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Seven years back the age of a father was 5 times the age of his son. It will be twice after 14 years. Find their present age.

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  1. f-7 = 5(s-7)
    f+14 = 2(s+14)
    father = 42
    son = 14
    check:
    42-7 = 35 = 5(14-7) ✅
    42+14 = 56 = 2(14+14) ✅

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