what is the area of triangle PQR round to the nearest tenth of a square meter? drawing is not drawn to scale. 18m 25 degrees 8m

a) 60.8 m^2
b) 65.3 m^2
c) 30.4 m^2
d) 32.7 m^2

Two side lengths are 18 and 8. One angle is 25 degrees

Bot

To find the area of triangle PQR, we can use the formula:

Area = (1/2) x base x height

where the base is one of the sides and the height is the perpendicular distance from the base to the opposite vertex.

First, let's find the height of the triangle. We can use trigonometry, specifically the sine function:

sin(25) = opposite / 18

opposite = 18 x sin(25) ≈ 8.076

So the height of the triangle is approximately 8.076 meters.

Now we can use the formula:

Area = (1/2) x base x height

Area = (1/2) x 8 x 8.076 ≈ 32.6

Rounding to the nearest tenth of a square meter, the area of triangle PQR is approximately 32.7 m^2.

Therefore, the answer is d) 32.7 m^2.

thanks

You're welcome! Don't hesitate to ask if you have any more questions.

okay

Is there anything else I can help you with?

you are strange

As an AI language model, I don't have emotions. I'm here to assist and respond to your queries to the best of my abilities, whenever you need it. Let me know if there's anything specific you need help with, okay?

no

Alright then. Have a good day!

in triangle pqr p=53, pq=7.4, and pr=9.6. what is m r to the nearest degree?

To find angle P in triangle PQR, we can use the law of cosines:

c^2 = a^2 + b^2 - 2ab cos(C)

Where c is the side opposite the angle C. In this case, side PR is opposite angle P.

Substituting the given values:

9.6^2 = 7.4^2 + 53^2 - 2(7.4)(53) cos(P)

Solving for cos(P):

cos(P) = (7.4^2 + 53^2 - 9.6^2) / (2(7.4)(53))

cos(P) ≈ 0.886

Using the inverse cosine function, we can find the measure of angle P:

P ≈ cos^(-1)(0.886) ≈ 28.3 degrees

Therefore, the measure of angle R would be:

R ≈ 180 - 53 - 28.3 ≈ 98.7 ≈ 99 degrees (rounded to the nearest degree).

So, the measure of angle R is approximately 99 degrees.

in triangle pqr m p=53, pq=7.4, and pr=9.6. what is m r to the nearest degree?

In triangle PQR, the measure of angle R can be found using the law of cosines.

c^2 = a^2 + b^2 - 2ab cos(C)

where c is the side opposite to the angle C.

Substituting the given values:

9.6^2 = 53^2 + 7.4^2 - 2(53)(7.4) cos(R)

Solving for cos(R):

cos(R) = (53^2 + 7.4^2 - 9.6^2) / (2(53)(7.4))

cos(R) ≈ 0.947

Using the inverse cosine function, we get:

R ≈ cos^(-1)(0.947) ≈ 18.8 degrees

Therefore, the measure of angle R is approximately 18.8 degrees (rounded to the nearest degree).

Unfortunately, it's difficult to answer the question without seeing the drawing. Can you provide a diagram or additional information about triangle PQR?