Algebra 2: Radicals URGENT!!

Could some kind, saintly soul help me solve this problem?

Simplify:

8w sqrt(48w^5) - x^2 sqrt(3xw^2)

.
.
=8w(√16)(√3)(√w^4)(√w) - x^2(√3)(√x)(√w^2)
=32w^3(√3w) - wx^2(√3x)

not much of a "simplification" really

8w sqrt(16*3w^5) - x^2 w sqrt(3x)
= 32 w sqrt 3 * w^(5/2) - w x^2 sqrt 3 *sqrt x
= w*sqrt 3 [32 w^(5/2) - x^(5/2)]

  1. 👍 0
  2. 👎 0
  3. 👁 180
asked by Maria

Respond to this Question

First Name

Your Response

Similar Questions

  1. algebra

    am I right? 1. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqrt

    asked by Carl Wheezer on May 7, 2017
  2. algebra,math,help

    Use Property 2 to simplify each of the following radical expressions. sqrt (10)/ sqrt(49) My answer: sqrt (10) / (7) THis next one i need help: Use the properties for radicals to simplify each of the following expressions. Assume

    asked by jas20 on March 9, 2007
  3. math,algebra,help

    Directions are simplify by combining like terms. x radiacal 18 -3 radical 8x^2 can someone show me how to do these types of problems. thanks I cant determine the second term. For the first, I think you meant x sqrt(18) which

    asked by Jasmine20 on January 26, 2007
  4. Calculus

    Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,

    asked by COFFEE on July 10, 2007
  5. some algebra help (radicals)

    I hope I am writing this down right.. I am trying to do some practice questions to learn 10^5 (sqrt)2y - 4^5 (sqrt)2y I am trying to figure out how to solve this They gave us some answers to choose from, but I am clueless on how

    asked by Cassie on May 6, 2007
  6. Math/Calculus

    Solve the initial-value problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? Thanks. y''+4y'+6y=0, y(0)=2, y'(0)=4 r^2+4r+6=0, r=(-4 +/- sqrt(16-4(1)(6))/2 r=-2 +/- sqrt(2)*i , alpha

    asked by COFFEE on July 12, 2007
  7. Math Help please!!

    Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine

    asked by Reggie on May 20, 2007
  8. Algebra

    Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now

    asked by Jamie on August 17, 2006
  9. Math

    How do you find a square root of a number that's not a perfect square? I'm very confused. The book doesn't explain it too well. You can approximate it or simplify it in terms of (products of) square roots of smaller numbers. E.g.

    asked by Emily on February 12, 2007
  10. math

    how would you simplify this equation: y = (x+3)/[(4-sqrt(16+h))] please help me! you have three variables. I am not certain "simplify" is an appropriate term here. ohhhh it was my mistake. I meant: y = h/[(4-sqrt(16+h))] y =

    asked by kristie on June 30, 2006

More Similar Questions