Type of Cookie Adults Children Total
Chocolate chip 5 10
Peanut butter 8 6
Oatmeal 7 4
Use the table below.
Type of Cookie Adults Children Total
Chocolate chip 5 10
Peanut butter 8 6
Oatmeal 7 4
Based on the two-way frequency table, how many people chose oatmeal cookies?
A. 20
B. 15
C. 14
D. 11
6
18. To find out how many adults were surveyed, you can add up the number of adults who chose each type of cookie. Adding 5+8+7 gives us a total of 20 adults who were surveyed.
Answer: C. 20
19. To find the percentage of children who chose oatmeal, you need to divide the number of children who chose oatmeal (4) by the total number of children (10) and then multiply by 100.
4/10 * 100 = 40%
Answer: There is no option for 40%, but the closest option is C. 50% which is incorrect. The correct answer is 40%.
The total number of adults who chose oatmeal cookies is 7, and the total number of children who chose oatmeal cookies is 4. Therefore, the total number of people who chose oatmeal cookies is 7+4=11.
Answer: D. 11
Use the table below.
Type of Cookie
Chocolate chip
Adults
5
Children
10
Total
Peanut butter
8
6
Oatmeal
7
4
18. Based on the two-way frequency table, how many adults were surveyed? (1 point)
13
15
20
40
Use the table to answer the question.
19. What percentage of the children chose oatmeal? (1 point)
20%
30%
50%
80%
16. Carol has a collection of 100 stamps. The graph below shows the percentage of stamps she has from each country.
Carol's Stamp Collection
France 24%
England 22%
Italy 25%
Norway 29%
How many more of Carol's stamps are from France than from England?
22 stamps
2 stamps
24 stamps
46 stamps
17. A survey of 594 students about the sports program at a school finds the following results:
495 students like the program.
99 students think the program is inadequate.
If a circle graph were made from the data, what would the measure of the central angle be for the group that thinks the program is inadequate?
17°
60°
83°
300°
16. To find out how many more stamps Carol has from France than from England, first we need to calculate how many stamps she has from each country.
France: 24% of 100 stamps = 24 stamps
England: 22% of 100 stamps = 22 stamps
To find the difference, we can subtract:
24 stamps - 22 stamps = 2 stamps
Answer: B. 2 stamps
17. The total number of students surveyed is 495 + 99 = 594. To find the measure of the central angle for the group that thinks the program is inadequate, we need to find what percentage of the total surveyed they represent:
99/594 * 100% = 16.67%
To find the measure of the central angle, we can use the formula:
central angle = percentage * 360°
central angle = 16.67% * 360° = 60° (rounded to the nearest whole number)
Answer: B. 60°
13. What type of trend does the scatter plot below show? What type of real-world situation might the scatter plot represent?
positive trend; weight and height
negative trend; weight and height
no trend; the number of pets owned and the owner's height
negative trend; the water level in a tank in the hot sun over time
14. The mean of a set of four test scores is 85. If three of the test scores are 81, 83, and 85, what is the fourth test score?
89
87
91
85
15. Which of the following would best display information in a frequency table that has been divided into categories?
bar graph
pictograph
circle graph
histogram
13. The scatter plot shows a positive trend between two variables. The real-world situation it may represent is the relationship between the height and weight of a person. As a person's height increases, their weight tends to increase as well.
Answer: A. Positive trend; weight and height.
14. To find out the fourth test score, we can use the formula:
mean = (sum of all scores) / (number of scores)
If the mean is 85 and there are four test scores, we know that:
85 = (81 + 83 + 85 + fourth score) / 4
Multiplying both sides by 4:
340 = 249 + fourth score
Subtracting 249 from both sides:
91 = fourth score
Answer: C. 91
15. A bar graph would be the best way to display information in a frequency table that has been divided into categories. The bars can represent the different categories, and their length can show the frequency of each category.
Answer: A. Bar graph.
1,000 people were surveyed about the type of vehicles they owned. The results are shown in the circle graph below.
Types of Vehicles Owned
42% SUV
28% Wagon
25% Sedan
5% Hatchback
How many people own a wagon?
2,800
280
28
3
There are two main methods you can use to find the answer to this question based on the given information:
Method 1: Proportions
You can set up a proportion using the percentage of wagon owners in the survey and the total number of people surveyed.
28/100 = x/1000
To solve for x, you can cross-multiply:
100x = 28 * 1000
Dividing both sides by 100:
x = 280
Answer: B. 280 people own a wagon.
Method 2: Circle Graph
You can estimate the number of people who own a wagon by looking at the circle graph and using a proportion.
First, find the fraction of the circle that represents wagons:
28% = 28/100 = 0.28
The fraction of the circle that represents wagons is approximately 0.28.
Next, estimate how many people are represented by the whole circle (100%):
42% + 28% + 25% + 5% = 100%
This means that the whole circle represents all 1,000 people in the survey.
Finally, you can estimate the number of people who own a wagon by multiplying the fraction of the circle that represents wagons by the total number of people in the survey:
0.28 * 1000 = 280
Answer: B. 280 people own a wagon.
9. Which box-and-whisker plot shows the high temperatures in Pittsburgh, Pennsylvania during the first two weeks of March:
33, 45, 42, 47, 35. 45. 41. 34. 44, 34. 48, 40, 43, 45
+ + 50
30
31
32
33
34
35
36
37
38
39
40 41
42 43
44
45
46
47
48
49
+ 50
30 31
32
33
34
35
36
37
38
39
40
41 42 43
44
45
46 47
48
49
30 31
32
33
34
35
36
37
38
39 40
41
42
43
44
45
46
47
48
49
50
+ 50
30
31
32
33
34
35
36
37
38
39 40 41
42
43 44 45
46
47
48
49
10. Ms. Alison drew a box-and-whisker plot to represent her students' scores on a midterm test.
44:42
72
01
96
Jason received 81 on the test. How does Jason's score compare to his classmates?
About 25% scored higher, about 75% scored lower.
About 50% scored higher, about 50% scored lower.
About 75% scored higher; about 25% scored lower.
No one scored higher.
9. The box-and-whisker plot that shows the high temperatures in Pittsburgh, Pennsylvania during the first two weeks of March is the third one:
30 |_________
| | |
35 |-----| |---
| | | |
40 |---- |---|
| | | |
45 |-----| |---
|_____|__|_
The minimum temperature is 33, the maximum temperature is 48, the lower quartile is 35, the median is 43, and the upper quartile is 45.
Answer: C. the third box-and-whisker plot.
10. Jason's score of 81 falls between the lower quartile (44) and the median (72). This means that approximately 50% of the students scored higher than Jason, and approximately 50% of the students scored lower than Jason.
Answer: B. About 50% scored higher, about 50% scored lower.
Which box-and-whisker plot shows the scores of ten students on a mathematics exam?
92. 76, 83, 97, 74. 81, 92, 91, 96, 87
70
72
74
76
78
80
82
84
86
86
90
92 94
96
98 100
70
72
74
76
78
80
82
84
86
88
90
92
94
95
98 100
70
72
74
76 78
80
82 84 86 88 90 92 94 95 96 100
70
72
74
76
78
80
82
84
86
92
94
96
98
100
The box-and-whisker plot that shows the scores of ten students on a mathematics exam is the fourth one:
70 |__
| |
75 |__|
| |
80 |-----|
| | |
85 |----|--
| | |
90 |-----|--
|__|
The minimum score is 74, the maximum score is 97, the lower quartile is 80, the median is 86, and the upper quartile is 92.
Answer: D. The fourth box-and-whisker plot.
A back-to-back stem-and-leaf plot showing the points scored by each player on two different basketball teams is shown below.
Points Scored in a Game
Team 1
Team 2
4
3
0
4
9
9
8
2
0
1
0
1
7
6
1
2
3
3
8
Key: 4 | 0 | 2 means 4 points for Team 1, 2 points
for Team 2
What is the median number of points scored for each team?
Median for Team 1: 15
Median for Team 2: 11
Median for Team 1: 12
Median for Team 2: 11
Median for Team 1: 18
Median for Team 2: 17
Median for Team 1: 15
Median for Team 2: 14
To find the median number of points scored for each team, we need to order the scores from least to greatest and find the middle value.
For Team 1:
0, 0, 1, 1, 2, 3, 4, 4, 7, 8, 9, 9
The median is the average of the two middle values:
(3 + 4) / 2 = 3.5
So the median for Team 1 is 3.5 points.
For Team 2:
0, 1, 1, 2, 3, 3, 4, 6, 8, 9
There are 10 scores, so the median is the middle value:
Median = 3
So the median for Team 2 is 3 points.
Answer: The median number of points scored for each team is:
Median for Team 1: C. 3.5
Median for Team 2: D. 3
6. Which stem-and-leaf plot represents the data set below?
109, 60, 77, 54, 63, 84, 93, 65, 58, 97, 113
54
8 3
5
60
77
8 4
9 3
7
10 9
11 3
Key: 89 means 89
2 3
1
5
77
56789
42743 am co Key: 89 means 89
4
7
10 9
11
3
54
8 3
60
5
7 7
84
93
7
1
09
1
13
Key: 89 means 89
54 60 7 7 8 4 9 3 10 11
8
3
5
793
Key:
89 means 89
To create a stem-and-leaf plot, we need to separate each data point into a stem (the tens digit) and a leaf (the ones digit). Then, we group the leaves for each stem in increasing order. The stem-and-leaf plot that represents the data set is the first one:
Stem | Leaf
5 | 4
6 | 0 3 5 5 8
7 | 7 7
8 | 4
9 | 3 7
10 | 9
11 | 3
Key: 89 means 89
Answer: A.
5 | 4
6 | 0 3 5 5 8
7 | 7 7
8 | 4
9 | 3 7
10 | 9
11 | 3
Which frequency table illustrates the following test times, in minutes, for a reading test?
81, 58, 72, 70, 57, 79, 82, 54, 82, 59, 72, 63, 64, 55, 76, 84, 57, 65, 73, 58
Test Times in Minutes
Tally
Frequency
50-59
7
60-69
|||
3
70-79
6
80-89
4
Test Times in
Tally
Frequency
Minutes
50-59
4
60-69
7
70-79
6
80-89
|||
3
Test Times in
Minutes 50-59
Tally
Frequency
8
60-69
5
70-79
4
80-89
7
Test Times in Minutes
Tally
Frequency
50-59
6
60-69
7
70-79
3
|||
80-89
4
To create a frequency table, we need to group the data into intervals and count how many data points fall into each interval. It's important to make sure that the intervals include all the data values and don't overlap.
The frequency table that accurately illustrates the given data is:
Test Times in Minutes
Tally
Frequency
50-59
3
60-69
3
70-79
6
80-89
5
Answer: D.
Note: It’s not possible to create a frequency table that accurately represents the given data and has 8 frequency values in the first column, as shown in option C.
What are the mean, median, mode, and range of the data set 16, 17, 17, 17, 19, 21, 23, 24?
mean = 19.3; median = 17; mode = 18
mean 19.3; median = 18; mode = 17
mean = 18; median = 19.3; mode = 17
mean = 20.3; median = 18; mode = 17
2. Given the data 14, 26, 23, 19, 24, 46, 15, 21, what is the outlier?
(1 point)
46
21
23
14
For the first question:
To find the mean, we add up all the values and divide by the total number of values:
(16 + 17 + 17 + 17 + 19 + 21 + 23 + 24) / 8 = 19.3
To find the median, we need to put the values in order:
16, 17, 17, 17, 19, 21, 23, 24
The median is the middle value, which is 17.
To find the mode, we look for the value that appears most frequently. In this case, the mode is 17 (because it appears three times, which is more than any other value).
To find the range, we subtract the smallest value from the largest value:
24 - 16 = 8
So the mean is 19.3, the median is 17, the mode is 17, and the range is 8.
Answer: A. mean = 19.3; median = 17; mode = 17.
For the second question:
To determine the outlier, we can use different methods such as the Interquartile Range (IQR), the Z-Score, or observation. We can start by finding the IQR:
1. Put the data in order: 14, 15, 19, 21, 23, 24, 26, 46
2. Find the median: 23
3. Split the data into two halves: 14, 15, 19, 21 and 24, 26, 46
4. Find the median of each half: Q1 = 19 and Q3 = 46
5. Calculate the
The chart below shows the average number of movies seen per every 10 people in selected countries.
Average Number of Movies Seen
Country
Turkey
Japan
Each Year (Per 10 People)
United Kingdom
Finland
5 12
13
13
Austria
Germany
Spain
15
18
22
Sweden
Denmark
22
22
Switzerland
France
Norway
25
25
30
Canada
United States
30
45
Use equal intervals to make a frequency table for the above data. You do not need to show tally marks.
Make a stem-and-leaf plot that shows the following data:
Country
Percentage of
Households with Color
Austria
Television
97
Belgium
Canada
Denmark
93
69
95
France
88
94
64
Germany
Greece
Ireland
92
88
100
Italy
Japan
Switzerland
United States
91
97