College Math

Assume that the playbook contains 11 passing plays and 15 running plays. The coach randomly selects 8 plays from the playbook.

What is the probability that the coach selects at least 2 passing plays and at least 3 running plays?

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asked by Taymor
  1. Add up these probabilities:
    2 running (5 passing)
    1 passing (7 running)
    1 running (7 passing)
    0 running (8 passing)
    0 passing (8 running)
    and subtract the total from 1.

    The probability of 0 passing plays is (15/26)^8 = 0.01227

    You do the others

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    posted by drwls

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