local library has 345 patrons, approximately how many of them borrow novels when they visit the library?(1 point)
Use the table to answer the question.
Group A 18 20 46 34 58 31 41
Group B 15 21 32 42 29 57 39The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.(2 points)
The mean time Group A spent shopping is
minutes.
The mean time Group B spent shopping is
minutes.
The mean times Group A and Group B spent shopping differ by
minutes.
Which data set has the highest median?(1 point)
Responses
{11, 15, 16, 8, 12, 14}
, left brace 11 comma 15 comma 16 comma 8 comma 12 comma 14 right brace
{1, 10, 8, 29, 14, 17, 3}
, left brace 1 comma 10 comma 8 comma 29 comma 14 comma 17 comma 3 right brace
{8, 20, 13, 14, 12, 9}
, left brace 8 comma 20 comma 13 comma 14 comma 12 comma 9 right brace
{1, 6, 15, 7, 15, 18, 14}
{11, 15, 16, 8, 12, 14}
Use the table to answer the question.
Value per House Number of Houses
$150,000 2
$220,000 4
$490,000 3
$540,000 2
$800,000 5
$975,000 2The values of several houses on Mango Street are displayed on the table. What is the median value of these houses?
(1 point)
To find the median value of the houses, we need to arrange them in order from lowest to highest value.
$150,000, $150,000, $220,000, $220,000, $220,000, $220,000, $490,000, $490,000, $490,000, $540,000, $540,000, $800,000, $800,000, $800,000, $800,000, $800,000, $975,000, $975,000
The median is the middle value in this ordered list. Since there are 18 houses in total (2 + 4 + 3 + 2 + 5 + 2), the middle value is the ninth value.
The ninth value in the list is $490,000.
Therefore, the median value of the houses is $490,000.
Theo, Ara, Jose, and Dana all got 100 percent on their latest math test. Their scores on the previous six tests are listed. Whose mean test score will increase the most? (1 point)
Responses
Jose: 91, 93, 97, 96, 96, 96, 88, 90
Jose: 91, 93, 97, 96, 96, 96, 88, 90
Theo: 84, 88, 81, 80, 85, 77, 76
Theo: 84, 88, 81, 80, 85, 77, 76
Ara: 100, 98, 99, 97, 100, 100
Ara: 100, 98, 99, 97, 100, 100
Dana: 68, 74, 83, 80, 81, 82, 70
We need to calculate the mean test score for each student before and after the latest math test, and then compare the increase in mean test score for each student.
Let's use the notation "M1" to represent the mean test score before the latest math test, and "M2" to represent the mean test score after the latest math test.
For Jose:
M1 = (91 + 93 + 97 + 96 + 96 + 96 + 88 + 90) / 8 = 93
M2 = (91 + 93 + 97 + 96 + 96 + 96 + 88 + 90 + 100) / 9 ≈ 95.33
Increase in mean score = 2.33
For Theo:
M1 = (84 + 88 + 81 + 80 + 85 + 77 + 76) / 7 ≈ 81.7
M2 = (84 + 88 + 81 + 80 + 85 + 77 + 76 + 100) / 8 = 85.375
Increase in mean score = 3.675
For Ara:
M1 = (100 + 98 + 99 + 97 + 100 + 100) / 6 ≈ 98.33
M2 = (100 + 98 + 99 + 97 + 100 + 100 + 100) / 7 ≈ 98.57
Increase in mean score = 0.24
For Dana:
M1 = (68 + 74 + 83 + 80 + 81 + 82 + 70) / 7 ≈ 77.57
M2 = (68 + 74 + 83 + 80 + 81 + 82 + 70 + 100) / 8 ≈ 83.75
Increase in mean score = 6.18
Therefore, Dana had the greatest increase in mean test score after the latest math test.
The stem-and-leaf plot shows the speeds of the fastest steel roller coasters in Europe. The table shows the speeds of the fastest steel roller coasters in North America.
Speeds of the Fastest Steel Roller Coasters in Europe (in miles per hour)
Stem Leaf
7 4 5 5 5
8 0 0 3 4 8
9 9
11 1Key: 7|4=74 miles per hour
Speeds of the Fastest Steel Roller Coasters in North America (in miles per hour)
Canada 90 128 91
U.S. 93 120 100
Mexico 95 92 85
Find the range of the speeds of the fastest steel roller coasters on both continents.
(1 point)
The range of the speeds of the fastest steel roller coasters in Europe is
mph. The range of the speeds of the fastest steel roller coasters in North America is
mph.
The range is the difference between the highest and lowest values in a set of data.
For the speeds of the fastest steel roller coasters in Europe, the highest value is 115 and the lowest value is 74. Therefore, the range is:
115 - 74 = 41 mph
For the speeds of the fastest steel roller coasters in North America, the highest value is 128 and the lowest value is 85. Therefore, the range is:
128 - 85 = 43 mph
Therefore, the range of the speeds of the fastest steel roller coasters in Europe is 41 mph and the range of the speeds of the fastest steel roller coasters in North America is 43 mph.
Anthony wants to know the average daily high temperatures in his town during the summer. He chose two random samples of 10 consecutive days and recorded the daily high temperatures. The daily high temperatures in Fahrenheit are as follows.
Sample 1: 78 82 85 87 90 85 79 86 91 88
Sample 2: 81 79 80 86 89 92 82 88 84 87
Find the mean daily high temperatures of each sample and calculate the difference between these mean daily high temperatures.
(2 points)
The mean daily high temperature of Sample 1 is
°.
The mean daily high temperature of Sample 2 is
°.
The mean daily high temperatures of the two samples differ by
The data from two random samples of 100 students regarding what pet they own is given below.
Dog Cat Bird Total
Sample 1 54 38 8 100
Sample 2 39 49 12 100
Based on the two samples, what percentage of students own a bird as a pet?
(1 point)
To find the percentage of students who own a bird as a pet using the two samples, we first need to add up the number of students who own a bird in both samples:
Total number of students who own a bird = 8 + 12 = 20
Then, we divide this total by the total number of students in both samples:
Total number of students in both samples = 100 + 100 = 200
Percentage of students who own a bird = (20/200) x 100% = 10%
Therefore, based on the two samples, 10% of students own a bird as a pet.
These are the scores for two randomly selected lacrosse teams. Find the range of the number of goals scored by each team. Based on the range, which team has a more consistent number of goals scored?
Lacrosse Team 1: 6 0 4 17 3 12
Lacrosse Team 2: 23 14 22 14 17 22(2 points)
The range of the number of goals scored by Lacrosse Team 1 is
. The range of the number of goals scored by Lacrosse Team 2 is
. Based on the range, Lacrosse Team
has a more consistent number of goals scored.
To find the range of the number of goals scored, we need to subtract the lowest score from the highest score.
For Lacrosse Team 1, the highest score is 17 and the lowest score is 0.
Range for Team 1 = 17 - 0 = 17
For Lacrosse Team 2, the highest score is 23 and the lowest score is 14.
Range for Team 2 = 23 - 14 = 9
Lacrosse Team 1 has a larger range than Lacrosse Team 2. A larger range means that the scores are more spread out, indicating less consistency. Therefore, based on the range, Lacrosse Team 2 has a more consistent number of goals scored.
The dot plots show the gas mileage for randomly selected cars and SUVs. Which data values do both distributions have in common?
(1 point)
The data value in common for both distributions with the lowest number is
.
The data value in common for both distributions for the highest number is
.
Question
Fifteen students are randomly selected from two different classes. They were asked how many books they read during the summer. Their responses are as follows. Find the median number of books read by each class. Which class has a higher median number of books read?
Class 1: 0, 5, 3, 6, 7, 8, 10, 1, 1, 4, 5, 6, 4, 5, 6
Class 2: 2, 2, 4, 3, 0, 0, 6, 7, 10, 9, 6, 5, 3, 1, 2
(2 points)
The median number of books read during the summer by Class 1 is
.
The median number of books read during the summer by Class 2 is
.
Class
has a higher median number of books read during the summer.
To find the median number of books read by each class, we need to arrange the values in each list in order from lowest to highest and find the middle value.
For Class 1, the ordered list is:
0, 1, 1, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 8, 10
The median is the middle value, which is 5.
Therefore, the median number of books read during the summer by Class 1 is 5.
For Class 2, the ordered list is:
0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6, 6, 7, 9, 10
The median is the middle value, which is 4.
Therefore, the median number of books read during the summer by Class 2 is 4.
Since 5 is greater than 4, we can conclude that Class 1 has a higher median number of books read during the summer.
Question
The ages of randomly selected employees at two companies are recorded. Their ages are as follows.
Company A: 34, 28, 36, 27, 45, 44, 30, 42, 41, 40, 50, 48, 52, 45, 39, 38
Company B: 29, 32, 48, 51, 49, 37, 33, 35, 36, 40, 45, 48, 43, 43, 44, 48
Which of the following statements is true?
The mean age of employees from Company A is higher than the mean age of employees from Company B.
The median age of employees from Company A is lower than the median age of employees from Company B.
The range of ages of employees from Company A is higher than the range of ages of employees from Company B.
(1 point)
Responses
statements 1 and 3
statements 1 and 3
statements 1 and 2
statements 1 and 2
statements 2 and 3
statements 2 and 3
statements 1, 2, and 3
Statement 1: To determine if the mean age of employees from Company A is higher than the mean age of employees from Company B, we need to find the mean age for each company.
Mean age of employees from Company A:
(34 + 28 + 36 + 27 + 45 + 44 + 30 + 42 + 41 + 40 + 50 + 48 + 52 + 45 + 39 + 38) / 16 = 40.375
Mean age of employees from Company B:
(29 + 32 + 48 + 51 + 49 + 37 + 33 + 35 + 36 + 40 + 45 + 48 + 43 + 43 + 44 + 48) / 16 = 41.125
Statement 1 is false because the mean age of employees from Company A is actually lower than the mean age of employees from Company B.
Statement 2: To determine if the median age of employees from Company A is lower than the median age of employees from Company B, we need to find the median age for each company.
Median age of employees from Company A:
Arrange the ages in numerical order: 27, 28, 30, 34, 36, 38, 39, 40, 41, 42, 44,