A hockey player applies a 70 N force to a 170 g hockey puck in a span of 2.20 second.
Determine the impulse experience by the hockey puck. If the hockey puck started at rest, what is its final velocity?
To determine the impulse experienced by the hockey puck, we can use the equation:
Impulse (J) = Force (F) * Time (Δt)
Given that the force (F) applied by the hockey player is 70 N and the time (Δt) over which the force is applied is 2.20 seconds, we can calculate the impulse as follows:
J = 70 N * 2.20 s
J = 154 N·s
Now, to find the final velocity of the hockey puck, we can use the impulse-momentum relationship:
Impulse (J) = Change in momentum (Δp)
Since the hockey puck starts at rest, its initial momentum (p_initial) is zero. Therefore, the change in momentum (Δp) is equal to the final momentum (p_final). We can rearrange the equation to solve for the final velocity (v_final):
J = m * v_final, where m is the mass of the puck
Given that the mass (m) of the hockey puck is 170 g (0.17 kg), we can calculate the final velocity as follows:
154 N·s = 0.17 kg * v_final
v_final = 154 N·s / 0.17 kg
v_final ≈ 905.88 m/s
Therefore, the final velocity of the hockey puck is approximately 905.88 m/s.