# Chemistry

Include an explanation, balanced chemical equation, units, significant figures and/or calculations where appropriate.

Determination of the Molar Mass of an Unknown Acid

Trial 1:
0.499 g unknown acid
24.07 mL NaOH

Trial 2:
0.501 g unknown acid
23.71 mL NaOH

Trial 3:
0.500 g unknown acid
24.15 mL NaOH

Using the data presented above, calculate the molar mass of the unknown acid. Include the calculation for each trial and the average.

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1. Is this a duplicate post? See my response below.

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posted by DrBob222
2. No, this is not a duplicate. The other question refers to molarity. This one is asking for molar mass of an unknown acid.

For this question would I do the following...

Start with the volume of NaOH then convert it to moles with the answer from the first question.

Use stoichiometry to find the number of moles of HX (unknown acid).

Then divide the mass of the acid by the number of moles of the acid to find the molar mass.

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posted by Jake
3. moles NaOH = M x L
You must have some knowledge about the unknown compound; I assume you were told that it took 1 or 2 or 3 moles NaOH to react with it (or the information could have been in another form such as monoprotic, diprotic, or triprotic acid).
Convert moles NaOH to moles unknown.
Then moles = g/molar mass.
You have moles and grams, calculate molar mass.

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posted by DrBob222

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