A 67gr mass of solid iron is heated by a flame until the temp of the iron equals the temp of the flame. The solid iron is then dropped into 250gr of liquid water at 26 degrees C. After 5 mins, the iron and the water are both at 47 degrees C.

Question

A 67gr mass of solid iron is heated by a flame until the temp of the iron equals the temp of the flame. The solid iron is then dropped into 250gr of liquid water at 26 degrees C. After 5 mins, the iron and the water are both at 47 degrees C.

Specific heat:
Iron- .451
Water- 4.184

Answer 1

And the question is?

Answer 2

To find the specific heat capacity of a substance, we need to use the formula:

q = mcΔT

Where:
- q is the heat energy gained or lost
- m is the mass of the substance
- c is the specific heat capacity of the substance
- ΔT is the change in temperature

Let's first calculate the heat gained by the iron when it is heated by the flame until its temperature equals the flame temperature.

Given:
- Mass of iron (m): 67 g
- Specific heat capacity of iron (c): 0.451 cal/g°C (assuming calories as the unit)

The change in temperature (ΔT) for the iron can be determined as the difference between the final temperature and the initial temperature. Since the iron reaches the temperature of the flame, we can assume the initial temperature of the iron is the same as the flame temperature.

Now, we are given the temperature of the iron and water after they have been in contact for 5 minutes. We can use the same formula to calculate the heat gained by the water:

- Mass of water (m): 250 g
- Specific heat capacity of water (c): 4.184 J/g°C (assuming joules as the unit)
- Initial temperature of water: 26°C
- Final temperature of water: 47°C

Using the given values, we can calculate the heat gained by the iron and the heat gained by the water separately.

For the heat gained by the iron:
q_iron = mcΔT
q_iron = (67 g) * (0.451 cal/g°C) * (final temperature - initial temperature)

For the heat gained by the water:
q_water = mcΔT
q_water = (250 g) * (4.184 J/g°C) * (final temperature - initial temperature)

To find the specific heat capacity of the iron, we can rearrange the formula:

c_iron = q_iron / (m * ΔT)

Similarly, we can find the specific heat capacity of water:

c_water = q_water / (m * ΔT)

By substituting the calculated heat gained values (q_iron and q_water), as well as the given mass and temperature values, into the specific heat capacity formulas, we can find the specific heat capacities of iron and water.