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Marble (calcium carbonate) reacts with hydrochloric acid solution to form calcium
chloride solution, water and carbon dioxide. What is the percent yield of carbon dioxide
if 3.65 g of the gas is collected when 10.0 g marble reacts?

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  1. CaCO3 + 2 HCl → CaCl2 + CO2 + H2O

    10.0 g CaCO3 is .1 mole ... so .1 mole of CO2 should be produced

    molar mass CO2 ... 44.0 g

    % yield ... (3.65 / 4.40) * 100%

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