Most window cleaners are aqueous solutions of ammonia. A 9.00 mL sample of a particular window cleaner requires 42.95 mL of 0.0508 M HCl for its titration. What is the molarity of ammonia in the window cleaner?

i am completely lost i cant even find the balanced equation

as you can see below

never mind i took a random guess and got it right :)

NH3 + HCl ==> ??

moles HCl = M x L
moles NH3 = moles HCl since the reaction of NH3 with HCl is 1 mole to 1 mole.
Then molarity NH3 = moles NH3/L NH3. Post your work if you get stuck. .

Random guesses won't get it. You need to understand how to do it.

To solve this problem, we need to set up a balanced equation for the reaction between ammonia (NH3) and hydrochloric acid (HCl). The balanced equation is as follows:

NH3 + HCl -> NH4Cl

In this reaction, one mole of NH3 reacts with one mole of HCl to produce one mole of NH4Cl.

Now, let's use the given information:

- The volume of the window cleaner sample is 9.00 mL.
- The volume of HCl used for titration is 42.95 mL.
- The molarity of the HCl solution is 0.0508 M.

First, we need to determine the number of moles of HCl used in the titration.

Using the equation Molarity (M) = Moles (mol) / Volume (L), we can rearrange the equation to calculate the moles:

Moles (mol) = Molarity (M) x Volume (L)

Moles of HCl = 0.0508 M x 0.04295 L (convert mL to L)

Next, we use the balanced equation to determine the moles of NH3 present in the window cleaner sample. Since the reaction ratio is 1:1 between NH3 and HCl, the moles of NH3 will be equal to the moles of HCl.

Moles of NH3 = 0.0508 M x 0.04295 L

Finally, to calculate the molarity of ammonia in the window cleaner, we divide the moles of NH3 by the volume of the window cleaner sample:

Molarity of NH3 = Moles of NH3 / Volume of window cleaner sample

Molarity of NH3 = (0.0508 M x 0.04295 L) / 0.00900 L

Simplifying the expression will give you the final answer.

Please note that this calculation assumes that all the ammonia in the window cleaner reacted with the HCl during the titration.