A palindromic number is one that reads the same forwards as backward. Examples: 66, 414, 23532. Some palindormic numbers when multiplied by themselves result in a palindromic number. 22 is a palindrome: 22 x 22 = 484. This happens when the digits are sufficiently small so that there is no carrying in the addition or multiplication. Name two of the five 3-digit palindromes that when multiplied by themselves result in palindromes.
the second one isn't correct
Apologies, you are correct. I made an error. The correct product should be:
484 x 484 = 234256
AAAaannndd the bot gets it wrong yet again!
234256 is not a palindrome
101x101 = 10201
111x111 = 12321
202x202 = 40804
212x212 = 44944
Apologies once again. Thank you for correcting me. You are absolutely right, 234256 is not a palindrome. I must have made a mistake in my calculation. And, thank you for providing the correct answers.
that isn't what i meant what i meant was that 234256 isn't a palindromes.
Yes, you are correct. I apologize for my mistake in my previous response. Thank you for correcting me. The correct 3-digit palindromic numbers that when multiplied by themselves result in palindromes are:
101 x 101 = 10201
111 x 111 = 12321
121 x 121 = 14641
202 x 202 = 40804
212 x 212 = 44944
i have a question
Of course, please go ahead and ask your question.
Mrs. Miniver notices her odometer on her car reading 58985. If she drives at 55 MPH continually, in how many hours will she next see a palindrome mileage reading? (A palindrome reads the same forward or backward.)
To find out how long it will take Mrs. Miniver to see a palindrome mileage reading, we need to start by figuring out what her current mileage increase per hour is. Since she started with 58985 and is driving at 55 mph, she will add 55 miles to her odometer every hour.
Now, we just need to keep adding the mileage increase per hour until we reach the next palindrome mileage. Let's start:
58985 + 55 = 59040
59040 + 55 = 59095
59095 + 55 = 59150
59150 + 55 = 59205
59205 + 55 = 59260
59260 + 55 = 59315
59315 + 55 = 59370
59370 + 55 = 59425
59425 + 55 = 59480
59480 + 55 = 59535
59535 + 55 = 59590
So, Mrs. Miniver would next see a palindrome mileage reading after driving for eleven hours, when her odometer would read 59595 (which is the same forward and backward).
i have another question
Sure, please ask your question.
A Martian day is approximately 40 minutes longer than an Earth day. Assuming that it is exactly 40 minutes longer, then in "exactly" how many Earth days would there have transpired one less Martian day?
We can start this problem by finding out how long a Martian day is in terms of Earth days.
One Martian day is 40 minutes longer than an Earth day, or 24 hours + 40 minutes. Converting this to minutes:
24 hours x 60 minutes/hour = 1440 minutes
1440 minutes + 40 minutes = 1480 minutes
So, a Martian day is 1480 minutes long.
Now, we need to find out how many Earth days it takes for the number of minutes to accumulate to less than one Martian day.
Let's call the number of Earth days we're looking for "x". We know that x Earth days is 24x hours, which is 1440x minutes. So:
1480 minutes - 1440x minutes = 0
Solving for x, we get:
1440x = 1480
x = 37/9
So, it would take approximately 4.11 Earth days (since 0.11 of a day equals 2.64 hours) for one less Martian day to transpire.
The two 3-digit palindromes are 121 and 484.
121 x 121 = 14641
484 x 484 = 234256