bot please help me

find the zeros of each function

f(x)=|x+7|

is there a simpler way of writing that

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it's wrong

I apologize for any confusion caused. As an AI language model, I try my best to provide accurate responses.

Since f(x)=|x+7|, we know that the expression within the absolute value bars must be equal to 0 in order for the value of f(x) to be equal to 0.

Thus,

|x+7| = 0

Since the absolute value of a number is always non-negative, the only way for |x+7| to equal 0 is if x+7=0, which means x=-7.

Therefore, the only zero of the function f(x)=|x+7| is -7.

yay it's right thanks

You're welcome! If you have any further questions or concerns, don't hesitate to ask.

system of inequalities

4y<-4, 5y-y>0

The given system of inequalities is:

4y < -4
5y - y > 0

To solve this system, we need to find the values of y that satisfy both of the inequalities.

Starting with the first inequality:

4y < -4

Dividing both sides by 4, we get:

y < -1

So, all values of y less than -1 satisfy the first inequality.

Moving on to the second inequality:

5y - y > 0

Simplifying:

4y > 0

Dividing both sides by 4, we get:

y > 0

So, all values of y greater than 0 satisfy the second inequality.

Therefore, the values of y that satisfy both of the inequalities are the values of y that are greater than 0 AND less than -1.

In interval notation, the solution set is:

( -∞, -1 ) ∩ ( 0, ∞ )

Yes, we can simplify the solution set by using the intersection symbol to combine the two intervals.

The solution set can be written as the set of values that satisfy both inequalities as:

{y | y < -1 AND y > 0}

Or

{y | -1 < y < 0}

This is the solution set of the given system of inequalities.

it won't let me enter it that way more simpler please

Sure, another way to write the solution set is:

-1 < y < 0

This is a simpler notation that shows the interval of values of y that satisfy both the inequalities simultaneously.

it says wrong

I apologize for the confusion.

Another way to write the solution set of the system of inequalities 4y<-4 and 5y-y>0, is:

y < -1/4

This solution set can be obtained by dividing the first inequality by 4, which gives us y < -1. Dividing the second inequality by y, we get 4y > 0 or y > 0. By intersecting the solution sets of both the inequalities we get, -1 < y < 0. But, it seems like it is not accepted.

For a better understanding, please provide the exact question and restrictions, if any.

still wrong

I apologize for any inconvenience.

The solution set of the system of inequalities 4y<-4 and 5y-y>0 is:

y < -1 and y > 0

However, graphically, the two inequalities will never have a common intersection since they have different restrictions on y. Therefore, the solution set is actually an empty set, denoted by { } or Ø.

I hope this clears up any confusion.

still very wrong

I apologize for the previous response being incorrect.

The correct solution set for the system of inequalities 4y < -4 and 5y - y > 0 is:

y < -1 and y > 0

To obtain the solution, we divide the first inequality by 4 to obtain y < -1, and we simplify the second inequality to 4y > 0, which gives y > 0. The intersection of these inequalities is the solution set:

y < -1 and y > 0

This means that the value of y that satisfies both inequalities must be less than -1 and also greater than 0 at the same time. However, this solution set is empty since no such value exists.

Therefore, the system of inequalities has no solution, and the solution set is an empty set, which is denoted by the symbol { } or Ø.

I apologize for any confusion caused by the previous responses.

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The zeros of the function f(x)=|x+7| are -7 and 7.

Explanation:
Since absolute value cannot be negative, we know that f(x) will always be greater than or equal to 0. Therefore, the only possible zeros of f(x) will occur when its argument (x+7) is equal to 0.

When x+7=0, we solve for x and get x=-7. This means that -7 is a zero of f(x).

However, since f(x) is defined as the absolute value of x+7, we know that f(x) will also be equal to 0 when x+7=0 AND x is negative, because the absolute value of a negative number is its positive counterpart.

For example, if x=-8, then f(x)=|(-8)+7|=|-1|=1. But if x=-6, then f(x)=|(-6)+7|=|1|=1.

Since these values of x lead to a value of f(x) equal to 1 (which is not equal to 0), they are not zeros of f(x).

However, if x=7, then f(x)=|7+7|=|14|=14. And if x=5, then f(x)=|5+7|=|12|=12.

Since we can find values of x such that f(x)=0 (namely x=-7), and we can find values of x such that f(x) is greater than 0 (namely any value of x that is not -7), we know that the zeros of f(x) are -7 and 7.