which of the following points could be added to the coordinate graph as a third point to create an isosceles triangle choose all that apply
Without providing a set of points, it is not possible for me to answer this question. Please provide the set of points.
which of the following points could be added to the coordinate graph as a third point to create an isosceles triangle choose all that apply
point are at -2,-1 and 4,1
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i have the asewrs for the questions
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1,3 1,-6 -2,5 4,-2
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which of the following points could be added to the coordinate graph as a third point to create an isosceles triangle choose all that apply
this is my question i already gave u the ansewrs
I apologize for my mistake. Here are the correct answers to your problem:
An isosceles triangle is a triangle that has two sides of equal length. To create an isosceles triangle using the given points (-2, -1) and (4, 1), we need to find a third point on the coordinate plane that is the same distance away from both points.
Using the Distance Formula, we find that the distance between (-2, -1) and (4, 1) is:
sqrt[(4-(-2))^2 + (1-(-1))^2] = sqrt(6^2 + 2^2) = sqrt(40)
Therefore, any point that is sqrt(40) units away from both (-2, -1) and (4, 1) can be added to the coordinate graph to create an isosceles triangle.
The possible points are:
(0, 3) - This point is located in the midpoint of (-2, -1) and (4, 1)
(6, -3)
(-6, 5)
(-3, 0)
Therefore, the answer is: (0, 3), (6, -3), (-6, 5), and (-3, 0).
which of the following points could be added to the coordinate graph as a third point to create an isosceles triangle choose all that apply
1,3
1,-6
-2,5
4,-2
The given points are:
- (-2, 5)
- (1, 3)
- (1, -6)
- (4, -2)
To create an isosceles triangle using the given points, we need to check if there is a point on the coordinate plane that is equidistant from two of the given points.
1. Distance between (-2, 5) and (1, 3):
sqrt[(1 -(-2))^2 + (3 - 5)^2] = 5
2. Distance between (-2, 5) and (1, -6):
sqrt[(1 -(-2))^2 + (-6 - 5)^2] = sqrt(10^2 + 11^2) = sqrt(221)
3. Distance between (-2, 5) and (4, -2):
sqrt[(4 -(-2))^2 + (-2 - 5)^2] = sqrt(6^2 + 7^2) = sqrt(85)
4. Distance between (1, 3) and (1, -6):
sqrt[(1 - 1)^2 + (-6 - 3)^2] = sqrt(9^2) = 9
5. Distance between (1, 3) and (4, -2):
sqrt[(4 -1)^2 + (-2 - 3)^2] = sqrt(9^2 + 5^2) = sqrt(106)
6. Distance between (1, -6) and (4, -2):
sqrt[(4 -1)^2 + (-2 -(-6))^2] = sqrt(9^2 + 4^2) = sqrt(97)
7. Distance between (4, -2) and (1, -6):
sqrt[(1 -4)^2 + (-6 -(-2))^2] = sqrt(3^2 + 4^2) = 5
From the above calculations, we see that there is no point on the coordinate plane that is equidistant from any two given points. Therefore, none of the given points can be used to create an isosceles triangle with the other two points. The answer is: None.