In a spacecraft the carbon dioxide exhaled by astronaut can be removed by the reaction with Lithium Hydroxide, LiOH according to the following;
πΆπ2 (π)+πΏπΌππ» (π)βπΏπππ» (π )+π»2π (π)
How many moles of Lithium hydroxide are required to react with 30 mol of CO2, the average exhaled by a person each day.
Your equation is not right. Not the right products and not balanced.
CO2(g) + 2LiOH(s) ==> Li2CO3(s) + H2O(l)
The equation tell you 1 mol CO2 needs 2 mols LiOH; therefore, 30 moles CO2 will need ..........moles LiOH.
50 moles
To determine the moles of lithium hydroxide (LiOH) required to react with 30 moles of carbon dioxide (CO2), we need to use the stoichiometry of the balanced equation.
The balanced equation is:
CO2 (g) + 2 LiOH (g) β Li2CO3 (s) + H2O (l)
From the equation, we can see that one mole of CO2 reacts with 2 moles of LiOH.
To find the moles of LiOH required, we can set up a proportion:
(30 moles CO2) x (2 moles LiOH / 1 mole CO2) = 60 moles LiOH
Therefore, 60 moles of LiOH are required to react with 30 moles of CO2, the average exhaled by a person each day.