# Chemistry

Include an explanation, balanced chemical equation, units, significant figures and/or calculations where appropriate.

Standardization of NaOH Solution

Trial 1:
0.501 g KHC8H4O4
15.22 mL NaOH

Trial 2:
0.503 g KHC8H4O4
15.11 mL

Trial 3:
0.500 g KHC8H4O4
15.10 mL

Using the data presented above, calculate the concentration of your standard sodium hydroxide solution. Include the calculation for each trial and the average.

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3. 👁 150

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posted by DrBob222
2. I'm not sure how to start it.

I know I need to have a balanced chemical equation, so...

KHC8H4O4 (aq) + NaOH (aq) --> H2O (l) + ????

Then once I figure this out, do I use the mass in each trial to find the moles of NaOH through stoichiometry.

Then divide the number of moles by the volume of NaOH.

??

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posted by Jake
3. Simplify the KHC8H4O4 to KHT.
Then KHT + NaOH ==> NaKT + HOH

mols KHT = grams/molar mass
mols HHT = moles NaOH.
M NaOH = moles/L NaOH.
You will have a M for each trial, then average the values you obtain.

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posted by DrBob222
4. Theory background of standardizing NaOH with KHP

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posted by Thando
5. What’s the concentration of the NaOH solution was found to be exactly??

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posted by Pheello

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