I really need help because I'm really confused. Can someone please check my answers?
1. what are the mean median and mode of the data set 15 16 21 23 25 25 25 39
A: Mean = 23.6; Median = 25; Mode = 24
B: Mean = 24; Median = 23.6; Mode = 25
C: Mean = 24.6; Median = 24 Mode = 25
D: Mean = 23.6; Median = 24; Mode = 25
I believe the answer could be D or A
2. Given the data 21 13 13 37 13 23 25 15 which number is the outlier?
A: 13
B: 15
C: 23
D: 37
I think the answer is D but I'm not sure because it seems too obvious
3. Which frequency table represents the set data below related to how each student in a class traveled to school in the morning?
| Family car | Bus | car pool | Biked |
| Biked | Walked | family care | Biked |
| Bus | Biked | Walked | Bus |
| Biked | Family car | Car pool | Biked |
| Bus | Bus | Walked | Walked |
| Walked | Walked | Walked | Car pool |
A:
| Transportation | Tally | frequency |
| Walked | 11111 11 | 7 |
| Biked | 11111 | 5 |
| Bus | 11111 | 5 |
| Family car | 1111 | 4 |
| Car pool | 111 | 3 |
B:
| Transportation | Tally | frequency |
| Walked | 11111 11 | 7 |
| Biked | 1111 | 4 |
| Bus | 11111 | 5 |
| Family car | 11111 | 5 |
| Car pool | 111 | 3 |
C:
| Transportation | Tally | frequency |
| Walked | 11111 11 | 7 |
| Biked | 11111 1 | 6 |
| Bus | 11111 | 5 |
| Family car | 111 | 3 |
| Car pool | 111 | 3 |
D:
| Transportation | Tally | frequency |
| Walked | 11111 11 | 7 |
| Biked | 1111 | 4 |
| Bus | 11111 1 | 6 |
| Family car | 1111 | 4 |
| Car pool | 111 | 3 |
I think it could be A but I'm not sure if I did this right
Please I really need help
1. median = sum/8 = 23.6
median: the middle number if data is ordered.
you have and even count, so there is no middle, in that case
add up the two in the middle, then divide by e
so ... (23+25)/2 = 24
mode: the number that appears most often, in your case 25
Looks like you decided to stop after finding the mean.
2. clearly 37,
3. can't make sense out of the posting for #3.
It is very hard to type charts in this format of jiskha.