Sammy girl wants to make some handicrafts to decorate her classroom. She as a rectangular piece of paper. The rectangles has a perimeter of 290 cm. The length of the rectangle is 97 cm. How much longer is the length that the width.

the width = 145-97 = 48

97-48 = 49

To find out how much longer the length is than the width, we need to determine the width of the rectangle first.

Let's define:
Length of the rectangle = 97 cm
Width of the rectangle = x cm

The formula for calculating the perimeter of a rectangle is:
Perimeter = 2 * (Length + Width)

In this case, the perimeter is given as 290 cm, so we can substitute these values into the formula:
290 = 2 * (97 + x)

Divide both sides of the equation by 2 to isolate the expression within the parentheses:
145 = 97 + x

Subtract 97 from both sides of the equation to solve for x:
x = 145 - 97
x = 48 cm

So the width of the rectangle is 48 cm.

To determine how much longer the length is than the width, subtract the width from the length:
97 cm - 48 cm = 49 cm

Therefore, the length is 49 cm longer than the width.

To find out how much longer the length is than the width, we need to determine the width of the rectangle first.

We know that the rectangle's perimeter is 290 cm. The perimeter of a rectangle can be calculated by using the formula:

Perimeter = 2 * (Length + Width)

Given that the length of the rectangle is 97 cm, we can rearrange the formula to solve for the width:

290 cm = 2 * (97 cm + Width)

First, let's simplify the equation by removing the parentheses:

290 cm = 2 * 97 cm + 2 * Width

Next, simplify the right side of the equation:

290 cm = 194 cm + 2 * Width

Now, isolate the variable by subtracting 194 cm from both sides of the equation:

290 cm - 194 cm = 2 * Width

96 cm = 2 * Width

Finally, divide both sides of the equation by 2 to solve for the width:

Width = 96 cm / 2 = 48 cm

Now that we know the width is 48 cm, we can calculate how much longer the length is:

Length - Width = 97 cm - 48 cm = 49 cm

Therefore, the length is 49 cm longer than the width.